Chapter 9: Problem 3
Find parametric equations for the line that passes through the point \(P\) and is parallel to the vector \(\mathbf{v}\). $$P(1,0,-2), \quad \mathbf{v}=\langle 3,2,-3\rangle$$
Short Answer
Expert verified
The parametric equations are \( x = 1 + 3t \), \( y = 2t \), and \( z = -2 - 3t \).
Step by step solution
01
Identify Components
First, identify the components of the problem. The given point is \( P(1,0,-2) \) and the direction vector is \( \mathbf{v} = \langle 3, 2, -3 \rangle \). We need to find the parametric equations of a line through point \( P \) parallel to \( \mathbf{v} \).
02
Write Parametric Equations Format
A line in space can be written in parametric form using a point and a direction vector. For a point \( (x_0, y_0, z_0) \) and a direction vector \( \langle a, b, c \rangle \), the parametric equations are: \[ x = x_0 + at \]\[ y = y_0 + bt \] \[ z = z_0 + ct \]
03
Substitute Point and Vector
Substitute the point \( P(1,0,-2) \) and the vector components \( \langle 3, 2, -3 \rangle \) into the parametric form. This gives: \[ x = 1 + 3t \]\[ y = 0 + 2t \] \[ z = -2 - 3t \]
04
Final Parametric Equations
The final parametric equations for the line through point \( P \) parallel to vector \( \mathbf{v} \) are: \[ x = 1 + 3t \]\[ y = 2t \] \[ z = -2 - 3t \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Directional Vector
A directional vector is a key concept in understanding the direction in which a line extends in space. It can be represented as a vector \(\mathbf{v} = \langle a, b, c \rangle\), where each component \(a\), \(b\), and \(c\) gives us information about the line's orientation in the \(x\), \(y\), and \(z\) axes respectively.
- In this exercise, the directional vector \(\mathbf{v} = \langle 3, 2, -3 \rangle \) tells us that the line moves 3 units along the \(x\)-axis, 2 units along the \(y\)-axis, and -3 units along the \(z\)-axis with each step \( t \).
- This vector serves as a guide for how the line behaves in three-dimensional space, dictating the path it takes.
- It is crucial as it helps us determine the parametric equations for the line, depicting the direction as functions of a parameter \(t\).
Point in 3D Space
A point in 3D space is defined by three coordinates \((x, y, z)\), each representing a unique position along the respective axis. For practical understanding, think of it as a precise marker in room that tells you exactly where something is located.
- The point given in the exercise is \(P(1, 0, -2)\). Here, \(1\) is the position on the \(x\)-axis, \(0\) on the \(y\)-axis, and \(-2\) on the \(z\)-axis.
- This particular point is important because it serves as a starting or reference point for the line in space.
- Whenever we talk about a line in 3D, this point provides a concrete location from which that line extends, with the directional vector then determining its path.
Lines in Space
Lines in space are a fundamental element of spatial geometry, described by parametric equations. These equations detail how a line extends through three-dimensional space based on a starting point and a direction indicated by a vector.
- \(x = 1 + 3t\)
- \(y = 2t\)
- \(z = -2 - 3t\)
These equations indicate that as \(t\) changes, the line extends infinitely in both directions within the 3D space, passing through the point \(P\) and parallel to the vector \(\mathbf{v}\). This visualization helps in comprehending not just the line's position, but also its infinite extension and direction across the space.
- The parametric form for a line relies heavily on a point \((x_0, y_0, z_0)\) and a direction vector \(\langle a, b, c \rangle\).
- The equations \(x = x_0 + at\), \(y = y_0 + bt\), and \(z = z_0 + ct\) define the trajectory of the line as the parameter \(t\) varies.
- This means that for each specific value of \(t\), we get a point on the line.
- \(x = 1 + 3t\)
- \(y = 2t\)
- \(z = -2 - 3t\)
These equations indicate that as \(t\) changes, the line extends infinitely in both directions within the 3D space, passing through the point \(P\) and parallel to the vector \(\mathbf{v}\). This visualization helps in comprehending not just the line's position, but also its infinite extension and direction across the space.