Chapter 1: Problem 6
The graph of the equation \((x-1)^{2}+(y-2)^{2}=9\) is a circle with center (_____ , _____) and radius __________.
Short Answer
Expert verified
Center: (1, 2); Radius: 3.
Step by step solution
01
Identify the general form of a circle's equation
The equation of a circle in standard form is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.
02
Read the given equation
The given equation is \((x-1)^2 + (y-2)^2 = 9\). This matches the standard form of a circle's equation.
03
Extract the center from the equation
In the equation \((x-1)^2 + (y-2)^2 = 9\), the expressions for \((h, k)\) can be seen directly. Here, \(h = 1\) and \(k = 2\). Therefore, the center of the circle is \((1, 2)\).
04
Determine the radius from the equation
The equation equates to \(r^2 = 9\), so we find the radius \(r\) by taking the square root of 9. Hence, \(r = 3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form of a Circle
To understand the equation of a circle, it's important to start with the standard form. The standard form of a circle's equation is expressed as \((x-h)^2 + (y-k)^2 = r^2\). Here, the terms \((h, k)\) represent the center of the circle, and \(r\) is the radius. The standard form is especially useful because it clearly shows these crucial details at a glance.
- The left side of the equation, \((x-h)^2 + (y-k)^2\), indicates the transformations applied to a circle's radius to shift its center from the origin to the specific point \((h, k)\).
- The right side of the equation, \(r^2\), represents the square of the radius of the circle.
Center of a Circle
The center of a circle is a fixed point from which all points on the circle are equidistant. In the equation \((x-h)^2 + (y-k)^2 = r^2\), the terms \((h, k)\) define the circle's center.
- The value \(h\) represents the x-coordinate of the center.
- The value \(k\) represents the y-coordinate of the center.
Finding the Center:
Take the values inside the parentheses:- The expression \((x-1)\) indicates a shift from \(x = 0\) to \(x = 1\).
- The expression \((y-2)\) shows a shift from \(y = 0\) to \(y = 2\).
Radius of a Circle
The radius of a circle is the constant distance from the center of the circle to any point on its edge. In the circle's standard form equation, \((x-h)^2 + (y-k)^2 = r^2\), the radius is represented as \(r\). But in this form, it's given as \(r^2\), so you'll need to take a square root to find \(r\). For example, when looking at the equation \((x-1)^2 + (y-2)^2 = 9\), you see that \(r^2 = 9\).
- Taking the square root of both sides gives \(r = \sqrt{9}\).
- This simplifies further to \(r = 3\), indicating that every point on the edge of the circle is 3 units away from the center \((1, 2)\).