Chapter 3: Problem 39
Use synthetic division and the Remainder Theorem to evaluate \(P(c)\). $$P(x)=4 x^{2}+12 x+5, \quad c=-1$$
Short Answer
Expert verified
The value of \(P(-1)\) is -3.
Step by step solution
01
Setup the Synthetic Division
Write down the coefficients of the polynomial \(P(x) = 4x^2 + 12x + 5\) in order: 4, 12, 5. The value of \(c\) given is -1, which will be used in the synthetic division process below the division line.
02
Perform Synthetic Division
- Draw a horizontal line and place the coefficients 4, 12, and 5 in a row.- Write the value of \(c = -1\) to the left.- Bring down the first coefficient (4) directly under the line.- Multiply this 4 by \(c = -1\) and write the result under the second coefficient (12), then add them to get the new number below (which is 8).- Repeat the multiplication by \(-1\) with the new number (8), place the result under the third coefficient (5), add them to get the final remainder, which is your answer (this case, -3).
03
Remainder Interpretation
In synthetic division, the last number you derived, in this case, -3, represents the remainder of the division. According to the Remainder Theorem, this remainder is equal to \(P(-1)\). Hence, \(P(-1) = -3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Remainder Theorem
The Remainder Theorem is a handy tool when dealing with polynomials. It tells us that if a polynomial \( P(x) \) is divided by \( x-c \), then the remainder of this division is the same as evaluating the polynomial at \( c \). In simpler terms, if you plug \( c \) into the polynomial, the result is the remainder you'd get from division. For our exercise, after performing synthetic division on \( P(x) = 4x^2 + 12x + 5 \) using \( c = -1 \), we found the remainder to be -3. Therefore, by the Remainder Theorem, \( P(-1) = -3 \). This concept helps us quickly find specific values of a polynomial without needing to do full polynomial division.
Polynomial Evaluation
Evaluating a polynomial simply means substituting a given value for the variable in the polynomial and simplifying. For instance, if we want to determine \( P(-1) \) in the polynomial \( P(x) = 4x^2 + 12x + 5 \), we substitute \(-1\) in place of \(x\):
\( P(-1) = 4(-1)^2 + 12(-1) + 5 \)
- First, calculate \((-1)^2\) which is 1.
- Then, proceed to find \( 4 \times 1 + 12 \times (-1) + 5 \) .
- This simplifies to \( 4 - 12 + 5 \).
Finally, \( P(-1) = -3 \), corroborating the result obtained by synthetic division and the Remainder Theorem. Using synthetic division streamlines this process by reducing multiple steps into a quicker algorithm.
\( P(-1) = 4(-1)^2 + 12(-1) + 5 \)
- First, calculate \((-1)^2\) which is 1.
- Then, proceed to find \( 4 \times 1 + 12 \times (-1) + 5 \) .
- This simplifies to \( 4 - 12 + 5 \).
Finally, \( P(-1) = -3 \), corroborating the result obtained by synthetic division and the Remainder Theorem. Using synthetic division streamlines this process by reducing multiple steps into a quicker algorithm.
Synthetic Division Steps
Synthetic division is a shortcut method for dividing polynomials that is easier and faster than long division under certain circumstances. Here are the steps to follow:
- Identify the coefficients of your polynomial. For instance, in \( P(x)=4x^2+12x+5 \) the coefficients are 4, 12, and 5.
- Write down these coefficients in a sequence.
- Next to them, place the value of \( c \) from \( x-c \). Here, this is \(-1\).
- Start by bringing down the leading coefficient (4) to below the line.
- Multiply this by \(-1\) to get -4 and add it to the next coefficient (12), which gives you 8.
- Repeat the multiplication with 8 and \(-1\), to get -8. Add this to the next coefficient (5) to yield -3.
Polynomial Coefficients
Polynomial coefficients are the numerical factors of each term in a polynomial. These integers or real numbers form the backbone of polynomial expressions by accompanying each degree of the variable. In our polynomial \( P(x) = 4x^2 + 12x + 5 \), the coefficients are:
- 4: The coefficient of \(x^2\)
- 12: The coefficient of \(x\)
- 5: The constant term (also interpretable as the coefficient of \(x^0\))