Chapter 1: Problem 70
Factor the trinomial. $$x^{2}+4 x-5$$
Short Answer
Expert verified
The trinomial factors to \((x - 1)(x + 5)\).
Step by step solution
01
Identify the Coefficients
First, identify the coefficients in the trinomial. Here, the trinomial is in the form of: \[ ax^2 + bx + c \]For the given expression, \( a = 1 \), \( b = 4 \), and \( c = -5 \).
02
Find Two Numbers with Product c and Sum b
Find two numbers that multiply to \( c = -5 \) and add to \( b = 4 \). The numbers that satisfy these conditions are \( 5 \) and \( -1 \):- Product: \( 5 \times (-1) = -5 \)- Sum: \( 5 + (-1) = 4 \).
03
Decompose the Middle Term
Rewrite the middle term, \( 4x \), using the numbers identified in Step 2:\[ x^2 + 5x - 1x - 5 \]
04
Group and Factor by Grouping
Group the terms as follows to enable factorization:\[ (x^2 + 5x) + (-1x - 5) \]Factor out the greatest common factor from each group:\[ x(x + 5) - 1(x + 5) \]
05
Factor Out the Common Binomial
Notice that \((x+5)\) is a common factor in both groups. Factor \((x+5)\) out:\[ (x - 1)(x + 5) \]
06
Conclusion: Verify the Factored Form
Expand \((x - 1)(x + 5)\) to check that it equals the original trinomial:\[ (x - 1)(x + 5) = x^2 + 5x - x - 5 = x^2 + 4x - 5 \]The factored form is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expressions
A quadratic expression is a type of polynomial with a degree of two. It generally comes in the form: \[ ax^2 + bx + c \] where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). A quadratic expression has an "x" term that is squared, making it a second-degree expression. This type of expression often describes parabolic curves in a graph.Quadratics are significant in mathematics because they are frequently used to model real-world situations. From calculating the trajectory of a thrown object to optimizing areas in resource management, quadratics are everywhere.In the exercise above, the quadratic expression is \( x^2 + 4x - 5 \). Breaking this down, we identify that \( a = 1 \), \( b = 4 \), and \( c = -5 \). Recognizing these coefficients is the first key step in factoring, which simplifies analysis and solves related equations.
Factoring by Grouping
Factoring by grouping is a handy algebraic technique used to simplify polynomials, particularly quadratics when they do not easily factor by simple inspection. The method involves rewriting the middle term of a trinomial as two separate terms, which facilitates factoring later.In the given problem, we use the numbers found, \( 5 \) and \(-1\), to decompose the middle term, creating two groups:
- First Group: \(x^2 + 5x\)
- Second Group: \(-x - 5\)
- From \(x^2 + 5x\), factor out \(x\) to get \(x(x + 5)\)
- From \(-x - 5\), factor out \(-1\) to get \(-1(x + 5)\)
Algebraic Techniques
Algebra involves numerous techniques, each designed for manipulating and breaking down expressions into simpler forms. Factoring is a particularly powerful method because it can transform complex equations into solvable parts, revealing roots and solutions.The process illustrated in this exercise utilizes several key algebraic skills:
- Identifying Coefficients: Determining \(a\), \(b\), and \(c\) is crucial for any quadratic expression as it sets the stage for other techniques like factoring.
- Finding Product and Sum: This step is searching for numbers that multiply to \(c\) and add to \(b\). It is grounded in understanding factor pairs and their relationships in an equation.
- Decomposition: Splitting the middle term for other factors to emerge, making polynomial division or further factorization accessible.