/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Evaluate the quotient, and write... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the quotient, and write the result in the form \(a+b i\) $$\frac{10 i}{1-2 i}$$

Short Answer

Expert verified
The result is \(-4 + 2i\).

Step by step solution

01

Identify the Complex Numbers

Identify the complex numbers in the given expression. Here, the complex numbers are the numerator \(10i\) and the denominator \(1 - 2i\).
02

Conjugate of the Denominator

To eliminate the imaginary part from the denominator, multiply the numerator and the denominator by the conjugate of the denominator. The conjugate of \(1 - 2i\) is \(1 + 2i\).
03

Multiply Numerator and Denominator by the Conjugate

Multiply the expression by the conjugate of the denominator: \(\frac{10i}{1-2i} \times \frac{1+2i}{1+2i} = \frac{10i(1+2i)}{(1-2i)(1+2i)}\).
04

Simplify the Denominator

The denominator becomes a real number by using the formula \((a-b)(a+b) = a^2 - b^2\). Hence, \((1-2i)(1+2i) = 1^2 - (2i)^2 = 1 - 4(-1) = 1 + 4 = 5\).
05

Distribute Across the Numerator

Distribute \(10i\) across \((1 + 2i)\). This gives \(10i \cdot 1 + 10i \cdot 2i = 10i + 20i^2\).
06

Simplify the Numeric Expression

Since \(i^2 = -1\), replace \(i^2\) in \(20i^2\) with \(-1\), so it becomes \(20 \cdot -1 = -20\). Thus, the numerator is \(10i - 20\).
07

Write the Quotient in Standard Form

Write the result \(\frac{-20 + 10i}{5}\) as separate parts and simplify: \(-\frac{20}{5} + \frac{10i}{5} = -4 + 2i\). The expression is now in the form \(a + bi\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Part
In the realm of complex numbers, the imaginary part is crucial. A complex number is expressed generally as \(a + bi\), where \(a\) represents the real part, and \(bi\) signifies the imaginary part. The **imaginary part** is the component that involves the imaginary unit \(i\), which is defined by the fundamental property \(i^2 = -1\).
Understanding the imaginary part is key to performing arithmetic operations involving complex numbers. When calculating quotients like \(\frac{10i}{1-2i}\), identifying the imaginary component helps determine how to simplify the expression further by addressing the real and the imaginary parts distinctly.
- In this problem, \(10i\) is purely imaginary, with the coefficient 10 as the imaginary part.- The denominator \(1 - 2i\) contains both real (1) and imaginary (-2i) parts.
Recognizing and separating these parts aids in performing operations like multiplication with a conjugate, which balances the real and imaginary components across the equation.
Complex Conjugate
The complex conjugate is a vital concept in simplifying complex number expressions. The **complex conjugate** of a given complex number \(a + bi\) is \(a - bi\). This reflection across the real axis removes the imaginary part when multiplied by its original complex number.
For example, with the expression \(1 - 2i\), its conjugate is \(1 + 2i\). This trait is particularly useful for eliminating imaginary numbers from the denominator of a complex fraction. By multiplying both the numerator and the denominator by the conjugate of the denominator, you convert an uncomfortable imaginary scenario into a simple real division.
- Multiplying \(\frac{10i}{1-2i}\) by \(\frac{1+2i}{1+2i}\) uses the property of conjugates.- This results in the denominator becoming \((1-2i)(1+2i) = 1 + 4 = 5\), a real number.
Applying this method clears the path to expressing the result in the standard form \(a+bi\), where calculations can be more straightforward.
Standard Form of Complex Numbers
The **standard form of complex numbers** is crucial for comprehensibility and systematic computation. It allows complex numbers to be written as \(a + bi\), where \(a\) is the real part and \(b\) the imaginary part. This standardization provides a consistent way to evaluate, add, subtract, and multiply complex expressions.
After working through the problem, finding the standard form simplifies understanding and communicating results.- Begin with \(\frac{-20 + 10i}{5}\) from the simplified quotient.- Divide separated real and imaginary parts: - \(-\frac{20}{5} = -4\) - \(\frac{10i}{5} = 2i\)- Resulting in the standard form \(-4 + 2i\).
Having results in this standard form ensures clarity and ease when dealing with further mathematical operations involving complex expressions. Remember, always aim to express complex numbers in this form for maximum simplicity and utility.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Simplify the expression. (a) \((4 b)^{1 / 2}\left(8 b^{1 / 4}\right)\) (b) \(\left(3 a^{3 / 4}\right)^{2}\left(5 a^{1 / 2}\right)\)

Shrinkage in Concrete Beams As concrete dries, it shrinks - the higher the water content, the greater the shrinkage. If a concrete beam has a water content of \(\bar{w} \mathrm{kg} / \mathrm{m}^{3},\) then it will shrink by a factor $$S=\frac{0.032 w-2.5}{10,000}$$ where \(S\) is the fraction of the original beam length that disappears due to shrinkage. (a) A beam \(12.025 \mathrm{m}\) long is cast in concrete that contains \(250 \mathrm{kg} / \mathrm{m}^{3}\) water. What is the shrinkage factor \(S ?\) How Iong will the beam be when it has dried? (b) A beam is \(10.014 \mathrm{m}\) long when wet. We want it to shrink to \(10.009 \mathrm{m},\) so the shrinkage factor should be \(S=0.00050 .\) What water content will provide this amount of shrinkage? PICTURE CANT COPY

Use scientific notation, the Laws of Exponents, and a calculator to perform the indicated operations. State your answer rounded to the number of significant digits indicated by the given data. $$\left(7.2 \times 10^{-9}\right)\left(1.806 \times 10^{-12}\right)$$

Decimal Notation Write each number in decimal notation. (a) \(3.19 \times 10^{5}\) (b) \(2.721 \times 10^{8}\) (c) \(2.670 \times 10^{-8}\) (d) \(9.999 \times 10^{-9}\)

Profit \(\quad\) A small-appliance manufacturer finds that the profit \(P\) (in dollars) generated by producing \(x\) microwave ovens per week is given by the formula \(P=\frac{1}{10} x(300-x)\) provided that \(0 \leq x \leq 200 .\) How many ovens must be manufactured in a given week to generate a profit of \(\$ 1250 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.