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Absolute Value Inequalities Solve the absolute value inequality. Express the answer using interval notation and graph the solution set. $$|8 x+3| > 12$$

Short Answer

Expert verified
The solution is \((-\infty, -\frac{15}{8}) \cup (\frac{9}{8}, \infty)\).

Step by step solution

01

Understanding the Absolute Value Inequality

We start with the inequality \(|8x+3| > 12\). The absolute value inequality \(|A| > B\) implies two scenarios: \(A > B\) or \(A < -B\). This inequality represents all numbers whose absolute distance from zero is greater than 12.
02

Breaking It into Two Cases

For \(|8x+3| > 12\), we have two cases to consider:1. \(8x + 3 > 12\)2. \(8x + 3 < -12\)We'll solve each of these inequalities separately.
03

Solving Case 1: 8x + 3 > 12

Subtract 3 from both sides to isolate the term with \(x\):\[8x + 3 - 3 > 12 - 3\]\[8x > 9\]Now, divide both sides by 8:\[x > \frac{9}{8}\]
04

Solving Case 2: 8x + 3 < -12

Subtract 3 from both sides:\[8x + 3 - 3 < -12 - 3\]\[8x < -15\]Divide both sides by 8:\[x < -\frac{15}{8}\]
05

Combining the Solutions

The solution to the absolute value inequality \(|8x+3| > 12\) is the union of the solutions to the two individual inequalities:\[x > \frac{9}{8}\] or \[x < -\frac{15}{8}\]In interval notation, this is expressed as:\((-\infty, -\frac{15}{8}) \cup (\frac{9}{8}, \infty)\).
06

Graphing the Solution Set

On a number line, the solution consists of two open intervals. Shade the region to the left of \(-\frac{15}{8}\) and the region to the right of \(\frac{9}{8}\) without including these endpoints, indicating two separate intervals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Inequalities
In mathematics, inequalities express the relationship between two expressions that are not necessarily equal. They reveal the difference in value through symbols like greater than (>) and less than (<). Inequalities demonstrate how quantities relate and order themselves.
When we talk about absolute value inequalities, as in this case of \(|8x+3| > 12\), we essentially handle inequalities involving absolute values.This indicates the number's distance from zero on the number line.
Notice that absolute value inequalities can result in two separate expressions. For instance, \(|A| > B\) becomes two cases: \(A > B\) and \(A < -B\). These scenarios cover the full range of numbers exceeding a certain distance from zero.
Using Interval Notation
Interval notation is a concise way to express set of solutions for inequalities. It's a shorthand method to describe intervals on a number line.
For example, in our solution \(x > \frac{9}{8}\) or \(x < -\frac{15}{8}\), the solution set is represented as \((-fty, -\frac{15}{8}) \cup (\frac{9}{8}, \infty)\). Here, each part of the interval uses parentheses \(()\) to show that endpoints are not included in the solution, known as open intervals.
The union symbol \(\cup\) indicates that the solutions for both separate conditions are combined. This way, interval notation efficiently handles the complex task of writing solutions without lengthy expressions.
Graphing Inequalities
Graphing inequalities provides a visual representation of solution sets on a number line.
In this case, we have two open intervals: one to the left of \(-\frac{15}{8}\) and another to the right of \(\frac{9}{8}\).To graph these, place an open circle at each endpoint and shade the entire region stretching to infinity on either side.
Open circles denote that endpoints are not part of the solution, keeping the intervals open.This graph vividly shows all values \(x\) that satisfy the inequality \(|8x+3| > 12\), giving a clear and immediate understanding of the solution set. Additionally, graphing such inequalities aids in connecting algebraic expressions with their geometric representations.

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Most popular questions from this chapter

DISCOVER - PROVE: Relationship Between Solutions and Coefficients The Quadratic Formula gives us the solutions of a quadratic equation from its coefficients. We can also obtain the coefficients from the solutions. (a) Find the solutions of the equation \(x^{2}-9 x+20=0\) and show that the product of the solutions is the constant term 20 and the sum of the solutions is \(9,\) the negative of the coefficient of \(x\) (b) Show that the same relationship between solutions and coefficients holds for the following equations:$$ \begin{array}{l}x^{2}-2 x-8=0 \\\x^{2}+4 x+2=0\end{array}$$ (c) Use the Quadratic Formula to prove that in general, if the equation \(x^{2}+b x+c=0\) has solutions \(r_{1}\) and \(r_{2}\) then \(c=r_{1} r_{2}\) and \(b=-\left(r_{1}+r_{2}\right)\)

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