/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 In this chapter we adopted the c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In this chapter we adopted the convention that in rational functions, the numerator and denominator don't share a common factor. In this exercise we consider the graph of a rational function that does not satisfy this rule. (a) Show that the graph of $$ r(x)=\frac{3 x^{2}-3 x-6}{x-2} $$ is the line \(y=3 x+3\) with the point \((2,9)\) removed. [Hint: Factor. What is the domain of \(r ?]\) (b) Graph the rational functions: $$ \begin{aligned} s(x) &=\frac{x^{2}+x-20}{x+5} \\ t(x) &=\frac{2 x^{2}-x-1}{x-1} \\ u(x) &=\frac{x-2}{x^{2}-2 x} \end{aligned} $$

Short Answer

Expert verified
(a) The graph is the line \(y = 3x + 3\) with a hole at \((2, 9)\). (b) Graphs: \(s(x)\) line with hole at \(-5\), \(t(x)\) line with hole at \(1\), \(u(x)\) hyperbola excluding \(2\).

Step by step solution

01

Factoring the numerator of r(x)

Given the rational function \( r(x) = \frac{3x^2 - 3x - 6}{x-2} \), start by factoring the numerator. Notice that each term in the numerator \(3x^2 - 3x - 6\) can be factored by taking out a common factor of 3, leading to \(3(x^2 - x - 2)\). Further factor \(x^2 - x - 2\) as \((x-2)(x+1)\). Thus, the numerator becomes \(3(x-2)(x+1)\).
02

Simplifying the rational function r(x)

Now, simplify \(r(x)\) by canceling the common factor \((x-2)\) in the numerator and the denominator: \(r(x) = \frac{3(x-2)(x+1)}{x-2} = 3(x+1)\) for \(x eq 2\). Thus, \(r(x)\) simplifies to \(3(x+1)\), or \(3x + 3\) with \(x eq 2\).
03

Determine the properties of the graph of r(x)

The above simplification of \(r(x)\) shows that the graph of \(r(x)\) is the line \(y = 3x + 3\), but there is a restriction at \(x = 2\). At \(x = 2\), the original function is undefined, removing the point \((2, \, 3(2) + 3) = (2, 9)\) from the line.
04

Analyze and graph s(x)

Given \(s(x) = \frac{x^2 + x - 20}{x+5}\), factor the numerator: \(x^2 + x - 20 = (x+5)(x-4)\). Cancel the common factor \((x+5)\), resulting in \(s(x) = x - 4\) for \(x eq -5\), indicating \(s(x)\) is a line with a hole at \(x = -5\).
05

Analyze and graph t(x)

For \(t(x) = \frac{2x^2 - x - 1}{x-1}\), begin by factoring the numerator: \(2x^2 - x - 1 = (2x+1)(x-1)\). Cancel the factor \((x-1)\) to simplify \(t(x) = 2x + 1\) for \(x eq 1\). The graph is a line with a hole at \((1, 3)\).
06

Analyze and graph u(x)

For the function \(u(x) = \frac{x-2}{x^2 - 2x}\), factor the denominator as \(x(x-2)\). Simplify to \(u(x) = \frac{1}{x}\) for \(x eq 0\) and \(x eq 2\). Graphically, this is the hyperbola \(y = \frac{1}{x}\) with vertical asymptote at \(x = 0\), excluding points \((2,\frac{1}{2})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring polynomials is a crucial step in simplifying rational functions and identifying other characteristics of their graphs. When you encounter a polynomial, the first task is to look for common factors among its terms. For example, consider the polynomial expression \(3x^2 - 3x - 6\). Here, the common factor is \(3\). By factoring this number out, the expression reduces to \(3(x^2 - x - 2)\).

Once the common factor is extracted, further factor the polynomial \(x^2 - x - 2\). This involves finding two numbers whose product is \(-2\) and whose sum is \(-1\). The appropriate choice for these numbers is \(-2\) and \(1\), which leads to the factorization \((x - 2)(x + 1)\).
  • Extract any common numeric or variable factors.
  • Break down the resulting polynomial further into binomials, if possible.
  • Use techniques such as grouping or quadratic equivalents.
Factoring is not just an exercise in simplification—it reveals solutions and helps identify potential issues like undefined points or other characteristics in graphs.
Domain of a Function
The domain of a function is the set of all possible inputs (x-values) for the function that produce valid outputs. For rational functions, such as \(r(x) = \frac{3x^2 - 3x - 6}{x - 2}\), the domain excludes any value of \(x\) that makes the denominator zero, as division by zero is undefined.

In the case of \(r(x)\), the denominator \(x - 2\) means \(x = 2\) is excluded from the domain. Thus, the domain of \(r(x)\) is all real numbers except \(x = 2\). For graphing purposes, these excluded values can produce holes, and understanding them is crucial for constructing an accurate graph of the function.
  • Identify the values that make the denominator zero.
  • Exclude these values from the domain of the function.
  • Remember to adjust the graph accordingly to reflect these missing points.
The domain helps us understand the scope of the function and ensures that we are aware of any discontinuities to expect.
Graphing Functions
Graphing functions involves translating the mathematical expression of a function into visual form on a coordinate plane. For rational functions, this can involve identifying and plotting any simplified linear or nonlinear graphs, accounting for modifications due to excluded domains.

For example, if we simplify \(r(x) = \frac{3(x-2)(x+1)}{x-2}\) to \(3(x+1)\), it initially appears as the line \(y = 3x + 3\). But, since \(x = 2\) is not in the domain, the graph will have a disruption at \((2, 9)\).
  • Identify the core graph structure after simplification.
  • Locate and mark any holes or asymptotes on the graph.
  • Ensure to indicate and adjust lines based on these disrupted points.
Graphing is about capturing both the general shape and specific peculiarities, like missing points or extreme values, to convey the behavior of the function comprehensively.
Holes in Graphs
Holes occur in graphs of rational functions at the x-values that are excluded from the function's domain due to the zeroes in their denominators. Essentially, they are points where the function is not defined, but near which the graph behaves predictably.

Using \(r(x)\) once simplified to \(3(x+1)\), and excluding \(x = 2\), means the point \((2, 9)\) is not on the graph of the simplified linear equation. However, as \(x\) approaches \(2\) from either direction, the y-values approach \(9\). Therefore, a hole is depicted by a small open circle on the graph to show the missing point.
  • Identify the point(s) where the original rational function is undefined.
  • Mark these points on the graph with open circles to indicate missing data.
  • Ensure clarity by showing how close the function value gets at nearby points.
Holes give a gentle nudge that simplicity may hide omissions, urging you to remember that the algebraic process could simplify the appearance but lose the complete story.

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Most popular questions from this chapter

Use a graphing device to find all real solutions of the equation, rounded to two decimal places. $$2 x^{3}-8 x^{2}+9 x-9=0$$

The quadratic formula can be used to solve any quadratic (or second-degree) equation. You might have wondered whether similar formulas exist for cubic (thirddegree), quartic (fourth-degree), and higher-degree equations. For the depressed cubic \(x^{3}+p x+q=0,\) Cardano (page 274) found the following formula for one solution: $$x=\sqrt[3]{\frac{-q}{2}+\sqrt{\frac{q^{2}}{4}+\frac{p^{3}}{27}}}+\sqrt[3]{\frac{-q}{2}-\sqrt{\frac{q^{2}}{4}+\frac{p^{3}}{27}}}$$ A formula for quartic equations was discovered by the Italian mathematician Ferrari in \(1540 .\) In 1824 the Norwegian mathematician Niels Henrik Abel proved that it is impossible to write a quintic formula, that is, a formula for fifth-degree equations. Finally, Galois (page 254) gave a criterion for determining which equations can be solved by a formula involving radicals. Use the cubic formula to find a solution for the following equations. Then solve the equations using the methods you learned in this section. Which method is easier? (a) \(x^{3}-3 x+2=0\) (b) \(x^{3}-27 x-54=0\) (c) \(x^{3}+3 x+4=0\)

Find all solutions of the equation and express them in the form \(a+b i\) $$x^{2}-3 x+3=0$$

Find the intercepts and asymptotes, and then sketch a graph of the rational function and state the domain and range. Use a graphing device to confirm your answer. $$r(x)=\frac{x^{2}+3 x}{x^{2}-x-6}$$

Give examples of polynomials that have the following properties, or explain why it is impossible to find such a polynomial. (a) A polynomial of degree 3 that has no real zeros (b) A polynomial of degree 4 that has no real zeros (c) A polynomial of degree 3 that has three real zeros, only one of which is rational (d) A polynomial of degree 4 that has four real zeros, none of which is rational What must be true about the degree of a polynomial with integer coefficients if it has no real zeros?

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