Chapter 2: Problem 18
A function is given. Determine (a) the net change and (b) the average rate of change between the given values of the variable. $$g(t)=t^{4}-t^{3}+t^{2} ; \quad t=-2, t=2$$
Short Answer
Expert verified
Net change: -16, Average rate of change: -4.
Step by step solution
01
Calculate the Value of g(t) at t = -2
Substitute \( t = -2 \) into the function: \[ g(-2) = (-2)^4 - (-2)^3 + (-2)^2 \]Calculate: \[ g(-2) = 16 + 8 + 4 = 28 \]
02
Calculate the Value of g(t) at t = 2
Substitute \( t = 2 \) into the function:\[ g(2) = (2)^4 - (2)^3 + (2)^2 \]Calculate:\[ g(2) = 16 - 8 + 4 = 12 \]
03
Determine the Net Change
Net change is the difference between \( g(2) \) and \( g(-2) \):\[ \text{Net change} = g(2) - g(-2) = 12 - 28 = -16 \]
04
Calculate the Average Rate of Change
The average rate of change is given by the formula:\[ \text{Average Rate of Change} = \frac{g(2) - g(-2)}{2 - (-2)} \]Substitute the values:\[ \frac{12 - 28}{2 + 2} = \frac{-16}{4} = -4 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Function
A **Polynomial Function** is a mathematical expression consisting of variables, coefficients, and exponents. The name "polynomial" comes from "poly," meaning many, and "nomial," meaning terms. Therefore, it is a combination of many terms. A typical polynomial function can be written as:\[a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0\]where:
- \(a_n, a_{n-1}, \ldots, a_0\) are constants known as coefficients.
- \(x\) is the variable.
- The highest power of \(x\) (n) is called the degree of the polynomial.
Evaluating Functions
**Evaluating Functions** refers to finding the value of a function for specific inputs of its variable(s). It involves substituting the given value into the function and simplifying. For example, if you have a function \( g(t) = t^4 - t^3 + t^2 \) and you want to find \( g(-2) \), substitute \( t = -2 \):
\[g(-2) = (-2)^4 - (-2)^3 + (-2)^2\]
Calculate each term:
\[g(-2) = (-2)^4 - (-2)^3 + (-2)^2\]
Calculate each term:
- \((-2)^4 = 16\)
- \((-2)^3 = -8\)
- \((-2)^2 = 4\)
Difference Quotient
The **Difference Quotient** is a formula that provides the average rate of change of the function over a specific interval. It's a fundamental concept in calculus, as it forms the basis for the derivative, which represents instantaneous rate of change.
For a function \( f(x) \), the difference quotient over the interval \([a, b]\) is:
\[\frac{f(b) - f(a)}{b - a}\]This formula calculates how much the function's output changes compared to how much the input changes. It's particularly useful in determining how steep or flat a function's graph is over an interval.
In the context of the given exercise, it helps find the average rate of change of \( g(t) \) from \( t = -2 \) to \( t = 2 \). That's why \[\frac{g(2) - g(-2)}{2 - (-2)}\] obtains the result of \(-4\).
For a function \( f(x) \), the difference quotient over the interval \([a, b]\) is:
\[\frac{f(b) - f(a)}{b - a}\]This formula calculates how much the function's output changes compared to how much the input changes. It's particularly useful in determining how steep or flat a function's graph is over an interval.
In the context of the given exercise, it helps find the average rate of change of \( g(t) \) from \( t = -2 \) to \( t = 2 \). That's why \[\frac{g(2) - g(-2)}{2 - (-2)}\] obtains the result of \(-4\).
Rate of Change
The **Rate of Change** is a fundamental concept in mathematics, describing how one quantity changes concerning another. In simpler terms, it's how fast or slow a variable changes over a given period.
In the exercise, the average rate of change between \( t = -2 \) and \( t = 2 \) was calculated:\[\frac{g(2) - g(-2)}{2 - (-2)} = -4\]This result indicates that, on average, the function's value decreases by 4 units as \( t \) increases by 1 unit from -2 to 2.
- For linear functions, the rate of change is constant, usually known as the slope.
- For non-linear functions like polynomials, the rate of change varies along the function's graph.
In the exercise, the average rate of change between \( t = -2 \) and \( t = 2 \) was calculated:\[\frac{g(2) - g(-2)}{2 - (-2)} = -4\]This result indicates that, on average, the function's value decreases by 4 units as \( t \) increases by 1 unit from -2 to 2.