Chapter 7: Problem 41
Solve the given equation. $$4 \cos ^{2} \theta-4 \cos \theta+1=0$$
Short Answer
Expert verified
Solutions are \( \theta = \frac{\pi}{3} + 2n\pi \) or \( \theta = \frac{5\pi}{3} + 2n\pi \) where \( n \) is an integer.
Step by step solution
01
Understand the Equation
The given equation is \(4 \cos^{2} \theta - 4 \cos \theta + 1 = 0\). This is a quadratic equation in terms of \( \cos \theta \). To solve it, we treat \( \cos \theta \) as a variable, say \( x \), and rewrite the equation as \( 4x^2 - 4x + 1 = 0 \).
02
Apply the Quadratic Formula
The general form of a quadratic equation is \( ax^2 + bx + c = 0 \). Here, \( a = 4 \), \( b = -4 \), and \( c = 1 \). The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute the values to get \( x = \frac{4 \pm \sqrt{(-4)^2 - 4 \cdot 4 \cdot 1}}{8} \).
03
Simplify the Discriminant
Simplify \( \sqrt{(-4)^2 - 4 \times 4 \times 1} \) which is \( \sqrt{16 - 16} \), resulting in \( \sqrt{0} \). Thus the expression becomes \( x = \frac{4 \pm 0}{8} \).
04
Solve for x
Since the discriminant is zero, there is only one solution for \( x \): \( x = \frac{4}{8} = \frac{1}{2} \). Therefore, \( \cos \theta = \frac{1}{2} \).
05
Find the Angles for \( \cos \theta = \frac{1}{2} \)
The cosine function equals \( \frac{1}{2} \) at angles \( \theta = 60^\circ \) or \( \theta = 300^\circ \) (in degrees), or \( \theta = \frac{\pi}{3} \) and \( \theta = \frac{5\pi}{3} \) (in radians).
06
Complete the Solution
The general solution for \( \cos \theta = \frac{1}{2} \) can also be expressed as \( \theta = 2n\pi \pm \frac{\pi}{3} \) where \( n \) is any integer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a fundamental concept in algebra, and they generally take the form \( ax^2 + bx + c = 0 \). These equations involve terms where the variable is raised to the highest power of two. Solving these equations usually demands finding the values of \( x \) that satisfy the equation. To achieve this, we often use the quadratic formula:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- The formula allows us to calculate the roots of any quadratic equation directly.
- The term \( b^2 - 4ac \) is known as the 'discriminant'.
- It determines the nature of the roots:
- If it is positive, there are two distinct real roots.
- If zero, there is exactly one real root.
- If negative, the equation has complex roots.
Cosine Function
The cosine function is one of the primary trigonometric functions. Cosine is the ratio of the adjacent side of a right triangle to its hypotenuse, and it's denoted by \( \cos \theta \). Here are some critical points to understand:
- The cosine function is periodic, with a cycle that repeats every \( 2\pi \) radians or 360 degrees.
- Values of the cosine function oscillate between -1 and 1.
Graphical Understanding
The graph of the cosine function forms a wave-like pattern that helps visually identify points where the cosine equals specific values.- At \( \theta = 0 \) or any multiples of \( 2\pi \), \( \cos \theta = 1 \).
- When \( \theta = \pi/2 \) or its odd multiples, \( \cos \theta = 0 \).
- Sustained at -1 at \( \theta = \pi \) or its even multiples.
Radians and Degrees
Radians and degrees are two units for measuring angles. Understanding both is key in trigonometry for converting and solving problems:
- Degrees: The full circle is 360 degrees. It's the more common unit used in everyday contexts and initial learning.
- Radians: This unit is more prevalent in higher mathematics. A full circle is \( 2\pi \) radians.
Conversion Basics
To interconvert between radians and degrees:- From degrees to radians, multiply by \( \frac{\pi}{180} \).
- From radians to degrees, multiply by \( \frac{180}{\pi} \).
- \( 60^\circ \) is equivalent to \( \frac{\pi}{3} \) radians.
- \( 300^\circ \) equals \( \frac{5\pi}{3} \) in radians.