/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 Rationalize the numerator. $$\... [FREE SOLUTION] | 91Ó°ÊÓ

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Rationalize the numerator. $$\frac{\sqrt{x}-\sqrt{x+h}}{h \sqrt{x} \sqrt{x+h}}$$

Short Answer

Expert verified
The rationalized expression is \( \frac{-1}{(\sqrt{x} + \sqrt{x+h}) \sqrt{x} \sqrt{x+h}} \).

Step by step solution

01

Identify the Terms

The expression to rationalize the numerator is \( \frac{\sqrt{x}-\sqrt{x+h}}{h \sqrt{x} \sqrt{x+h}} \). The numerator consists of \( \sqrt{x} - \sqrt{x+h} \). Rationalization involves eliminating the square roots from the numerator.
02

Multiply by the Conjugate

To eliminate the square roots, multiply both the numerator and the denominator by the conjugate of the numerator, \( \sqrt{x} + \sqrt{x+h} \). This involves performing the operation \( \frac{\sqrt{x}-\sqrt{x+h}}{h \sqrt{x} \sqrt{x+h}} \times \frac{\sqrt{x}+\sqrt{x+h}}{\sqrt{x}+\sqrt{x+h}} \).
03

Apply the Difference of Squares Formula

The product of the numerator and its conjugate, \( (\sqrt{x} - \sqrt{x+h})(\sqrt{x} + \sqrt{x+h}) \), is a difference of squares: \( x - (x+h) = x - x - h = -h \). This simplifies the numerator to \( -h \).
04

Simplify the Denominator

The denominator becomes \( h \sqrt{x} \sqrt{x+h} (\sqrt{x} + \sqrt{x+h}) \), which remains unsimplified until the 'h' in the numerator cancels out. After simplification, it becomes \(- (\sqrt{x} + \sqrt{x+h}) \sqrt{x} \sqrt{x+h}\).
05

Cancel the Common Factors

Cancel the \(-h\) in the numerator with the \(h\) in the denominator. This simplifies the expression to \( \frac{-1}{(\sqrt{x} + \sqrt{x+h}) \sqrt{x} \sqrt{x+h}} \). The numerator is now rationalized.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
Imagine you have two squares lying next to each other, each with different areas. The difference of squares is a mathematical concept used when you subtract the area of one square from another. In our context, it simplifies calculations involving terms like \((a-b)(a+b)\), which equals \(a^2-b^2\). This formula comes in handy as it transforms complex expressions into simpler ones without square roots.

For the given expression, the difference of squares formula is applied to \((\sqrt{x} - \sqrt{x+h})(\sqrt{x} + \sqrt{x+h})\). Here, \(a\) is \(\sqrt{x}\) and \(b\) is \(\sqrt{x+h}\). By using the formula, it translates to \(x - (x+h)\), which eventually gives \(-h\). The key takeaway here is that this formula offers a neat and powerful shortcut for simplifying expressions that combine subtraction with roots.
Conjugate
The term conjugate refers to a pair of binomials like \((a-b)\) and \((a+b)\). When multiplied, these binomials use the difference of squares to eliminate radicals or complex numbers. This is extremely helpful for simplifying expressions, especially in rationalizing numerators or denominators that contain square roots or imaginary numbers.

In our expression, the conjugate of the numerator \((\sqrt{x} - \sqrt{x+h})\) is \((\sqrt{x} + \sqrt{x+h})\). By multiplying the numerator and the denominator by this conjugate, we effectively eliminate the roots in the numerator. This action transforms complicated radicals into a single number without radicals. Such transformations are pivotal in simplification, as they allow further steps like canceling common factors.
Simplifying Expressions
Simplifying expressions is like solving a puzzle. It involves reducing the expression to its simplest form using mathematical operations and properties. One powerful tool in this process is canceling common factors that appear in both the numerator and the denominator. This transforms a complex statement into a more manageable form.

In our example, once we applied the conjugate and difference of squares, we simplified the numerator to \(-h\). The denominator, however, became more complex. At this point, we can cancel the \(-h\) in the numerator with the \(h\) in the denominator. This step is crucial as it further simplifies the overall expression to \( \frac{-1}{(\sqrt{x} + \sqrt{x+h}) \sqrt{x} \sqrt{x+h}} \).
  • This demonstrates how strategically maneuvering through expressions simplifies mathematical computation effectively.
  • Always look for common factors to cancel.
  • Through rationalization and simplification, the solution becomes clearer and easier to handle.

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Most popular questions from this chapter

The Lens Equation If \(F\) is the focal length of a convex lens and an object is placed at a distance \(x\) from the lens, then its image will be at a distance \(y\) from the lens, where \(F, x,\) and \(y\) are related by the lens equation $$\frac{1}{F}=\frac{1}{x}+\frac{1}{y}$$ Suppose that a lens has a focal length of \(4.8 \mathrm{cm}\) and that the image of an object is \(4 \mathrm{cm}\) closer to the lens than the object itself. How far from the lens is the object?

Suppose an object is dropped from a height \(h_{0}\) above the ground. Then its height after \(t\) seconds is given by \(h=-16 t^{2}+h_{0},\) where \(h\) is measured in feet. Use this information to solve the problem. If a ball is dropped from 288 ft above the ground, how long does it take to reach ground level?

Gravity If an imaginary line segment is drawn between the centers of the earth and the moon, then the net gravitational force \(F\) acting on an object situated on this line segment is $$F=\frac{-K}{x^{2}}+\frac{0.012 K}{(239-x)^{2}}$$ where \(K>0\) is a constant and \(x\) is the distance of the object from the center of the earth, measured in thousands of miles. How far from the center of the earth is the "dead spot" where no net gravitational force acts upon the object? (Express your answer to the nearest thousand miles.) PICTURE CANT COPY

Radicals Simplify the expression, and eliminate any negative exponents(s). Assume that all letters denote positive numbers. (a) \(\sqrt[4]{b^{3}} \sqrt{b}\) (b) \((2 \sqrt{a})(\sqrt[3]{a^{2}})\)

DISCUSS: Proof That \(0=1 ?\) The following steps appear to give equivalent equations, which seem to prove that \(1=0 .\) Find the error. \(\begin{aligned} x &=1 & & \text { Given } \\ x^{2} &=x & & \text { Multiply by } x \\ x^{2}-x &=0 & & \text { Subtract } x \end{aligned}$$(x-1)=0\)Factor \(\frac{(x-1)}{x-1}=\frac{0}{x-1} \quad\) Divide by \(x-1$$x=0 \quad\) Simplify\(1=0 \quad\) Given \(x=1\)

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