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(a) Graph the conics $$r=\frac{e d}{(1+e \sin \theta)}$$ for \(e=1\) and various values of \(d .\) How does the value of \(d\) affect the shape of the conic? (b) Graph these conics for \(d=1\) and various values of \(e\) How does the value of \(e\) affect the shape of the conic?

Short Answer

Expert verified
Changing \( d \) modifies the parabola size, and changing \( e \) changes the conic type and shape.

Step by step solution

01

Understanding the Conic Section Equation

The given polar equation is \( r = \frac{e d}{1 + e \sin \theta} \), which represents a conic section in polar coordinates. The parameter \( e \) is the eccentricity, determining the type of conic, and \( d \) is the directrix, influencing its scale.
02

Graphing for Fixed Eccentricity (e = 1)

For \( e = 1 \), the conic is a parabola. Vary \( d \) (e.g., \( d = 0.5, 1, 2 \)) and graph each conic. A smaller \( d \) results in a smaller-scale parabola, while a larger \( d \) results in a larger, more stretched parabola.
03

Effect of Parameter 'd'

The parameter \( d \) acts as a scaling factor. As \( d \) increases, the parabola widens, and as \( d \) decreases, it narrows. Thus, \( d \) affects the size of the conic section but not its type when \( e = 1 \).
04

Graphing for Fixed Directrix (d = 1)

Fix \( d = 1 \) and vary \( e \). For \( e = 0.5, 1, 1.5 \), graph the conics. This will show different types of conics: \( e < 1 \) (an ellipse), \( e = 1 \) (a parabola), and \( e > 1 \) (a hyperbola).
05

Effect of Eccentricity 'e'

The eccentricity \( e \) determines the type of conic: an ellipse if \( e < 1 \), a parabola if \( e = 1 \), and a hyperbola if \( e > 1 \). As \( e \) varies from less than 1 to greater than 1, the conic transitions through these types.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eccentricity
Eccentricity, denoted by the symbol \( e \), is a key parameter in defining the shape of a conic section. It tells us how much the conic deviates from being circular. Depending on its value, the conic section can take different forms:
  • **Ellipse**: If \( e < 1 \), the conic is an ellipse, which means the shape looks like an elongated circle. The smaller the \( e \), the more rounded the ellipse appears.

  • **Parabola**: If \( e = 1 \), the conic becomes a parabola. Parabolas are mirror-symmetrical and open shapes.

  • **Hyperbola**: If \( e > 1 \), the conic is identified as a hyperbola. Hyperbolas look like two opposite-facing curves.
In essence, eccentricity serves as a measure of how "stretched" a conic section is. The transition from ellipse to parabola to hyperbola is smooth as \( e \) increases. By merely adjusting this parameter, we can completely change the nature of the conic in question. Understanding eccentricity helps in predicting the conic's geometric layout.
Polar Coordinates
Polar coordinates are a way to define the position of a point in a two-dimensional plane. Unlike the Cartesian coordinate system, which uses \( x \) and \( y \) coordinates, polar coordinates use the distance from a reference point and an angle from a reference direction to specify locations.
  • The reference point, often labeled as the origin or pole, serves as the starting point for measure.

  • The angular coordinate, \( \theta \), is the angle measured from a fixed direction, commonly the positive x-axis.

  • The radial coordinate, \( r \), is the direct distance from the pole to the point.
Conic sections can be represented in polar form, as seen in the equation \( r = \frac{e d}{1 + e \sin \theta} \). Here, \( r \) relates directly to the distance from the origin to a point on the conic curve. This method simplifies graphing some curves, especially when symmetry around a reference axis is involved. Understanding polar coordinates allows for a more natural description and deduction of properties related to circular and conic pathways.
Directrix
The directrix is another fundamental component in understanding conic sections. It is a straight line that helps in defining the conic along with a focus and eccentricity. Essentially, the directrix serves as a reference line that, together with the focus, helps describe the set of points that form the conic section.
  • For ellipses and parabolas, there is usually one directrix, while hyperbolas have two.

  • The role of the directrix in equations is crucial, as seen in \( r = \frac{e d}{1 + e \sin \theta} \). The parameter \( d \) corresponds to the distance from a directrix.

  • When dealing with parabolas, the distance from any point on the parabola to the focus equals the perpendicular distance from the point to the directrix.
The concept of a directrix helps in visualizing and plotting the conic section in relation to the focus and other geometrical properties. By adjusting \( d \), as noted in the exercise, we can alter the scale of the conic while preserving its type when \( e = 1 \). Therefore, understanding the directrix offers a clearer insight into the geometrically constructed definitions of conics.

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Most popular questions from this chapter

Finding the Equation of an Ellipse Find an equation for the ellipse that satisfies the given conditions. Endpoints of minor axis: \((0, \pm 3),\) distance between foci: 8

(a) For the hyperbola $$\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$$ determine the values of \(a, b,\) and \(c,\) and find the coordinates of the foci \(F_{1}\) and \(F_{2}\). (b) Show that the point \(P\left(5, \frac{16}{3}\right)\) lies on this hyperbola. (c) Find \(d\left(P, F_{1}\right)\) and \(d\left(P, F_{2}\right)\). (d) Verify that the difference between \(d\left(P, F_{1}\right)\) and \(d\left(P, F_{2}\right)\) is \(2 a\).

The polar equation of an ellipse can be expressed in terms of its eccentricity \(e\) and the length \(a\) of its major axis. (a) Show that the polar equation of an ellipse with directrix \(x=-d\) can be written in the form $$r=\frac{a\left(1-e^{2}\right)}{1-e \cos \theta}$$ [Hint: Use the relation \(a^{2}=e^{2} d^{2} /\left(1-e^{2}\right)^{2}\) given in the proof on page 825 .] (b) Find an approximate polar equation for the elliptical orbit of the earth around the sun (at one focus) given that the eccentricity is about 0.017 and the length of the major axis is about \(2.99 \times 10^{8} \mathrm{km}\).

The graph of the equation \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) with \(a>b>0\) is an ellipse with vertices (________ , ________ )and (_______ ,________ ) and foci \((\pm c, 0),\) where \(c=\) ________ . So the graph of \(\frac{x^{2}}{5^{2}}+\frac{y^{2}}{4^{2}}=1\) is an ellipse with vertices (_______ , _______ ) and (_______,_______) and foci (_______ , _______ ) and (_______,_______).

Finding the Equation of an Ellipse Find an equation for the ellipse that satisfies the given conditions. Eccentricity: \(0.75,\) foci: \((\pm 1.5,0)\)

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