/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Three vectors \(\mathbf{a}\), \(... [FREE SOLUTION] | 91Ó°ÊÓ

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Three vectors \(\mathbf{a}\), \(\mathbf{b}\), and \(\mathbf{c}\) are given. \(\mathbf{(a)}\) Find their scalar triple product \(\mathbf{a} \cdot(\mathbf{b} \times \mathbf{c}) .\) \(\mathbf{(b)}\) Are the vectors coplanar? If not, find the volume of the parallelepiped that they determine. $$\mathbf{a}=\mathbf{i}-\mathbf{j}+\mathbf{k}, \quad \mathbf{b}=-\mathbf{j}+\mathbf{k}, \quad \mathbf{c}=\mathbf{i}+\mathbf{j}+\mathbf{k}$$

Short Answer

Expert verified
(a) Scalar triple product is -2. (b) Vectors are not coplanar; volume is 2.

Step by step solution

01

Compute the cross product

First, we need to find the cross product of vectors \( \mathbf{b} \) and \( \mathbf{c} \). Recall that the cross product formula is given by:\[ \mathbf{b} \times \mathbf{c} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 0 & -1 & 1 \ 1 & 1 & 1 \end{vmatrix} \]Compute the determinant using the diagonals method:\[ \mathbf{b} \times \mathbf{c} = \mathbf{i}((-1)(1) - 1(1)) - \mathbf{j}(0(1) - 1(1)) + \mathbf{k}(0(1) - (-1)(1)) \]This simplifies to:\[ \mathbf{b} \times \mathbf{c} = \mathbf{i}(-1 - 1) + \mathbf{j}(1) + \mathbf{k}(1) \]\[ \mathbf{b} \times \mathbf{c} = -2\mathbf{i} + \mathbf{j} + \mathbf{k} \]
02

Compute the scalar triple product

Now, calculate the scalar triple product \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) \). Substitute \( \mathbf{a} = \mathbf{i} - \mathbf{j} + \mathbf{k} \) and use the cross product result from Step 1:\[ \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = (\mathbf{i} - \mathbf{j} + \mathbf{k}) \cdot (-2\mathbf{i} + \mathbf{j} + \mathbf{k}) \]Compute the dot product:\[ \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = 1(-2) + (-1)(1) + 1(1) \]Compute further:\[ \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = -2 - 1 + 1 = -2 \]
03

Determine if vectors are coplanar

Vectors are coplanar if their scalar triple product is zero. In this case, \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = -2 \), which is not zero. Therefore, the vectors are not coplanar.
04

Calculate the volume of the parallelepiped

Since the vectors are not coplanar, they form a parallelepiped whose volume is given by the absolute value of their scalar triple product. Calculate the volume:\[ V = |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| = |-2| = 2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross Product
The cross product is a mathematical operation that takes two vectors and produces another vector that is perpendicular to both. For two vectors \( \mathbf{u} = u_1\mathbf{i} + u_2\mathbf{j} + u_3\mathbf{k} \) and \( \mathbf{v} = v_1\mathbf{i} + v_2\mathbf{j} + v_3\mathbf{k} \), the cross product \( \mathbf{u} \times \mathbf{v} \) is determined using the determinant:\[\mathbf{u} \times \mathbf{v} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ u_1 & u_2 & u_3 \ v_1 & v_2 & v_3 \end{vmatrix}\]Hence, we perform operations to find the vector perpendicular to both input vectors. A significant aspect of the cross product is that it not only gives a vector but also a sense of orientation (right-hand rule). Besides, the magnitude of the cross product represents the area of the parallelogram spanned by the original two vectors.
Dot Product
The dot product is an operation on two vectors that results in a scalar. For vectors \( \mathbf{u} = u_1\mathbf{i} + u_2\mathbf{j} + u_3\mathbf{k} \) and \( \mathbf{v} = v_1\mathbf{i} + v_2\mathbf{j} + v_3\mathbf{k} \), the dot product is calculated as:\[\mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3\]This computation results in a single number, representing how much one vector extends in the direction of the other. When the dot product is zero, the vectors are orthogonal. In this context, the dot product is used in calculating the scalar triple product, which helps determine coplanarity and volume of structures like parallelepipeds.
Coplanarity
Coplanarity of vectors involves determining if multiple vectors lie within the same plane. For three vectors \( \mathbf{a}, \mathbf{b}, \) and \( \mathbf{c} \), they are said to be coplanar if their scalar triple product is zero:\[ \mathbf{a} \cdot ( \mathbf{b} \times \mathbf{c}) = 0\]Being coplanar implies that there is no volume created by the vectors, as they do not form a three-dimensional space. It's a critical evaluation when working with 3D vector problems to understand if the vectors lie flat or extend into a space. For example, three coplanar vectors won't form a parallelepiped.
Parallelepiped Volume
A parallelepiped is a 3D shape formed by three vectors, and its volume can be found using the scalar triple product:\[V =| \mathbf{a} \cdot ( \mathbf{b} \times \mathbf{c}) |\]This formula calculates the magnitude of the product, which gives the volume of the parallelepiped spanned by vectors \( \mathbf{a}, \mathbf{b}, \) and \( \mathbf{c} \). If the result is zero, it confirms the vectors are coplanar, meaning no volume exists. This is a practical way to determine spatial arrangements with vectors and is fundamental in physics and engineering when assessing structures and forces.

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Most popular questions from this chapter

An object located at the origin in a three-dimensional coordinate system is held in equilibrium by four forces. One has magnitude 7 Ib and points in the direction of the positive \(x\) -axis, so it is represented by the vector 7 i. The second has magnitude 24 Ib and points in the direction of the positive \(y\) -axis. The third has magnitude 25 Ib and points in the direction of the negative z-axis. (a) Use the fact that the four forces are in equilibrium (that is, their sum is 0 ) to find the fourth force. Express it in terms of the unit vectors \(\mathbf{i}, \mathbf{j},\) and \(\mathbf{k}\) (b) What is the magnitude of the fourth force?

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