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Find parametric equations for the line that passes through the points \(P\) and \(Q\) $$P(1,1,0), \quad Q(0,2,2)$$

Short Answer

Expert verified
The parametric equations are \(x = 1 - t\), \(y = 1 + t\), \(z = 2t\).

Step by step solution

01

Determine the Direction Vector

To find the parametric equations of the line, we first need to determine the direction vector from point \(P\) to point \(Q\). This direction vector \(\mathbf{d}\) can be found by subtracting the coordinates of \(P\) from \(Q\): \(\mathbf{d} = Q - P = (0-1, 2-1, 2-0) = (-1, 1, 2)\).
02

Write the Parametric Equations

Using point \(P(1,1,0)\) as a reference point and the direction vector \(\mathbf{d} = (-1,1,2)\), we can write the parametric equations for the line. These will be in the form: \(x = 1 - t\), \(y = 1 + t\), and \(z = 0 + 2t\), where \(t\) is the parameter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direction Vector
When working with parametric equations in three-dimensional space, one essential concept is the **direction vector**. This vector provides a direction along which the line extends. If you have two given points, say, \(P(1,1,0)\) and \(Q(0,2,2)\), you can calculate the direction vector by finding the difference between the two points.
The direction vector \(\mathbf{d}\) is determined by subtracting the coordinates of the starting point from the coordinates of the ending point. Thus, for points \(P\) and \(Q\), we perform the following subtraction:
  • For the \(x\)-coordinate: \(0 - 1 = -1\)
  • For the \(y\)-coordinate: \(2 - 1 = 1\)
  • For the \(z\)-coordinate: \(2 - 0 = 2\)
Hence, the direction vector is \((-1, 1, 2)\). This vector essentially tells us that for each move in a parametric step \(t\), the line will move \(-1\) unit in the x-direction, \(+1\) unit in the y-direction, and \(+2\) units in the z-direction. The direction vector is crucial as it provides the pathway in which the line progresses.
Coordinate Geometry
Coordinate geometry, or analytic geometry, deals with understanding geometrical shapes through algebraic equations. In 3D space, a line can be represented using parametric equations, which are a powerful tool in coordinate geometry.
Parametric equations break down the complexity of describing a line in three dimensions by using a parameter, usually denoted as \(t\). By expressing the coordinates \((x, y, z)\) of points on the line in terms of \(t\), we simplify the representation of geometrical paths. For instance, given the point \(P(1,1,0)\) and the direction vector \((-1, 1, 2)\), the parametric form of the line is:
  • \(x(t) = 1 - t\)
  • \(y(t) = 1 + t\)
  • \(z(t) = 0 + 2t\)
Each of these equations will give the \(x\), \(y\), and \(z\) coordinates of any point on the line for a specific value of \(t\). This formulation not only helps in visualizing the line but also aids in performing calculations involving lines and distances in 3D space.
Line Equations
Line equations in three-dimensional space can take different forms, but the parametric form is particularly handy. It describes lines in terms of direction vectors and initial points.
A parametric line equation in 3D space expresses each coordinate as a function of a single variable \(t\), capturing the line's direction and position:
  • \(x = x_0 + at\)
  • \(y = y_0 + bt\)
  • \(z = z_0 + ct\)
In these expressions, \((x_0, y_0, z_0)\) represents a point on the line, and \((a, b, c)\) represents the direction vector. This construction makes understanding and working with lines more intuitive, especially in physics and engineering where trajectories are often dealt with.
For example, given \(P(1,1,0)\) and a direction vector \((-1, 1, 2)\), substituting into these formulas provides the parametric equations that describe the line connecting any point on it. Parametric equations streamline the process of finding lines in space, making complex spatial problems more manageable.

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Most popular questions from this chapter

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