Chapter 3: Problem 37
Find the maximum or minimum value of the function. $$f(s)=s^{2}-1.2 s+16$$
Short Answer
Expert verified
The minimum value is 15.64 at \( s = 0.6 \).
Step by step solution
01
Identify the Type of Quadratic Function
The given function is a quadratic function of the form \( f(s) = as^2 + bs + c \) where \( a = 1 \), \( b = -1.2 \), and \( c = 16 \). Since \( a > 0 \), the parabola opens upwards, indicating a minimum value.
02
Find the Vertex of the Parabola
The vertex form of a quadratic function \( f(s) = as^2 + bs + c \) can give us the minimum or maximum point. The s-coordinate of the vertex is calculated using \( s = -\frac{b}{2a} \). Substituting the values, we have \( s = -\frac{-1.2}{2 \times 1} = 0.6 \).
03
Calculate the Minimum Value of the Function at the Vertex
Once we have the s-coordinate of the vertex \( s = 0.6 \), we substitute it back into the function to find the minimum value. So, \( f(0.6) = (0.6)^2 - 1.2 \times 0.6 + 16 = 0.36 - 0.72 + 16 = 15.64 \).
04
Conclusion: State the Minimum Value
The minimum value of the function \( f(s) = s^2 - 1.2s + 16 \) is 15.64, which occurs at \( s = 0.6 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a crucial concept in understanding quadratic functions. For a quadratic equation of the form \( f(x) = ax^2 + bx + c \), the vertex represents the highest or lowest point of the graph. This is because a parabola is symmetrical around its vertex.
To find the vertex, we use the formula for the vertex's x-coordinate, which is \( x = -\frac{b}{2a} \). For example, in the quadratic function \( f(s) = s^2 - 1.2s + 16 \), we identify \( a = 1 \) and \( b = -1.2 \). Plugging these values into the formula, we get
\[ s = -\frac{-1.2}{2 \times 1} = 0.6 \]
This means the vertex occurs at \( s = 0.6 \).
The vertex gives us a crucial point on the graph:
To find the vertex, we use the formula for the vertex's x-coordinate, which is \( x = -\frac{b}{2a} \). For example, in the quadratic function \( f(s) = s^2 - 1.2s + 16 \), we identify \( a = 1 \) and \( b = -1.2 \). Plugging these values into the formula, we get
\[ s = -\frac{-1.2}{2 \times 1} = 0.6 \]
This means the vertex occurs at \( s = 0.6 \).
The vertex gives us a crucial point on the graph:
- It helps determine the direction of the parabola (whether it opens up or down).
- It provides the minimum or maximum value.
- It serves as a point of symmetry for the parabola.
Minimum Value
Quadratic functions can have either a minimum or maximum value depending on the orientation of the parabola. If the parabola opens upwards, the vertex provides a minimum point. Conversely, if the parabola opens downwards, the vertex provides a maximum point.
In our function \( f(s) = s^2 - 1.2s + 16 \), since \( a = 1 \) is positive, the parabola opens upwards, indicating a minimum value at its vertex.
To find this minimum value, we substitute the s-coordinate of the vertex back into the function:
\[ f(0.6) = (0.6)^2 - 1.2 \times 0.6 + 16 = 0.36 - 0.72 + 16 \]
Which simplifies to 15.64.
Thus, the minimum value is:
In our function \( f(s) = s^2 - 1.2s + 16 \), since \( a = 1 \) is positive, the parabola opens upwards, indicating a minimum value at its vertex.
To find this minimum value, we substitute the s-coordinate of the vertex back into the function:
\[ f(0.6) = (0.6)^2 - 1.2 \times 0.6 + 16 = 0.36 - 0.72 + 16 \]
Which simplifies to 15.64.
Thus, the minimum value is:
- Determined by evaluating the function at the vertex.
- Provides the lowest point on the graph for a parabola that opens upward.
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations of the form \( ax^2 + bx + c = 0 \). While it is primarily used for finding the roots of a quadratic equation, it indirectly relates to finding attributes such as the vertex and the minimum or maximum value.
The quadratic formula is expressed as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
While solving for the vertex or the extremum of the quadratic function, we modify this formula to just \( x = -\frac{b}{2a} \), focusing only on the part without the square root.
Understanding how the quadratic formula connects different aspects of a quadratic equation can:
The quadratic formula is expressed as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
While solving for the vertex or the extremum of the quadratic function, we modify this formula to just \( x = -\frac{b}{2a} \), focusing only on the part without the square root.
Understanding how the quadratic formula connects different aspects of a quadratic equation can:
- Help in finding key points like roots and vertex.
- Offer insights into the nature and shape of the parabola.
- Provide a comprehensive toolkit for analyzing quadratic functions.