/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Evaluate the expression and writ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the expression and write the result in the form \(a+b i\) $$i^{100}$$

Short Answer

Expert verified
The expression \(i^{100}\) evaluates to \(1+0i\).

Step by step solution

01

Understanding the imaginary unit

The imaginary unit is represented by the symbol \(i\), which is defined as \(\sqrt{-1}\). The powers of \(i\) cycle in a predictable pattern: \(i^1 = i\), \(i^2 = -1\), \(i^3 = -i\), and \(i^4 = 1\). Then the cycle repeats again from \(i^5 = i\).
02

Determine the pattern cycle length

Since \(i^1 = i\), \(i^2 = -1\), \(i^3 = -i\), and \(i^4 = 1\), we see the powers of \(i\) repeat every four terms. This is an important observation for simplifying higher powers of \(i\).
03

Calculate the remainder of the exponent divided by the cycle length

To find \(i^{100}\), we need to find the remainder of 100 when divided by 4 (the length of the pattern cycle). Performing the division, we find \(100 \div 4 = 25\) with a remainder of 0.
04

Use the cycle pattern to simplify

Since the remainder is 0, \(i^{100}\) corresponds to \(i^4\), which equals 1. Thus, using the cycle pattern of \(i\), \(i^{100} = 1\).
05

Express the result in the form \(a + bi\)

The result \(1\) can be expressed in the form \(a + bi\) as \(1 + 0i\) where \(a = 1\) and \(b = 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Unit
The imaginary unit, denoted by the symbol \(i\), is a fundamental concept in the field of complex numbers. It is defined as \(i = \sqrt{-1}\). This is a crucial definition because the square root of a negative number isn't a real number, so \(i\) serves as a bridge to understand complex numbers.
The introduction of \(i\) allows mathematicians to solve equations that were previously impossible to solve within the realm of real numbers alone. It forms the simplest type of complex number, which can be expressed as \(0 + 1i\).
The powers of \(i\) cycle through a pattern because each multiplication by \(i\) can be understood in terms of rotation in the complex plane.
Understanding \(i\) is key to unlocking the larger world of complex numbers and provides a new way to express and solve problems in mathematics.
Powers of i
When dealing with powers of the imaginary unit \(i\), a key point to remember is that it follows a predictable four-cycle pattern. This makes calculations straightforward.
Here's the cyclical pattern of \(i\):
  • \(i^1 = i\)
  • \(i^2 = -1\)
  • \(i^3 = -i\)
  • \(i^4 = 1\)
After \(i^4\), the powers repeat starting again from \(i^1\) as the cycle repeats every four steps.
To find higher powers like \(i^{100}\), you simply determine how far 100 goes into the cycle. Since 100 divided by 4 leaves a remainder of 0, \(i^{100}\) corresponds to \(i^4\) in the pattern, which is 1. This simplification process makes calculating powers of \(i\) quick and efficient.
Complex Numbers in Standard Form
Complex numbers are expressed in their standard form as \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit. This structure combines both real and imaginary parts.
For example, a number like \(1 + 0i\) is a complex number, where \(1\) is the real part and \(0i\) is the imaginary part.
Standard form is useful because it visually separates the real component from the imaginary component, making complex numbers simpler to work with.
In the exercise \(i^{100}\), it reduced down to \(1 + 0i\) due to the properties of the powers of \(i\). Expressing it in this form helps to easily combine and compare complex numbers, contributing to the versatility and power of complex numbers in mathematics.

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Most popular questions from this chapter

Find the intercepts and asymptotes, and then sketch a graph of the rational function and state the domain and range. Use a graphing device to confirm your answer. $$t(x)=\frac{x-2}{x^{2}-4 x}$$

Find all solutions of the equation and express them in the form \(a+b i\) $$9 x^{2}+4=0$$

The quadratic formula can be used to solve any quadratic (or second-degree) equation. You might have wondered whether similar formulas exist for cubic (thirddegree), quartic (fourth-degree), and higher-degree equations. For the depressed cubic \(x^{3}+p x+q=0,\) Cardano (page 274) found the following formula for one solution: $$x=\sqrt[3]{\frac{-q}{2}+\sqrt{\frac{q^{2}}{4}+\frac{p^{3}}{27}}}+\sqrt[3]{\frac{-q}{2}-\sqrt{\frac{q^{2}}{4}+\frac{p^{3}}{27}}}$$ A formula for quartic equations was discovered by the Italian mathematician Ferrari in \(1540 .\) In 1824 the Norwegian mathematician Niels Henrik Abel proved that it is impossible to write a quintic formula, that is, a formula for fifth-degree equations. Finally, Galois (page 254) gave a criterion for determining which equations can be solved by a formula involving radicals. Use the cubic formula to find a solution for the following equations. Then solve the equations using the methods you learned in this section. Which method is easier? (a) \(x^{3}-3 x+2=0\) (b) \(x^{3}-27 x-54=0\) (c) \(x^{3}+3 x+4=0\)

Recall that the symbol \(\bar{z}\) represents the complex conjugate of \(z .\) If \(z=a+b i\) and \(w=c+d i,\) prove each statement. \(z+\bar{z}\) is a real number.

Find the intercepts and asymptotes, and then sketch a graph of the rational function and state the domain and range. Use a graphing device to confirm your answer. $$r(x)=\frac{x^{2}+3 x}{x^{2}-x-6}$$

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