Chapter 1: Problem 108
Test the equation for symmetry. $$x^{4} y^{4}+x^{2} y^{2}=1$$
Short Answer
Expert verified
The equation is symmetric with respect to the x-axis, y-axis, and the origin.
Step by step solution
01
Identify Types of Symmetry
To test the symmetry of the given equation, Identify the three types of symmetries to check for: symmetry with respect to the x-axis, y-axis, and origin.
02
Check for X-axis Symmetry
For the test of x-axis symmetry, replace y with -y in the equation and check if the equation remains unchanged.Original equation: \[x^4 y^4 + x^2 y^2 = 1\]Replace y with -y:\[x^4 (-y)^4 + x^2 (-y)^2 = 1\]Since \((-y)^n = y^n\) when n is even, the equation remains: \[x^4 y^4 + x^2 y^2 = 1\]Thus, the equation is symmetric with respect to the x-axis.
03
Check for Y-axis Symmetry
To test for y-axis symmetry, replace x with -x in the equation and determine if it remains the same.Original equation: \[x^4 y^4 + x^2 y^2 = 1\]Replace x with -x: \[(-x)^4 y^4 + (-x)^2 y^2 = 1\]Since \((-x)^n = x^n\) when n is even, the equation simplifies to: \[x^4 y^4 + x^2 y^2 = 1\]Thus, the equation is symmetric with respect to the y-axis.
04
Check for Origin Symmetry
To test for origin symmetry, replace x with -x and y with -y. The equation should remain the same.Original equation: \[x^4 y^4 + x^2 y^2 = 1\]Replace x with -x and y with -y:\[(-x)^4 (-y)^4 + (-x)^2 (-y)^2 = 1\]Since both exponents are even, \[x^4 y^4 + x^2 y^2 = 1\]So, the equation is symmetric with respect to the origin.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-axis symmetry
Understanding symmetry with respect to the x-axis is important in mathematics, especially when dealing with graphs of equations. To determine if an equation is symmetric about the x-axis, you replace every occurrence of \( y \) with \( -y \) in the equation. If the resulting equation is identical to the original, then the graph of the equation is symmetric with respect to the x-axis.
This type of symmetry means that if a point \((x, y)\) is on the graph, then \((x, -y)\) will also be on the graph. A classic example would be the graph of the equation \( y^2 = x \), which shows symmetry about the x-axis. However, not every equation is symmetric; testing with \( x^4 y^4 + x^2 y^2 = 1 \), after substitution, the equation remains unchanged:
This type of symmetry means that if a point \((x, y)\) is on the graph, then \((x, -y)\) will also be on the graph. A classic example would be the graph of the equation \( y^2 = x \), which shows symmetry about the x-axis. However, not every equation is symmetric; testing with \( x^4 y^4 + x^2 y^2 = 1 \), after substitution, the equation remains unchanged:
- Original equation: \( x^4 y^4 + x^2 y^2 = 1 \).
- Substitution: \( x^4 (-y)^4 + x^2 (-y)^2 = 1 \).
- Since the equation remains \( x^4 y^4 + x^2 y^2 = 1 \), it shows x-axis symmetry.
y-axis symmetry
The concept of y-axis symmetry is quite similar to x-axis symmetry but focuses on the horizontal mirror line. For an equation to have y-axis symmetry, replacing \( x \) with \( -x \) has to yield the same equation. If it does, that's a clear sign that the graph is mirrored along the y-axis.
In simpler terms, this symmetry means that if the point \((x, y)\) exists on the graph, then \((-x, y)\) will also be present. An equation like \( x^2 + y = 3 \) will typically show this kind of symmetry. For the equation \( x^4 y^4 + x^2 y^2 = 1 \), replacing \( x \) with \( -x \) gives:
In simpler terms, this symmetry means that if the point \((x, y)\) exists on the graph, then \((-x, y)\) will also be present. An equation like \( x^2 + y = 3 \) will typically show this kind of symmetry. For the equation \( x^4 y^4 + x^2 y^2 = 1 \), replacing \( x \) with \( -x \) gives:
- Original equation: \( x^4 y^4 + x^2 y^2 = 1 \).
- Substitution: \( (-x)^4 y^4 + (-x)^2 y^2 = 1 \).
- It simplifies to the original: \( x^4 y^4 + x^2 y^2 = 1 \).
origin symmetry
Origin symmetry, also known as point symmetry or rotational symmetry, involves a situation where the graph of an equation is symmetric with respect to the origin. For an equation to exhibit origin symmetry, both \( x \) and \( y \) must be replaced with \( -x \) and \( -y \) respectively. If these changes transform the equation back to its original form, the equation has origin symmetry. This reflects that if a point \((x, y)\) lies on the graph, then \((-x, -y)\) will also lie on the graph.
Such symmetry indicates that rotating the graph 180 degrees around the origin will not change its appearance. Consider the equation \( y = x^3 \) as an example, which is symmetric about the origin. When we apply this test to \( x^4 y^4 + x^2 y^2 = 1 \):
Such symmetry indicates that rotating the graph 180 degrees around the origin will not change its appearance. Consider the equation \( y = x^3 \) as an example, which is symmetric about the origin. When we apply this test to \( x^4 y^4 + x^2 y^2 = 1 \):
- Original equation: \( x^4 y^4 + x^2 y^2 = 1 \).
- Substitution: \( (-x)^4 (-y)^4 + (-x)^2 (-y)^2 = 1 \).
- The equation remains \( x^4 y^4 + x^2 y^2 = 1 \).