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(a) Use the discriminant to determine whether the graph of the equation is a parabola, an ellipse, or a hyperbola. (b) Use a rotation of axes to eliminate the xy-term. (c) Sketch the graph. $$21 x^{2}+10 \sqrt{3} x y+31 y^{2}=144$$

Short Answer

Expert verified
(a) The equation represents an ellipse. (b) Rotate axes by 30° to eliminate xy-term. (c) The graph is an ellipse centered at the origin.

Step by step solution

01

Identifying the type of conic section using the discriminant

The general form of a conic section is given by the equation \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\). Here, we have \(A = 21\), \(B = 10\sqrt{3}\), \(C = 31\), \(D = 0\), \(E = 0\), \(F = -144\). The discriminant \( \Delta \) is calculated as \( B^2 - 4AC \). Substituting the given values, we get \( \Delta = (10\sqrt{3})^2 - 4(21)(31) = 300 - 2604 = -2304 \). Since \( \Delta < 0 \), the equation represents an ellipse.
02

Rotation of axes to eliminate the xy-term

To eliminate the \(xy\)-term, we use the rotation formulas: \( x = x' \cos \theta - y' \sin \theta \) and \( y = x' \sin \theta + y' \cos \theta \), where \( \tan(2\theta) = \frac{B}{A-C} = \frac{10\sqrt{3}}{21 - 31} = -\sqrt{3} \). Solving, \( 2\theta = 120^\circ \) or \( \theta = 60^\circ \). Using \( \theta = 30^\circ \) (since we need \( \theta = 60^\circ / 2 \)), we have \( \cos \theta = \frac{\sqrt{3}}{2} \) and \( \sin \theta = \frac{1}{2} \). Substitute these values into the rotation formulas to convert the equation into a new system where the \(xy\)-term will vanish.
03

Simplifying the rotated equation

After substituting the rotation formulas into the conic equation, we get a new equation with no \(xy\)-term. Simplification involves substituting \( x = x' \cos(30^\circ) - y' \sin(30^\circ) \) and \( y = x' \sin(30^\circ) + y' \cos(30^\circ) \) into the equation and comparing coefficients. The simplified form will look like \( A'x'^2 + C'y'^2 = 144 \), representing the standard form of an ellipse.
04

Sketching the graph

The equation now represents an ellipse, whose axes have been aligned to the coordinate axes due to the rotation. Using the coefficients from the simplified equation (which are determined in the previous step), identify the lengths of the semi-major and semi-minor axes. The center of the ellipse remains at the origin (0, 0) due to the lack of linear terms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discriminant
In the world of conic sections, the discriminant is a powerful tool that helps determine the type of conic represented by a given equation. For any conic section in the form \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), the discriminant is defined as \[\Delta = B^2 - 4AC\].

The value of \(\Delta\) plays a crucial role in identifying the conic section:
  • If \(\Delta > 0\), the graph is a hyperbola.
  • If \(\Delta = 0\), the graph is a parabola.
  • If \(\Delta < 0\), the graph is an ellipse.
Given the equation in our exercise, by substituting \(A = 21\), \(B = 10\sqrt{3}\), and \(C = 31\) into the discriminant formula, we calculate \(\Delta = (10\sqrt{3})^2 - 4(21)(31) = -2304\).

Since \(\Delta < 0\), the conic section is an ellipse. Understanding these basic properties of the discriminant allows students to efficiently categorize different conic sections.
Rotation of Axes
The rotation of axes is a mathematical technique used to simplify conic equations by eliminating the \(xy\)-term. This is especially useful in transforming the equation of a conic section to align its axes with the coordinate axes.

The rotation involves changing the coordinate system using the formulas:
\[x = x' \cos \theta - y' \sin \theta\]
\[y = x' \sin \theta + y' \cos \theta\]
where \(\theta\) is the angle of rotation.

To find \(\theta\), use the equation \(\tan(2\theta) = \frac{B}{A-C}\). In our example, this calculates as \(\tan(2\theta) = -\sqrt{3}\), leading to \(2\theta = 120^\circ\) or \(\theta = 60^\circ\). However, to apply the rotation correctly, use \(\theta = 30^\circ\), which is half of \(60^\circ\).

Using \(\cos(30^\circ) = \frac{\sqrt{3}}{2}\) and \(\sin(30^\circ) = \frac{1}{2}\), substitute these into the rotation formulas to derive a new axis-aligned equation. This process simplifies the original equation and directly leads to understanding the graph's orientation.
Ellipse
An ellipse represents a type of conic section characterized by the equation \(A'x'^2 + C'y'^2 = 144\) after rotation, as shown in the exercise. It's like a stretched circle and has unique properties regarding its geometric shape.

Ellipses have:
  • Two axes: a major axis (the longest) and a minor axis (the shortest).
  • A center point, which remains at the origin after rotation in our case.
  • Focal points along the major axis, inside the boundary of the ellipse.
Once you have the simplified form of the equation, it becomes straightforward to identify the lengths of these axes. The major axis corresponds to the larger coefficient in the standard form.

In this example, the absence of linear terms indicates that the center is precisely at the axes' intersection. Drawing the ellipse involves plotting these axes and ensuring the graph reflects the calculated proportions. Visualizing an ellipse can be easier once it is reduced to its standard form through the rotation process.

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Most popular questions from this chapter

Find the intersection points of the pair of ellipses. Sketch the graphs of each pair of equations on the same coordinate axes, and label the points of intersection. $$\left\\{\begin{aligned}100 x^{2}+25 y^{2} &=100 \\\x^{2}+\frac{y^{2}}{9} &=1\end{aligned}\right.$$

Finding the Equation of an Ellipse Find an equation for the ellipse that satisfies the given conditions. Eccentricity: \(\sqrt{3} / 2,\) foci on \(y\) -axis, length of major axis: 4

The polar equation of an ellipse can be expressed in terms of its eccentricity \(e\) and the length \(a\) of its major axis. (a) Show that the polar equation of an ellipse with directrix \(x=-d\) can be written in the form $$r=\frac{a\left(1-e^{2}\right)}{1-e \cos \theta}$$ [Hint: Use the relation \(a^{2}=e^{2} d^{2} /\left(1-e^{2}\right)^{2}\) given in the proof on page 825 .] (b) Find an approximate polar equation for the elliptical orbit of the earth around the sun (at one focus) given that the eccentricity is about 0.017 and the length of the major axis is about \(2.99 \times 10^{8} \mathrm{km}\).

A polar equation of a conic is given. (a) Find the eccentricity and the directrix of the conic. (b) If this conic is rotated about the origin through the given angle \(\theta\), write the resulting equation. (c) Draw graphs of the original conic and the rotated conic on the same screen. $$r=\frac{1}{4-3 \cos \theta} ; \quad \theta=\frac{\pi}{3}$$

(a) Use a graphing device to sketch the top half (the portion in the first and second quadrants) of the family of ellipses \(x^{2}+k y^{2}=100\) for \(k=4,10,25,\) and 50 (b) What do the members of this family of ellipses have in common? How do they differ?

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