/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Solve triangle \(A B C\). \(b=... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve triangle \(A B C\). \(b=125, \quad c=162, \quad \angle B=40^{\circ}\)

Short Answer

Expert verified
\(a = 104\), \(\angle A \approx 83.8^\circ\), \(\angle C \approx 56.2^\circ\).

Step by step solution

01

Identify What Is Given

The problem gives us the lengths of two sides of triangle \(ABC\) and one angle. Specifically, we have \(b = 125 \), \( c = 162 \), and \( \angle B = 40^\circ \). The task is to find the other angles and the remaining side, \(a\).
02

Apply the Law of Cosines

To find side \(a\), we use the Law of Cosines: \[ a^2 = b^2 + c^2 - 2bc \cdot \cos B \].Substitute the known values:\[ a^2 = 125^2 + 162^2 - 2 \times 125 \times 162 \times \cos 40^\circ \].Calculate to find \(a\).
03

Calculate the Value of \(a\)

First, calculate each part:\(125^2 = 15625\), \(162^2 = 26244\).\(2 \times 125 \times 162 = 40500.\)\(\cos 40^\circ \approx 0.7660\).Substitute these into the equation:\[ a^2 = 15625 + 26244 - 40500 \times 0.7660 \].\[ a^2 = 41869 - 31053.0 \].\[ a^2 = 10816\].Thus, \( a = \sqrt{10816} = 104 \).
04

Apply the Law of Sines to Find \(\angle C\)

Using the Law of Sines, we have:\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \].We use \( \frac{c}{\sin C} = \frac{b}{\sin 40^\circ} \) to find \(\sin C\):\[ \frac{162}{\sin C} = \frac{125}{\sin 40^\circ} \].Solve for \(\sin C\):\[ \sin C = \frac{162 \times \sin 40^\circ}{125} \approx \frac{162 \times 0.6428}{125} \approx 0.834 \].Thus, \( \angle C \approx \sin^{-1}(0.834) \approx 56.2^\circ \).
05

Use the Angle Sum Property to Find \(\angle A\)

In any triangle, the sum of angles \(A, B,\) and \(C\) is \(180^\circ\). Since we know \(\angle B = 40^\circ\) and \(\angle C \approx 56.2^\circ\),we find \(\angle A\) by subtracting from \(180^\circ\):\[ \angle A = 180^\circ - 40^\circ - 56.2^\circ \approx 83.8^\circ \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triangle solving
Solving a triangle involves determining all its unknown sides and angles based on the given information. It's like piecing together a puzzle where you know some parts and need to find others.
Typically, you start with known values like side lengths or angles, and use various trigonometric laws to find the missing pieces.
In this particular problem, we're looking at triangle \(ABC\) and are given two sides, \(b = 125\) and \(c = 162\), and an angle, \(\angle B = 40^\circ\).
To perform triangle solving efficiently, you may use:
  • The Law of Cosines: helpful for finding a side when two sides and their included angle are given.
  • The Law of Sines: useful for relating the sides and angles when two angles and one side are known.
  • The Angle Sum Property: every triangle's angles add up to \(180^\circ\), which can help find the unknown angle once you know two angles.
For this exercise, applying each of these tools will help us determine the side \(a\) and the remaining angles \(\angle A\) and \(\angle C\).
Law of Sines
The Law of Sines is a powerful formula used in triangle solving. It helps find unknown angles or sides when certain sides and angles are known.
The formula is given by:
\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \]
Here, each ratio represents side length over the sine of the opposite angle, establishing a relationship for each side-angle pair.
In simple terms, it's about comparing proportionality between different trigonometric expressions in the triangle.
In the current problem, after finding side \(a\) using the Law of Cosines, we apply the Law of Sines to determine \(\angle C\).
  • We used the equation \( \frac{162}{\sin C} = \frac{125}{\sin 40^\circ} \).
  • Solving this yields \(\sin C\), and hence \(\angle C\), simplifies calculation by providing a straightforward relation.
Understanding the Law of Sines helps you work through complex triangles much more easily by breaking them down into simpler ratios.
Angle sum property
The angle sum property is a fundamental principle in geometry, primarily associated with triangles.
It states that the sum of all internal angles in any triangle is always \(180^\circ\). This principle is key for determining the final unknown angle in a triangle when the other two are known.
In our exercise, where we already figured out \(\angle B = 40^\circ\) and approximate \(\angle C = 56.2^\circ\), this property allows us to easily calculate \(\angle A\) by:
  • Subtracting the sum of \(\angle B\) and \(\angle C\) from \(180^\circ\).
This property is especially handy when you have derived two angles from other methods, such as using trigonometric laws, providing a quick way to complete your triangle solution.
Thus, ensuring all elements of the triangle are known and verified.

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