Chapter 1: Problem 86
Find the center and radius of the circle, and sketch its graph. $$(x+1)^{2}+y^{2}=9$$
Short Answer
Expert verified
The center is \((-1, 0)\) and the radius is 3.
Step by step solution
01
Identify the Circle Equation
The equation given is \((x+1)^2 + y^2 = 9\). This is the standard form of a circle equation \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.
02
Determine the Center
Compare the given equation \((x+1)^2 + y^2 = 9\) to the standard form \((x-h)^2 + (y-k)^2 = r^2\). Here, \(h = -1\) and \(k = 0\). Thus, the center of the circle is \((-1, 0)\).
03
Determine the Radius
In the equation \((x+1)^2 + y^2 = 9\), the right-hand side is \(9\), which is \(r^2\) in the standard form. Therefore, the radius \(r\) is \(\sqrt{9} = 3\).
04
Sketch the Graph
To sketch the graph, plot the center of the circle at \((-1, 0)\). From this point, draw a circle with a radius of 3, ensuring all points on the circle are equidistant from the center.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Center of a Circle
To understand the center of a circle as depicted in a circle equation, it is crucial to begin by examining the standard form of a circle's equation: \[(x-h)^2 + (y-k)^2 = r^2\]Here, the components \(h\) and \(k\) represent the coordinates of the center of the circle, \((h, k)\). These coordinates are derived from the expressions
- \((x-h)^2\)
- \((y-k)^2\)
Radius of a Circle
The radius of a circle is a fundamental aspect defined by the term \(r^2\) in the equation \[(x-h)^2 + (y-k)^2 = r^2\].It represents the distance from the center of the circle to any point on the circumference.The exercise equation is \((x+1)^2 + y^2 = 9\). We know that the right side, 9, corresponds to \(r^2\). By taking the square root,
- \(r = \sqrt{9} = 3\)
Graphing Circles
Graphing a circle involves interpreting the circle's equation to position and draw it accurately on a coordinate plane. To plot a circle, you need the center and the radius derived from its equation. In our example, the center is
- \((-1, 0)\)
- 3 units