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Complete the table. $$f(x)=2(x-1)^{2}$$ $$\begin{array}{|r|r|}\hline x & f(x) \\\\\hline-1 & \\\0 & \\\1 & \\\2 & \\\3 & \\\\\hline\end{array}$$

Short Answer

Expert verified
\(f(-1)=8\), \(f(0)=2\), \(f(1)=0\), \(f(2)=2\), \(f(3)=8\). Table is completed.

Step by step solution

01

Understand the Function

The given function is \( f(x) = 2(x-1)^2 \). This is a quadratic function where each value of \( f(x) \) depends on the square of \( (x-1) \) multiplied by 2.
02

Calculate \( f(-1) \)

Substitute \( x = -1 \) into the function: \[ f(-1) = 2((-1)-1)^2 = 2(-2)^2 = 2(4) = 8 \]. The value of \( f(-1) \) is 8.
03

Calculate \( f(0) \)

Substitute \( x = 0 \) into the function: \[ f(0) = 2(0-1)^2 = 2(-1)^2 = 2(1) = 2 \]. The value of \( f(0) \) is 2.
04

Calculate \( f(1) \)

Substitute \( x = 1 \) into the function: \[ f(1) = 2(1-1)^2 = 2(0)^2 = 2(0) = 0 \]. The value of \( f(1) \) is 0.
05

Calculate \( f(2) \)

Substitute \( x = 2 \) into the function: \[ f(2) = 2(2-1)^2 = 2(1)^2 = 2(1) = 2 \]. The value of \( f(2) \) is 2.
06

Calculate \( f(3) \)

Substitute \( x = 3 \) into the function: \[ f(3) = 2(3-1)^2 = 2(2)^2 = 2(4) = 8 \]. The value of \( f(3) \) is 8.
07

Complete the Table

Based on the calculated values: \[ \begin{array}{|r|r|}\hline x & f(x) \hline -1 & 8 \ 0 & 2 \ 1 & 0 \ 2 & 2 \ 3 & 8 \hline\end{array} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Tables
Function tables are tools used to organize the inputs and outputs of a function. They make it easier to see how different values of the independent variable (usually denoted as "x") affect the output or the function's result. In a function table, each row pairs a specific input with its corresponding output according to the defined function.

Here’s why function tables are valuable:
  • They provide a clear, visual representation of how the function behaves.
  • They help students easily check their work and ensure they are applying the function's operations correctly.
  • They are essential for exploring patterns in the data produced by the function.
In the context of our quadratic function example, we have a table with values of "x" and corresponding "f(x)" calculated by using the function formula. Filling this table involves evaluating "f(x)" for every given "x" value. For example, substituting "x = -1" yields "f(-1) = 8", which directly corresponds to the position (-1, 8) in the table. This step-by-step approach ensures accuracy in the results and strengthens understanding of how the function works.
Function Evaluation
Function evaluation is the process of determining the output of a function for particular input values. This means substituting a given value for each instance of the independent variable (commonly x) in the function's formula, and performing the arithmetic operations.

For quadratic functions, such as the one represented as \( f(x) = 2(x-1)^2 \), evaluation involves these steps:
  • Replacing "x" with the specific number you want to evaluate.
  • Completing the operations within the parenthesis, if any.
  • Squaring the result of the expression inside the parenthesis.
  • Multiplying by the coefficient outside the squared term.
Evaluating functions helps in understanding the relationship between variables and gives insights into how outputs change with different inputs. It also allows you to visualize function behavior, making graphing more intuitive. The output "f(x)" results give you the points that you could plot on a graph, effectively helping identify the shape and position of the function's parabola.
Precalculus
Precalculus is a mathematical level that prepares students for calculus, covering topics necessary to understand more advanced concepts. It involves learning about different types of functions, including linear, quadratic, polynomial, exponential, and logarithmic.

Quadratic functions, like the one in our exercise \( f(x) = 2(x-1)^2 \), are an integral part of precalculus studies. In these studies, students learn to:
  • Recognize and analyze the key features of the graph of a quadratic function, such as its vertex and axis of symmetry.
  • Understand how transformations (like translation, dilation) affect the graph's shape and position.
  • Develop skills to solve quadratic equations through various methods, including factoring and using the quadratic formula.
Precalculus strengthens algebraic manipulation skills and the ability to work with different function types, setting a solid foundation for tackling limits, derivatives, and integrals in calculus. By mastering these concepts, students build not only computational abilities but also critical thinking and problem-solving skills essential for higher-level math.

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Most popular questions from this chapter

The table gives the population in a small coastal community for the period 1997-2006. Figures shown are for January 1 in each year. (a) What was the average rate of change of population between 1998 and 2001 ? (b) What was the average rate of change of population between 2002 and 2004 ? (c) For what period of time was the population increasing? (d) For what period of time was the population decreasing? $$\begin{array}{|c|c|} \hline \text { Year } & \text { Population } \\ \hline 1997 & 624 \\ 1998 & 856 \\ 1999 & 1,336 \\ 2000 & 1,578 \\ 2001 & 1,591 \\ 2002 & 1,483 \\ 2003 & 994 \\ 2004 & 826 \\ 2005 & 801 \\ 2006 & 745 \\ \hline \end{array}$$

DISCUSS: Solving an Equation for an Unknown Function In Exercises \(69-72\) of Section 2.7 you were asked to solve equations in which the unknowns are functions. Now that we know about inverses and the identity function (see Exercise 104 ), we can use algebra to solve such equations. For instance, to solve \(f \circ g=h\) for the unknown function \(f,\) we perform the following steps: \(f^{\circ} g=h \quad\) Problem: Solve for \(f\) \(f^{\circ} g^{\circ} g^{-1}=h^{\circ} g^{-1} \quad\) Compose with \(g^{-1}\) on the right \(f \circ I=h \cdot g^{-1} \quad \text { Because } g^{\circ} g^{-1}=I\) \(f=h e g^{-1} \quad\) Because \(f \circ I=f\) So the solution is \(f=h \circ g^{-1} .\) Use this technique to solve the equation \(f \circ g=h\) for the indicated unknown function. (a) Solve for \(f,\) where \(g(x)=2 x+1\) and \(h(x)=4 x^{2}+4 x+7.\) (b) Solve for \(q,\) where \(f(x)=3 x+5\) and \(h(x)=3 x^{2}+3 x+2.\)

Sketch a graph of the piecewise defined function. $$f(x)=\left\\{\begin{array}{ll} 0 & \text { if } x<2 \\ 1 & \text { if } x \geq 2 \end{array}\right.$$

The 2014 domestic postage rate for firstclass letters weighing 3.5 oz or less is 49 cents for the first ounce (or less), plus 21 cents for each additional ounce (or part of an ounce). Express the postage \(P\) as a piecewise defined function of the weight \(x\) of a letter, with \(0

Graphing Functions Sketch a graph of the function by first making a table of values. $$g(x)=-(x+1)^{2}$$

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