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Difference Quotient Find \(f(a), f(a+h),\) and the difference quotient \(\frac{f(a+h)-f(a)}{h},\) where \(h \neq 0.\) $$f(x)=x^{3}$$

Short Answer

Expert verified
\(f(a) = a^3\), \(f(a+h) = a^3 + 3a^2h + 3ah^2 + h^3\), Difference quotient: \(3a^2 + 3ah + h^2\).

Step by step solution

01

Evaluate \(f(a)\)

To find \(f(a)\), substitute \(a\) into the function \(f(x) = x^3\). Therefore, we have \(f(a) = a^3\).
02

Evaluate \(f(a+h)\)

Next, we find \(f(a+h)\) by substituting \(a + h\) into the function. This gives us \(f(a+h) = (a+h)^3\).
03

Expand \((a+h)^3\)

To expand \((a+h)^3\), use the binomial theorem: \((a+h)^3 = a^3 + 3a^2h + 3ah^2 + h^3\).
04

Calculate the Difference Quotient

The difference quotient is given by \(\frac{f(a+h) - f(a)}{h}\). Substituting \(f(a+h) = a^3 + 3a^2h + 3ah^2 + h^3\) and \(f(a) = a^3\), we get \(\frac{(a^3 + 3a^2h + 3ah^2 + h^3) - a^3}{h}\).
05

Simplify the Difference Quotient

Simplify \(\frac{(a^3 + 3a^2h + 3ah^2 + h^3) - a^3}{h}\) by canceling the \(a^3\) terms, resulting in \(\frac{3a^2h + 3ah^2 + h^3}{h}\). Further simplification yields \(3a^2 + 3ah + h^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are fundamental elements in mathematics, primarily composed of variables raised to whole-number exponents and coefficients. These functions take the form \( f(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \), where \( a_i \) represents the coefficients and \( n \) is a non-negative integer. For example, the function \( f(x) = x^3 \) is a polynomial of degree 3, which means it involves a variable \( x \) raised to the power of 3.

Each polynomial function has various characteristics including its degree, leading coefficient, and end behavior, which determine its graph's shape and direction. Polynomials are smooth and continuous, making them easy to manipulate in calculus, where they are often used to approximate more complex functions.
Binomial Theorem
The binomial theorem is a powerful algebraic formula that provides an efficient method to expand expressions raised to a power, such as \((a + b)^n\). It is particularly useful in expanding terms that otherwise would be lengthy to calculate using straightforward multiplication. The formula is expressed as:
  • \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \)

Here, \( \binom{n}{k} \) represents the binomial coefficients, which are convenient in Pascal's Triangle and can be calculated as \( \frac{n!}{k!(n-k)!} \).

For the expression \((a+h)^3\), which appears in the difference quotient problem, the binomial theorem helps break it down into easier parts: \( a^3 + 3a^2h + 3ah^2 + h^3 \). This expansion is key to deriving simplified forms of polynomial expressions.
f(a) and f(a+h)
In mathematical analysis, evaluating a function at specific points \( f(a) \) and \( f(a+h) \) is essential to study the function's behavior. In this instance, given the polynomial \( f(x) = x^3 \):
  • \( f(a) = a^3 \)
  • \( f(a+h) = (a+h)^3 \)

These evaluations are often the first steps in determining a function's rate of change, which is critical in calculus studies. By substituting in different values, like \( a \) and \( a+h \), you can explore how the function changes over small increments, establishing groundwork for concepts such as derivatives.

The computed values \( f(a) \) and \( f(a+h) \) become components in forming the difference quotient, which approximates the derivative of \( f \).
Limits and Continuity
Limits and continuity are core concepts in calculus, dealing with the behavior of functions as they approach specific points. In the difference quotient, expressed as \( \frac{f(a+h) - f(a)}{h} \), understanding limits is crucial because it allows the approximation of rates of change and helps define derivatives when \( h \) approaches 0.
  • As \( h \to 0 \), the quotient provides information about the function's instantaneous rate of change at \( a \), leading towards the derivative \( f'(a) \).

Continuity, on the other hand, refers to the smoothness of a function and its unbroken nature over its domain. Polynomial functions like \( f(x) = x^3 \) are inherently continuous and smooth, enabling easy computation of limits and analysis through their derivatives.

This combination of limits with continuity furnishes the differentiation process and helps explore how functions behave infinitesimally close to a point.

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Most popular questions from this chapter

An airplane is flying at a speed of \(350 \mathrm{mi} / \mathrm{h}\) at an altitude of one mile. The plane passes directly above a radar station at time \(t=0\). (a) Express the distance \(s\) (in miles) between the plane and the radar station as a function of the horizontal distance \(d\) (in miles) that the plane has flown. (b) Express \(d\) as a function of the time \(t\) (in hours) that the plane has flown. (c) Use composition to express \(s\) as a function of \(t\).

DISCUSS: Sums of Even and Odd Functions If \(f\) and \(g\) are both even functions, is \(f+g\) necessarily even? If both are odd, is their sum necessarily odd? What can you say about the sum if one is odd and one is even? In each case, prove your answer.

DISCUSS: Finding an Inverse "in Your Head" In the margin notes in this section we pointed out that the inverse of a function can be found by simply reversing the operations that make up the function. For instance, in Example 7 we saw that the inverse of $$f(x)=3 x-2 \quad \text { is } \quad f^{-1}(x)=\frac{x+2}{3}$$ because the "reverse" of "Multiply by 3 and subtract 2" is "Add 2 and divide by 3 ". Use the same procedure to find the inverse of the following functions. (a) \(f(x)=\frac{2 x+1}{5}\) (b) \(f(x)=3-\frac{1}{x}\) (c) \(f(x)=\sqrt{x^{3}+2}\) (d) \(f(x)=(2 x-5)^{3}\) Now consider another function: $$f(x)=x^{3}+2 x+6$$ Is it possible to use the same sort of simple reversal of operations to find the inverse of this function? If so, do it. If not, explain what is different about this function that makes this task difficult.

When a bowl of hot soup is left in a room, the soup eventually cools down to room temperature. The temperature \(T\) of the soup is a function of time \(t .\) The table below gives the temperature (in "F) of a bowl of soup \(t\) minutes after it was set on the table. Find the average rate of change of the temperature of the soup over the first 20 minutes and over the next 20 minutes. During which interval did the soup cool off more quickly? $$\begin{array}{|c|c||c|c|} \hline t \text { (min) } & T\left(^{\circ} \mathrm{F}\right) & t \text { (min) } & T\left(^{\circ} \mathrm{F}\right) \\ \hline 0 & 200 & 35 & 94 \\ 5 & 172 & 40 & 89 \\ 10 & 150 & 50 & 81 \\ 15 & 133 & 60 & 77 \\ 20 & 119 & 90 & 72 \\ 25 & 108 & 120 & 70 \\ 30 & 100 & 150 & 70 \\ \hline \end{array}$$

In Example 7 and Exercises 82 and 83 we are given functions whose graphs consist of horizontal line segments. Such functions are often called step functions, because their graphs look like stairs. Give some other examples of step functions that arise in everyday life.

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