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Find the indicated power using De Moivre’s Theorem. $$(2-2 i)^{8}$$

Short Answer

Expert verified
The result is 4096.

Step by step solution

01

Convert Complex Number to Polar Form

First, we need to determine the modulus \(r\) and the argument \(\theta\) of the complex number \(2 - 2i\). Calculate the modulus using the formula \(r = \sqrt{a^2 + b^2}\), where \(a = 2\) and \(b = -2\). Thus, \(r = \sqrt{2^2 + (-2)^2} = \sqrt{8} = 2\sqrt{2}\). Next, find \(\theta\) using the formula \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\). Here, \(\theta = \tan^{-1}\left(\frac{-2}{2}\right) = \tan^{-1}(-1) = -\frac{\pi}{4}\). So, the polar form is \(2\sqrt{2}(\cos(-\frac{\pi}{4}) + i\sin(-\frac{\pi}{4}))\).
02

Apply De Moivre’s Theorem

De Moivre’s Theorem states that if \(z = r(\cos \theta + i\sin \theta)\), then \(z^n = r^n (\cos(n\theta) + i\sin(n\theta))\). Here, \(n = 8\), \(r = 2\sqrt{2}\), and \(\theta = -\frac{\pi}{4}\). Thus, we have \(z^8 = (2\sqrt{2})^8(\cos(8 \times -\frac{\pi}{4}) + i\sin(8 \times -\frac{\pi}{4}))\).
03

Compute the modulus to the Power of 8

Compute \((2\sqrt{2})^8\). Since \(2\sqrt{2} = 2^{1.5}\), then \((2\sqrt{2})^8 = (2^{1.5})^8 = 2^{12} = 4096\).
04

Compute the New Argument

Calculate the new argument: \(8 \times -\frac{\pi}{4} = -2\pi\). Since having an argument of \(-2\pi\) is equivalent to \(0\) (due to the periodicity of trigonometric functions), the trigonometric functions simplify to \(\cos(0) = 1\) and \(\sin(0) = 0\).
05

Write the Final Expression

Substitute back into the polar form to find the final expression for \((2-2i)^8\): \(4096(\cos(0) + i\sin(0)) = 4096(1 + 0i) = 4096\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are essential in mathematics and engineering because they allow us to work with quantities that have both real and imaginary parts. A complex number is generally expressed in the form \(a + bi\), where \(a\) is the real part, and \(b\) is the imaginary part with \(i\) being the unit imaginary number satisfying \(i^2 = -1\).
  • The real part \(a\) represents the horizontal axis on the complex plane.
  • The imaginary part \(bi\) represents the vertical axis on the complex plane.
  • Every complex number can be plotted on this plane, giving it a unique position.
Understanding how to work with complex numbers is crucial when delving into more advanced topics like De Moivre's Theorem, where polar representation becomes a valuable tool.
Polar Form
To make computations involving complex numbers easier, we often convert them into polar form. In polar form, a complex number is expressed as \(r(\cos \theta + i\sin \theta)\), where \(r\) is the modulus, and \(\theta\) is the argument.

  • The modulus \(r\) measures the distance from the origin to the point in the complex plane.
  • The angle \(\theta\), known as the argument, indicates the direction of the point from the positive real axis.
  • This conversion from Cartesian form \(a + bi\) to polar form is crucial for simplifying multiplication, division, and exponentiation of complex numbers.
Polar form also facilitates the use of De Moivre’s Theorem, making it simpler to raise complex numbers to powers.
Modulus and Argument
When dealing with complex numbers, calculating the modulus and argument is the first step to converting them into polar form.
- **Modulus**: The modulus \(r\) is obtained using the formula \(r = \sqrt{a^2 + b^2}\). It's the "length" of the vector representing the complex number on the complex plane and is always a non-negative number. In our example, the modulus of \(2 - 2i\) is \(2\sqrt{2}\).
- **Argument**: The argument \(\theta\) is calculated as \(\tan^{-1}(b/a)\). This angle is measured from the positive real axis to the vector in a counter-clockwise direction. It helps define the "direction" of the complex number from the origin.
For \(2 - 2i\), the argument \(\theta\) was found to be \(-\frac{\pi}{4}\), which helps set up our complex number for further operations.
Trigonometric Functions
Trigonometric functions play a pivotal role in the manipulation of complex numbers, especially when using De Moivre's Theorem.- **Cosine and Sine**: These functions are used in the polar representation of complex numbers as \(\cos \theta\) and \(\sin \theta\). They help break down the "direction" of the complex vector into components.
- **Periodicity**: Trigonometric functions are periodic, meaning they repeat their values in regular intervals. For example, \(\cos(\theta + 2\pi k) = \cos \theta\) for any integer \(k\). This property simplifies calculations like finding equivalent angles.
- **Use in De Moivre's Theorem**: When raising a complex number to a power, De Moivre’s Theorem uses these functions in the form \(\cos n\theta + i \sin n\theta\), allowing us to solve powers of complex numbers with ease.De Moivre's Theorem not only leverages these functions for simplification but also highlights their fundamental role in connecting complex numbers to the unit circle.

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Most popular questions from this chapter

The Mazda RX-8 uses an unconventional engine (invented by Felix Wankel in 1954 ) in which the pistons are replaced by a triangular rotor that turns in a special housing as shown in the figure. The vertices of the rotor maintain contact with the housing at all times, while the center of the triangle traces out a circle of radius \(r,\) turning the drive shaft. The shape of the housing is given by the parametric equations below (where \(R\) is the distance between the vertices and center of the rotor): $$x=r \cos 3 \theta+R \cos \theta \quad y=r \sin 3 \theta+R \sin \theta$$ (a) Suppose that the drive shaft has radius \(r=1 .\) Graph the curve given by the parametric equations for the following values of \(R: 0.5,1,3,5\). (b) Which of the four values of \(R\) given in part (a) seems to best model the engine housing illustrated in the figure?

Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\). Express your answer in polar form. $$z_{1}=3\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right), \quad z_{2}=5\left(\cos \frac{4 \pi}{3}+i \sin \frac{4 \pi}{3}\right)$$

Find the indicated power using De Moivre’s Theorem. $$(1+i)^{20}$$

A polar equation is given. (a) Express the polar equation in parametric form. (b) Use a graphing device to graph the parametric equations you found in part (a). $$r=\sin \theta+2 \cos \theta$$

A dog is tied to a circular tree trunk of radius 1 ft by a long leash. He has managed to wrap the entire leash around the tree while playing in the yard, and he finds himself at the point \((1,0)\) in the figure. Seeing a squirrel, he runs around the tree counterclockwise, keeping the leash taut while chasing the intruder. (a) Show that parametric equations for the dog's path (called an involute of a circle) are $$x=\cos \theta+\theta \sin \theta \quad y=\sin \theta-\theta \cos \theta$$ [Hint: Note that the leash is always tangent to the tree, so \(O T \text { is perpendicular to } T D .]\) (b) Graph the path of the dog for \(0 \leq \theta \leq 4 \pi\)

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