Chapter 1: Problem 88
Absolute Value Inequalities Solve the absolute value inequality. Express the answer using interval notation and graph the solution set. $$3-|2 x+4| \leq 1$$
Short Answer
Expert verified
The solution in interval notation is \((-\infty, -3] \cup [-1, \infty)\).
Step by step solution
01
Isolate the Absolute Value Expression
First, we need to isolate the absolute value term \(|2x + 4|\) in the inequality. We subtract 3 from both sides of the inequality: \(3 - |2x + 4| \leq 1\) becomes \[-|2x + 4| \leq -2\] To remove the negative sign, multiply through by -1, which will reverse the inequality:\[|2x + 4| \geq 2\]
02
Break Down the Absolute Value Inequality
The inequality \(|2x + 4| \geq 2\) can be interpreted as two separate inequalities:1. \(2x + 4 \geq 2\)2. \(2x + 4 \leq -2\)These account for both the positive and negative scenarios for the absolute value.
03
Solve the First Inequality
Solve the inequality \(2x + 4 \geq 2\) by subtracting 4 from both sides:\[2x \geq -2\]Next, divide by 2:\[x \geq -1\]
04
Solve the Second Inequality
Solve the inequality \(2x + 4 \leq -2\), again by subtracting 4 from both sides:\[2x \leq -6\]Divide by 2:\[x \leq -3\]
05
Combine the Solutions
We have two separate solutions: \(x \geq -1\) and \(x \leq -3\). Because the original inequality was \(|2x + 4| \geq 2\), these two inequalities are disjoint. The interval notation for the solution is:\((-\infty, -3] \cup [-1, \infty)\).
06
Graph the Solution Set
Draw a number line and plot points at \(-1\) and \(-3\). Use a filled circle on both points to signify they are included (inclusive). Shade the line towards negative infinity from \(-3\) and towards positive infinity from \(-1\), to represent the intervals \((-\infty, -3] \cup [-1, \infty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a handy mathematical expression used to describe a set of numbers, typically solutions to inequalities. Instead of listing all numbers in the set, interval notation succinctly provides the range of possible values. Here's how it works:
Generally, brackets or parentheses are used to denote the endpoints of the intervals:
Generally, brackets or parentheses are used to denote the endpoints of the intervals:
- A square bracket [ ] indicates that the endpoint is included in the interval, known as inclusive.
- A parenthesis ( ) implies the endpoint is not included, called exclusive.
- \((-\infty, -3]\)
- \([-1, \infty)\)
Inequality Solving
Solving absolute value inequalities involves a few specific steps that allow us to find the range of values a variable can take. Let's break it down out using the example inequality \(|2x + 4| \geq 2\):
First, we need to understand the meaning of the absolute value. When \(|2x + 4| \geq 2\), it indicates that the expression \(2x + 4\) can be either:
Once these scenarios are set, we solve each inequality separately:
In case of \(2x + 4 \geq 2\), subtract 4 from both sides to get \(2x \geq -2\), then divide by 2, resulting in \(x \geq -1\). For \(2x + 4 \leq -2\), subtract 4 to get \(2x \leq -6\) and divide by 2, yielding \(x \leq -3\).
The solutions \(x \geq -1\) and \(x \leq -3\) are separate due to the nature of the original inequality.
First, we need to understand the meaning of the absolute value. When \(|2x + 4| \geq 2\), it indicates that the expression \(2x + 4\) can be either:
- Greater than or equal to 2 (\(2x + 4 \geq 2\))
- Or less than or equal to -2 (\(2x + 4 \leq -2\))
Once these scenarios are set, we solve each inequality separately:
In case of \(2x + 4 \geq 2\), subtract 4 from both sides to get \(2x \geq -2\), then divide by 2, resulting in \(x \geq -1\). For \(2x + 4 \leq -2\), subtract 4 to get \(2x \leq -6\) and divide by 2, yielding \(x \leq -3\).
The solutions \(x \geq -1\) and \(x \leq -3\) are separate due to the nature of the original inequality.
Graphing Solution Sets
Graphing solution sets of inequalities helps visualize the solution on a number line, making it easier to comprehend. When we graph the solution set for \((-\infty, -3] \cup [-1, \infty)\), we use the following steps:
First, draw a horizontal line to represent the number line. Place markers on it at \(-3\) and \(-1\). Since the intervals are inclusive at these points, draw filled circles at these values:
These shaded regions represent solutions satisfying \(|2x + 4| \geq 2\). They visually show numbers belonging to either condition, as illustrated by the union of intervals.
First, draw a horizontal line to represent the number line. Place markers on it at \(-3\) and \(-1\). Since the intervals are inclusive at these points, draw filled circles at these values:
- A filled circle at \(-3\) signifies that -3 is part of the solution (\([, ]\))
- A filled circle at \(-1\) confirms -1's inclusion as well
These shaded regions represent solutions satisfying \(|2x + 4| \geq 2\). They visually show numbers belonging to either condition, as illustrated by the union of intervals.