Chapter 10: Problem 55
Find the inverse of the matrix. $$\begin{aligned}&\left[\begin{array}{rr}a & -a \\\a & a\end{array}\right]\\\&(a \neq 0)\end{aligned}$$
Short Answer
Expert verified
The inverse of the matrix is \( \begin{bmatrix} \frac{1}{2a} & \frac{1}{2a} \\ \frac{-1}{2a} & \frac{1}{2a} \end{bmatrix} \), given \( a \neq 0 \).
Step by step solution
01
Identify the Matrix
We have a square matrix \( A \) given as \[A = \begin{bmatrix}a & -a \a & a\end{bmatrix}.\] Our goal is to find its inverse, denoted as \( A^{-1} \).
02
Check Invertibility
To check whether a matrix is invertible, we calculate its determinant. The determinant of \( A \) is calculated as follows: \[ \text{det}(A) = a \cdot a - (-a) \cdot a = a^2 + a^2 = 2a^2.\] Since \( a eq 0 \) and \( 2a^2 eq 0 \), the matrix is invertible.
03
Apply the Formula for 2x2 Inverse
The formula for the inverse of a 2x2 matrix \( \begin{bmatrix} p & q \ r & s \end{bmatrix} \) is:\[ \frac{1}{ ext{det}(A)} \begin{bmatrix} s & -q \ -r & p \end{bmatrix}.\] Substitute \( p = a, q = -a, r = a, s = a \) into the formula:\[ A^{-1} = \frac{1}{2a^2} \begin{bmatrix} a & a \ -a & a \end{bmatrix}.\]
04
Simplify the Inverse Matrix
To simplify, distribute \( \frac{1}{2a^2} \) into the matrix:\[A^{-1} = \begin{bmatrix} \frac{a}{2a^2} & \frac{a}{2a^2} \ \frac{-a}{2a^2} & \frac{a}{2a^2} \end{bmatrix}.\] Simplify each term:\[ A^{-1} = \begin{bmatrix} \frac{1}{2a} & \frac{1}{2a} \ \frac{-1}{2a} & \frac{1}{2a} \end{bmatrix}.\]
05
Provide the Final Answer
The inverse of the given matrix \( A \) is:\[ A^{-1} = \begin{bmatrix} \frac{1}{2a} & \frac{1}{2a} \ \frac{-1}{2a} & \frac{1}{2a} \end{bmatrix}.\] The result assumes \( a eq 0 \) to ensure the matrix is invertible.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant
The determinant of a matrix is a special number that can be calculated from its elements. For a 2x2 matrix, particularly in linear algebra, the determinant plays a crucial role in understanding properties of the matrix such as invertibility.
To determine if a 2x2 matrix has an inverse, you first need to calculate its determinant. In our case, for the matrix \[A = \begin{bmatrix} a & -a \ a & a \end{bmatrix}\],
the determinant is given by \[det(A) = a \cdot a - (-a) \cdot a = 2a^2\].
To determine if a 2x2 matrix has an inverse, you first need to calculate its determinant. In our case, for the matrix \[A = \begin{bmatrix} a & -a \ a & a \end{bmatrix}\],
the determinant is given by \[det(A) = a \cdot a - (-a) \cdot a = 2a^2\].
- Calculate the product of the diagonal elements: \(a \cdot a\).
- Subtract the product of the off-diagonal elements: \((-a) \cdot a\).
- Sum these values to get the determinant.
Invertibility
Invertibility is a condition where a matrix can be reversed, or "inverted," to yield the identity matrix, which acts as a neutral element in matrix multiplication. The identity matrix for a 2x2 matrix looks like \[\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]. If a matrix is invertible, its determinant must not be zero.
The matrix \[A = \begin{bmatrix} a & -a \ a & a \end{bmatrix}\]is invertible because its determinant, \(2a^2\), is non-zero.
The matrix \[A = \begin{bmatrix} a & -a \ a & a \end{bmatrix}\]is invertible because its determinant, \(2a^2\), is non-zero.
- The determinant being zero would imply that the matrix cannot be inverted, as there would not be a unique way to reverse the effects of matrix multiplication.
- If the determinant is non-zero, a unique inverse matrix exists.
2x2 Matrix
A 2x2 matrix is a simple form of matrices in linear algebra characterized by two rows and two columns. This structure is common in entry-level matrix problems. When discussing invertibility and matrix inversion, understanding 2x2 matrices is particularly useful.
The general form of a 2x2 matrix \(\begin{bmatrix} p & q \ r & s \end{bmatrix}\)allows us to apply specific formulas to find the inverse. The inverse of a 2x2 matrix is \[\frac{1}{\text{det}} \begin{bmatrix} s & -q \ -r & p \end{bmatrix}\].
Here, each element is transformed using the calculated determinant.
The general form of a 2x2 matrix \(\begin{bmatrix} p & q \ r & s \end{bmatrix}\)allows us to apply specific formulas to find the inverse. The inverse of a 2x2 matrix is \[\frac{1}{\text{det}} \begin{bmatrix} s & -q \ -r & p \end{bmatrix}\].
Here, each element is transformed using the calculated determinant.
- Interchange the elements on the main diagonal.
- Change the signs of the off-diagonal elements.
- Divide each term by the determinant.
Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, vector spaces, and the linear transformations between them, including matrices.
In linear algebra, matrices are used to perform a range of operations and are indispensable tools in solving systems of linear equations, among other applications.
In linear algebra, matrices are used to perform a range of operations and are indispensable tools in solving systems of linear equations, among other applications.
- Matrices help represent linear transformations, which can be thought of as changing the perspective of data in a structured manner.
- The concept of the inverse matrix is vital for understanding how to "undo" these transformations.
- Matrix inversion, especially for a 2x2 matrix, is a fundamental skill in this field.