/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 110 Factor the expression completely... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor the expression completely. $$r^{2}-6 r s+9 s^{2}$$

Short Answer

Expert verified
The expression factors to \((r - 3s)^2\).

Step by step solution

01

Identify the Type of Expression

The given expression is a quadratic trinomial: \( r^2 - 6rs + 9s^2 \). It appears to be a perfect square trinomial, which takes the form \( (a - b)^2 = a^2 - 2ab + b^2 \).
02

Compare with Perfect Square Formula

To verify if it's a perfect square trinomial, compare it with \( a^2 - 2ab + b^2 \). Here, \( a^2 = r^2 \), which means \( a = r \), and \( b^2 = 9s^2 \), meaning \( b = 3s \).
03

Check the Middle Term

The expression \( -6rs \) is the middle term. In the perfect square formula \( a^2 - 2ab + b^2 \), the middle term is \(-2ab\). Check if \(-2ab = -6rs\).\ \(-2 \times r \times 3s = -6rs\), which matches \( -6rs \).
04

Write the Expression as a Square

Since all conditions of the perfect square trinomial are satisfied, write the expression as the square of a binomial: \( (r - 3s)^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perfect Square Trinomials
A perfect square trinomial is a special form of quadratic expressions. It looks like \(a^2 - 2ab + b^2\) or \(a^2 + 2ab + b^2\). When you spot a quadratic trinomial that fits this pattern, it means it can be factored into the square of a binomial.
Let's take a closer look at our example: \(r^2 - 6rs + 9s^2\). We can see the structure of a perfect square trinomial, because the first term \(r^2\) is a perfect square, as is the last term \(9s^2\).
To determine the middle term, we need \(-2ab\). Here, you identify \(a\) and \(b\) with the values \(r\) and \(3s\) respectively, so the middle term becomes \-6rs\. It perfectly matches the middle term in our expression.
Recognizing these patterns is key to factoring perfectly square trinomials quickly.
Quadratic Expressions
Quadratic expressions are made from a polynomial equation of degree 2. In simpler terms, these expressions have the highest exponent of two, such as \(x^2 + bx + c\).
The general form allows for these expressions to sometimes be factored into simpler expressions, especially when they fit certain patterns like the perfect square trinomial.
In our exercise, we started with \(r^2 - 6rs + 9s^2\), which is clearly quadratic because of the \(r^2\). The goal with quadratic expressions is typically to simplify or factor them, easing the process of solving related equations.
This also helps in graphing and understanding the nature of the expression itself, as often seen in algebra.
Binomial Squares
A binomial square comes from squaring a binomial, such as \( (a - b)^2 \) or \( (a + b)^2 \). The result is a perfect square trinomial.
This connects directly to our exercise solution, where the expression \(r^2 - 6rs + 9s^2\) was factored into \( (r - 3s)^2 \).
This shows the function of binomial squares in simplifying and understanding quadratic expressions. Remember, binomial squares make forming and simplifying expressions easier, showcasing the elegance of algebraic structures.
These concepts are crucial because they not only help with factoring but also with solving equations that involve squares, providing a foundational tool in algebra.

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Most popular questions from this chapter

Depth of a Well One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If \(d\) is the depth of the well (in feet) and \(t_{1}\) the time (in seconds) it takes for the stone to fall, then \(d=16 t_{1}^{2},\) so \(t_{1}=\sqrt{d} / 4 .\) Now if \(t_{2}\) is the time it takes for the sound to travel back up, then \(d=1090 t_{2}\) because the speed of sound is 1090 ft's. So \(t_{2}=d / 1090\) Thus the total time elapsed between dropping the stone and hearing the splash is $$t_{1}+t_{2}=\frac{\sqrt{d}}{4}+\frac{d}{1090}$$ How deep is the well if this total time is 3 s? PICTURE CANT COPY

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