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91Ó°ÊÓ

Find the limit, if it exists. If the limit does not exist, explain why. $$\lim _{x \rightarrow 0^{+}}\left(\frac{1}{x}-\frac{1}{|x|}\right)$$

Short Answer

Expert verified
The limit is 0.

Step by step solution

01

Understanding the Problem

We need to find the limit as \(x\) approaches 0 from the right (positive direction) of the expression \(\frac{1}{x} - \frac{1}{|x|}\). This requires examining how the expression behaves as \(x\) becomes very small positive values.
02

Simplify the Expression

When \(x\) is positive, \(|x| = x\). Therefore, the expression simplifies to \(\frac{1}{x} - \frac{1}{x} = 0\).
03

Calculate the Limit

Since the simplified expression as \(x\) approaches 0 from the right is 0, the limit is \(\lim_{x \to 0^+} 0 = 0\).
04

Conclusion

The limit exists because as \(x\) approaches 0 from the positive side, the expression consistently evaluates to 0. Therefore, the limit is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right-Hand Limit
Understanding limits is essential in calculus, and one important type is the right-hand limit. The right-hand limit of a function as \( x \) approaches a specific value is the value that the function approaches as \( x \) comes from the right side, or positive side, of that point. In our exercise, we are finding \( \lim_{x \to 0^+} \left( \frac{1}{x} - \frac{1}{|x|} \right) \). This means we are only interested in behavior of the function as \( x \) approaches 0 from positive values. Such limits are especially meaningful when functions behave differently as they approach from the right compared to from the left. A simple way to identify a right-hand limit question is by the notation \( x \to c^+ \), where "\( c \)" is the specific point of interest.
  • The right-hand limit considers only values from the positive side.
  • It is important when the left-hand and right-hand limits might differ.
  • Notationally represented as \( x \to c^+ \).
Absolute Value Function
The absolute value function is another critical concept in this exercise. The absolute value of a number \( x \) is its non-negative value on the number line, denoted as \( |x| \). It changes negative inputs into positive outputs while leaving positive inputs unchanged. This function influences the behavior of expressions, especially near points where \( x \) could approach zero or switch signs. For instance, when \( x \) is positive, \( |x| = x \). This fact allows us to simplify certain expressions easily. In our problem, this property of the absolute value function simplifies \( \frac{1}{|x|} \) into \( \frac{1}{x} \) as we examine limits from \( x \to 0^+ \).
  • Expressed as \( |x| \).
  • Transforms negative numbers into positive ones.
  • Integral for simplifying certain limits as seen in the exercise.
Simplifying Expressions
Simplifying expressions is a crucial step in solving calculus problems involving limits. It involves rewriting expressions to make them simpler or more exact, especially when evaluating a limit. In this exercise, recognizing that when \( x > 0 \), \( |x| = x \), enables us to simplify the expression \( \frac{1}{x} - \frac{1}{|x|} \) into \( \frac{1}{x} - \frac{1}{x} = 0 \). This simplification makes it easier to see that the limit as \( x \to 0^+ \) is 0. Simplifying expressions helps in removing indeterminate forms and avoiding unnecessary complications.
  • Keeps calculations manageable and straightforward.
  • Transforms complex expressions into simpler forms.
  • Helps prevent mistakes in solving limits.

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