Chapter 10: Problem 63
Let $$ A=\left[\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}\right] $$ Calculate \(A^{2}, A^{3}, A^{4}, \ldots\) until you detect a pattern. Write a general formula for \(A^{n}\)
Short Answer
Expert verified
The general formula for \( A^n \) is \( A^n = 2^{n-1} \begin{bmatrix} 1 & 1 \\ 1 & 1 \end{bmatrix} \).
Step by step solution
01
Understand the Matrix and Operation
We are given the matrix \( A \) as \( \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \). The task is to calculate powers of this matrix: \( A^2, A^3, \) and so on, until we identify a pattern. This involves the multiplication of matrices.
02
Calculate Square of Matrix A
To find \( A^2 \), multiply matrix \( A \) by itself. \\(A^2 = \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \times \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} = \begin{bmatrix} (1 \cdot 1 + 1 \cdot 1) & (1 \cdot 1 + 1 \cdot 1) \ (1 \cdot 1 + 1 \cdot 1) & (1 \cdot 1 + 1 \cdot 1) \end{bmatrix} = \begin{bmatrix} 2 & 2 \ 2 & 2 \end{bmatrix}.\)
03
Calculate Cube of Matrix A
To find \( A^3 \), use the result of \( A^2 \) and multiply by \( A \) again. \\(A^3 = \begin{bmatrix} 2 & 2 \ 2 & 2 \end{bmatrix} \times \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} = \begin{bmatrix} (2 \cdot 1 + 2 \cdot 1) & (2 \cdot 1 + 2 \cdot 1) \ (2 \cdot 1 + 2 \cdot 1) & (2 \cdot 1 + 2 \cdot 1) \end{bmatrix} = \begin{bmatrix} 4 & 4 \ 4 & 4 \end{bmatrix}.\)
04
Calculate Fourth Power of Matrix A
To find \( A^4 \), multiply the result of \( A^3 \) by \( A \) once more. \\(A^4 = \begin{bmatrix} 4 & 4 \ 4 & 4 \end{bmatrix} \times \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} = \begin{bmatrix} (4 \cdot 1 + 4 \cdot 1) & (4 \cdot 1 + 4 \cdot 1) \ (4 \cdot 1 + 4 \cdot 1) & (4 \cdot 1 + 4 \cdot 1) \end{bmatrix} = \begin{bmatrix} 8 & 8 \ 8 & 8 \end{bmatrix}.\)
05
Identify the Pattern
The entries of the resulting matrices double each time we multiply by \( A \). Hence, for any power \( n \), the resulting matrix \( A^n \) is \( 2^{n-1} \) times the initial matrix. Thus, \( A^n = 2^{n-1} \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra. Unlike regular multiplication, matrix multiplication involves combining rows with columns. When multiplying two matrices, say matrix \( A \) with matrix \( B \), the element in the \( i^{th} \) row and \( j^{th} \) column of the result is found by taking the dot product of the \( i^{th} \) row of \( A \) and the \( j^{th} \) column of \( B \).
For example, consider the multiplication of our matrix \( A = \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \). To compute \( A^2 = A \times A \), we calculate:
For example, consider the multiplication of our matrix \( A = \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \). To compute \( A^2 = A \times A \), we calculate:
- First row, first column: \((1\times1) + (1\times1) = 2\)
- First row, second column: \((1\times1) + (1\times1) = 2\)
- Second row, first column: \((1\times1) + (1\times1) = 2\)
- Second row, second column: \((1\times1) + (1\times1) = 2\)
Pattern Recognition in Matrices
Recognizing patterns in matrices is a vital skill in algebra and helps predict outcomes without full calculations. Upon examining the resulting matrices \( A^2, A^3, A^4, \ldots \), we notice that the values in the matrix are consistent:
- \( A^2 = \begin{bmatrix} 2 & 2 \ 2 & 2 \end{bmatrix}\)
- \( A^3 = \begin{bmatrix} 4 & 4 \ 4 & 4 \end{bmatrix}\)
- \( A^4 = \begin{bmatrix} 8 & 8 \ 8 & 8 \end{bmatrix}\)
General Formula for Matrix Powers
With the identified pattern, deriving a general formula for matrix powers becomes straightforward.
The initial matrix \( A \) is defined as \( \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \). From our pattern recognition, the matrix's entries double with each successive multiplication by \( A \). The formula can now be theorized as:\[A^n = 2^{n-1} \times \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix}\]This formula is derived from the observation that from \( A^2 \) to \( A^n \), every power introduces an additional factor of 2. The exponent \( n-1 \) signifies this process. Hence, for any positive integer \( n \), the matrix raised to the power \( n \) results in a matrix where each term is \( 2^{n-1} \) times the corresponding term in the original matrix. This concise formula enables easy computation of higher powers of the matrix without manual multiplication each time.
The initial matrix \( A \) is defined as \( \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix} \). From our pattern recognition, the matrix's entries double with each successive multiplication by \( A \). The formula can now be theorized as:\[A^n = 2^{n-1} \times \begin{bmatrix} 1 & 1 \ 1 & 1 \end{bmatrix}\]This formula is derived from the observation that from \( A^2 \) to \( A^n \), every power introduces an additional factor of 2. The exponent \( n-1 \) signifies this process. Hence, for any positive integer \( n \), the matrix raised to the power \( n \) results in a matrix where each term is \( 2^{n-1} \) times the corresponding term in the original matrix. This concise formula enables easy computation of higher powers of the matrix without manual multiplication each time.