Chapter 4: Problem 84
A function \(f(x)\) is given. (a) Find the domain of the function \(f .\) (b) Find the inverse function of \(f .\) $$f(x)=\ln (\ln (\ln x))$$
Short Answer
Expert verified
Domain of \(f(x)\): \((e, \infty)\). Inverse \(f^{-1}(x) = e^{e^{e^x}}\).
Step by step solution
01
Determine the Domain of the Innermost Function
The innermost function is the natural logarithm, \( \ln x \). For this function to be defined, \( x > 0 \).
02
Solve for the Domain of the Second Function
The second function, \( \ln (\ln x) \), is only defined when \( \ln x > 0 \). Solving \( \ln x > 0 \) implies \( x > 1 \).
03
Solve for the Domain of the Entire Function
The outermost function is \( \ln (\ln (\ln x)) \), and it requires \( \ln (\ln x) > 0 \). Using the result from Step 2, this means \( \ln x > 1 \). Solving \( \ln x > 1 \) gives \( x > e \). Thus, the domain of \( f(x) \) is \( (e, \infty) \).
04
Express the Inverse Function
To find the inverse function, we start by setting \( y = f(x) = \ln (\ln (\ln x)) \). We then solve the equation for \( x \).
05
Exponentiate to Remove the First Logarithm
Exponentiating both sides of \( y = \ln (\ln (\ln x)) \) gives \( e^y = \ln (\ln x) \).
06
Exponentiate Again to Remove the Second Logarithm
Exponentiating both sides of \( e^y = \ln (\ln x) \) results in \( e^{e^y} = \ln x \).
07
Get the Exponent of the Innermost Function
Lastly, exponentiating both sides of \( e^{e^y} = \ln x \) results in \( e^{e^{e^y}} = x \). Therefore, the inverse function \( f^{-1}(x) \) is \( f^{-1}(x) = e^{e^{e^x}} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a function
When working with functions, understanding the domain is essential. The domain of a function refers to all the possible input values (often referred to as "x") for which the function is defined. In simpler terms, it answers the question: "What can I put into this function?"
For example, consider the function described in the exercise, which is a composition of natural logarithm functions: \(f(x) = \ln(\ln(\ln x))\). Each logarithm function is only defined for positive numbers:
For example, consider the function described in the exercise, which is a composition of natural logarithm functions: \(f(x) = \ln(\ln(\ln x))\). Each logarithm function is only defined for positive numbers:
- The innermost function \(\ln x\) is defined for \(x > 0\).
- The next layer \(\ln(\ln x)\) adds another condition. The result of \(\ln x\) must also be positive, so \(x > 1\).
- The outermost function \(\ln(\ln(\ln x))\) requires \(\ln(\ln x) > 0\), which limits \(x > e\), where \(e\) is the base of the natural logarithm, approximately 2.71828.
Natural logarithm
The natural logarithm, denoted as \(\ln(x)\), is a fundamental function in mathematics. It is the inverse of the exponential function where the base is \(e\), a special constant approximately equal to 2.71828. Here's what you need to know:
- The natural logarithm of a number \(x\) answers the question "To what power must \(e\) be raised, to get \(x\)?"
- Because the logarithm is the inverse of an exponential function, \(\ln(e^y) = y\) for any real number \(y\).
- A key property of \(\ln x\) is that it is only defined for positive real numbers, i.e., \(x > 0\). This means when you see a \(\ln\) in a function, you must ensure the argument inside the \(\ln\) is positive for the function to be valid.
Function composition
Function composition is a method of combining two or more functions in such a way that the output of one function becomes the input of another. It is represented as \((f \circ g)(x) = f(g(x))\), which means you first apply \(g\) to \(x\), then apply \(f\) to the result.
In our specific case with \(f(x) = \ln(\ln(\ln x))\), we can see this composition at work:
In our specific case with \(f(x) = \ln(\ln(\ln x))\), we can see this composition at work:
- First, process the innermost function: \(g(x) = \ln x\). Apply \(\ln\) to \(x\).
- Next, let the result of \(g(x)\) be fed into another function, \(h(x) = \ln(\ln x)\).
- Finally, feed the result of \(h(x)\) into the outer function \(f(x) = \ln(\ln(\ln x))\).