Chapter 1: Problem 72
Find the \(x\) and \(y\)-intercepts of the line, and draw its graph. \(y=-4 x-10\)
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Chapter 1: Problem 72
Find the \(x\) and \(y\)-intercepts of the line, and draw its graph. \(y=-4 x-10\)
These are the key concepts you need to understand to accurately answer the question.
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Radicals Simplify the expression, and eliminate any negative exponents(s). Assume that all letters denote positive numbers. (a) \(\sqrt{x^{5}}\) (b) \(\sqrt[4]{x^{6}}\)
Use scientific notation, the Laws of Exponents, and a calculator to perform the indicated operations. State your answer rounded to the number of significant digits indicated by the given data. $$\frac{\left(3.542 \times 10^{-6}\right)^{9}}{\left(5.05 \times 10^{4}\right)^{12}}$$
Sketch the region given by the set. $$\left\\{(x, y) | x^{2}+y^{2} \leq 1\right\\}$$
Depth of a Well One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If \(d\) is the depth of the well (in feet) and \(t_{1}\) the time (in seconds) it takes for the stone to fall, then \(d=16 t_{1}^{2},\) so \(t_{1}=\sqrt{d} / 4 .\) Now if \(t_{2}\) is the time it takes for the sound to travel back up, then \(d=1090 t_{2}\) because the speed of sound is 1090 ft's. So \(t_{2}=d / 1090\) Thus the total time elapsed between dropping the stone and hearing the splash is $$t_{1}+t_{2}=\frac{\sqrt{d}}{4}+\frac{d}{1090}$$ How deep is the well if this total time is 3 s? PICTURE CANT COPY
A company manufactures industrial laminates (thin nylon-based sheets) of thickness 0.020 in., with a tolerance of 0.003 in. (a) Find an inequality involving absolute values that describes the range of possible thickness for the laminate. (b) Solve the inequality you found in part (a). (image cannot copy)
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