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Two vectors \(u\) and \(v\) are given. Find their dot product \(\mathbf{U}^{*} \mathbf{V}\). $$\mathbf{u}=\langle 2,5,0\rangle, \quad \mathbf{v}=\left\langle\frac{1}{2},-1,10\right\rangle$$

Short Answer

Expert verified
The dot product is \(-4\).

Step by step solution

01

Understanding Dot Product

The dot product of two vectors is found by multiplying corresponding components of the vectors and then summing up the products. If vectors \( \mathbf{u} = \langle a_1, a_2, a_3 \rangle \) and \( \mathbf{v} = \langle b_1, b_2, b_3 \rangle \), then the dot product is \( a_1b_1 + a_2b_2 + a_3b_3 \).
02

Component-wise Multiplication

For vectors \( \mathbf{u} = \langle 2, 5, 0 \rangle \) and \( \mathbf{v} = \langle \frac{1}{2}, -1, 10 \rangle \), compute the component-wise products: 1. \(2 \times \frac{1}{2} = 1\)2. \(5 \times (-1) = -5\)3. \(0 \times 10 = 0\).
03

Summing the Products

Now add the results of each component multiplication together: \[1 + (-5) + 0 = 1 - 5 = -4\]. Therefore, the dot product of \( \mathbf{u} \) and \( \mathbf{v} \) is \(-4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

vector multiplication
In mathematics, multiplying vectors is not as straightforward as regular number multiplication. One of the most common forms of vector multiplication is the dot product. This operation focuses on combining two vectors to produce a single scalar value. The dot product is not only a fundamental concept in vector mathematics but also widely used in various fields like physics and engineering to compute things like force, energy, and work. To calculate the dot product of two vectors, say \( \mathbf{u} \) and \( \mathbf{v} \), each component of \( \mathbf{u} \) is multiplied by its corresponding component in \( \mathbf{v} \).
Once each pair of components is multiplied, these products are summed together. This sum gives you the dot product, a real, single number.

When performing vector multiplication through the dot product:
  • Ensure vectors are of equal dimensions to use the dot product.
  • The result is a scalar, not a vector, making its interpretation straightforward in calculations.
  • Useful in determining vector angles, orthogonality, and projections between vectors.
component-wise product
The component-wise product lays the groundwork for the dot product calculation. This step is simple as each component of the first vector is individually multiplied by the corresponding component of the second vector. For example, if you have two vectors, \( \mathbf{u} = \langle 2, 5, 0 \rangle \) and \( \mathbf{v} = \langle \frac{1}{2}, -1, 10 \rangle \), you multiply component by component:
  • First component: \(2 \times \frac{1}{2} = 1\)
  • Second component: \(5 \times (-1) = -5\)
  • Third component: \(0 \times 10 = 0\)
The component-wise product does not give the final result of vector multiplication directly but is a crucial intermediate step toward it. Each component's multiplication makes it easier to handle and visualize the operation involved, ensuring clarity and reducing the possibility of errors.
Understanding this process helps in managing both theoretical and practical applications, simplifying complex vector mathematics into manageable calculations.
vector operations
Vector operations become quite fundamental when dealing with problems involving physics or engineering. Vectors can describe quantities that not only have a magnitude but also a direction, such as velocity or force. Vector operations allow us to add, subtract, multiply, and analyze these quantities.

Primarily, vector operations include:
  • Addition: Summing corresponding components of two vectors.
  • Subtraction: Subtracting corresponding components.
  • Multiplication: Includes scalar multiplication and the dot product, which we explored earlier.
  • Cross Product: Combining vectors to form another vector perpendicular to the original pair (defined only in 3-dimensional space).
Each operation has its specific use and rules that govern how they affect vectors. For instance, vector multiplication through the dot product is used not just for solving equations, but also for determining how parallel two vectors are. When the dot product is zero, vectors are orthogonal, implying a significant geometric interpretation.
By learning these operations and understanding how they manipulate vector quantities, you gain valuable insight into both theoretical and practical problems involving vector mathematics.

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Most popular questions from this chapter

A line is parallel to the vector \(\mathbf{v},\) and a plane has normal vector \(\mathbf{n}\). (a) If the line is perpendicular to the plane, what is the relationship between \(\mathbf{v}\) and \(\mathbf{n}\) (parallel or perpendicular)? (b) If the line is parallel to the plane (that is, the line and the plane do not intersect), what is the relationship between \(\mathbf{v}\) and \(\mathbf{n}\) (parallel or perpendicular)? (c) Parametric equations for two lines are given. Which line is parallel to the plane \(x-y+4 z=6 ?\) Which line is perpendicular to this plane? Line \(1: \quad x=2 t, \quad y=3-2 t, \quad z=4+8 t\) Line \(2: \quad x=-2 t, \quad y=5+2 t, \quad z=3+t\)

Every line can be described by infinitely many different sets of parametric equations, since any point on the line and any vector parallel to the line can be used to construct the equations. But how can we tell whether two sets of parametric equations represent the same line? Consider the following two sets of parametric equations: Line \(1: \quad x=1-t, \quad y=3 t, \quad z=-6+5 t\) Line \(2: \quad x=-1+2 t, \quad y=6-6 t, \quad z=4-10 t\) (a) Find two points that lie on Line 1 by setting \(t=0\) and \(t=1\) in its parametric equations. Then show that these points also lie on Line 2 by finding two values of the parameter that give these points when substituted into the parametric equations for Line 2 . (b) Show that the following two lines are not the same by finding a point on Line 3 and then showing that it does not lie on Line 4 Line \(3: \quad x=4 t, \quad y=3-6 t, \quad z=-5+2 t\) Line \(4: \quad x=8-2 t, \quad y=-9+3 t, \quad z=6-t\)

Let a \(=\langle 2,2,2\rangle\) \(\mathbf{b}=\langle- 2,-2,0\rangle,\) and \(\mathbf{r}=\langle x, y, z\rangle\) (a) Show that the vector equation \((\mathbf{r}-\mathbf{a}) \cdot(\mathbf{r}-\mathbf{b})=0\) represents a sphere, by expanding the dot product and simplifying the resulting algebraic equation. (b) Find the center and radius of the sphere. (c) Interpret the result of part (a) geometrically, using the fact that the dot product of two vectors is 0 only if the vectors are perpendicular. endpoints of the vectors \(\mathbf{a}, \mathbf{b},\) and \(\mathbf{r},\) noting that the end. points of a and b are the endpoints of a diameter and the endpoint of \(\mathbf{r} \text { is an arbitrary point on the sphere. }]\) (d) Using your observations from part (a), find a vector equation for the sphere in which the points \((0,1,3)\) and \((2,-1,4)\) form the endpoints of a diameter. Simplify the vector equation to obtain an algebraic equation for the sphere. What are its center and radius?

Three vectors \(\mathbf{a}\), \(\mathbf{b}\), and \(\mathbf{c}\) are given. \(\mathbf{(a)}\) Find their scalar triple product \(\mathbf{a} \cdot(\mathbf{b} \times \mathbf{c}) .\) \(\mathbf{(b)}\) Are the vectors coplanar? If not, find the volume of the parallelepiped that they determine. $$\mathbf{a}=2 \mathbf{i}-2 \mathbf{j}-3 \mathbf{k}, \quad \mathbf{b}=3 \mathbf{i}-\mathbf{j}-\mathbf{k}, \quad \mathbf{c}=6 \mathbf{i}$$

Two vectors \(u\) and \(v\) are given. Find the angle (expressed in degrees) between \(\mathbf{u}\) and \(v\) $$\mathbf{u}=\langle 2,-2,-1\rangle, \quad \mathbf{v}=\langle 1,2,2\rangle$$

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