Chapter 10: Problem 50
Solving a Linear System Solve the system of equations by converting to a matrix equation. Use a graphing calculator to perform the necessary matrix operations, as in Example 7. $$\left\\{\begin{array}{lr}x+\frac{1}{2} y-\frac{1}{3} z= & 4 \\\x-\frac{1}{4} y+\frac{1}{6} z= & 7 \\\x+y-z= & -6\end{array}\right.$$
Short Answer
Step by step solution
Write the system in matrix form
Use inverse matrix method
Calculate matrix inverse
Multiply inverse matrix with constant matrix
Interpret the solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Equations
- First, identify the coefficients in each equation.
- Form matrix \( A \) using these coefficients and vector \( \mathbf{b} \) with the constants.
- The solution will then hinge on operations we perform on these matrices.
Inverse Matrix Method
- First, calculate \( A^{-1} \), the inverse of the coefficient matrix.
- Then, multiply this inverse by the vector \( \mathbf{b} \) on the right side, resulting in \( \mathbf{x} = A^{-1}\mathbf{b} \).
- This computation yields the vector \( \mathbf{x} \), providing the solutions \( x, y, \) and \( z \).
Graphing Calculator
- Input the matrix \( A \) into the calculator.
- Select the matrix function to calculate \( A^{-1} \), the inverse.
- Once you have the inverse, multiply it by vector \( \mathbf{b} \).
- The graphing calculator will display the solution, the vector \( \mathbf{x} \), showing values for \( x, y, \) and \( z \).
Matrix Operations
- **Addition/Subtraction:** Used less frequently, but can help adjust matrices when combining different systems or correcting errors.
- **Multiplication:** Essential for applying operations involving vectors and matrices, such as when multiplying matrix \( A^{-1} \) by vector \( \mathbf{b} \).
- **Inverse:** Finding an inverse is central to solving equations like \( A\mathbf{x} = \mathbf{b} \). It transforms the problem to directly solving for \( \mathbf{x} \).