Chapter 3: Problem 23
A quadratic function is given. (a) Express the quadratic function in standard form. (b) Sketch its graph. (c) Find its maximum or minimum value. $$f(x)=x^{2}+2 x-1$$
Short Answer
Expert verified
The function is in standard form. The parabola opens upwards with a minimum value of -2 at x = -1.
Step by step solution
01
Identify the quadratic function
The given quadratic function is \( f(x) = x^2 + 2x - 1 \). This function is already presented in the standard form, which is \( ax^2 + bx + c \), where \( a = 1 \), \( b = 2 \), and \( c = -1 \).
02
Determine the direction of the parabola
In the quadratic function \( f(x) = ax^2 + bx + c \), the coefficient \( a \) determines the direction of the parabola. If \( a > 0 \), the parabola opens upwards, and if \( a < 0 \), it opens downwards. Here, \( a = 1 \), so the parabola opens upwards.
03
Find the vertex of the parabola
The vertex of a parabola given by \( f(x) = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Substituting \( a = 1 \) and \( b = 2 \), we get \( x = -\frac{2}{2 \times 1} = -1 \). Substitute \( x = -1 \) back into the function to find \( f(-1) = (-1)^2 + 2(-1) - 1 = -2 \). Thus, the vertex is \( (-1, -2) \).
04
Sketch the graph
The graph of \( f(x) = x^2 + 2x - 1 \) is a parabola opening upwards with a vertex at \( (-1, -2) \). The y-intercept occurs when \( x = 0 \): \( f(0) = 0^2 + 2(0) - 1 = -1 \). These points help in sketching the graph.
05
Determine the maximum or minimum value
Since the parabola opens upwards, the vertex is at a minimum point. The minimum value of the function is the y-coordinate of the vertex, which is \(-2\). This minimum value occurs at \( x = -1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a symmetric curve on a graph. It represents quadratic functions, which are equations of the form \( ax^2 + bx + c \). Two types of parabolas exist: those that open upwards and those that open downwards, depending on the coefficient "\( a \)".
When \( a > 0 \), like in the function \( f(x) = x^2 + 2x - 1 \), the parabola opens upwards, resembling a "U" shape.
Conversely, if \( a < 0 \), the parabola opens downwards, forming an upside-down "U".
When \( a > 0 \), like in the function \( f(x) = x^2 + 2x - 1 \), the parabola opens upwards, resembling a "U" shape.
Conversely, if \( a < 0 \), the parabola opens downwards, forming an upside-down "U".
- A U-shaped parabola has a minimum point (the lowest point).
- An upside-down U-shaped parabola has a maximum point (the highest point).
Vertex of a Parabola
The vertex of a parabola is its highest or lowest point. For a quadratic function in the form \( f(x) = ax^2 + bx + c \), the vertex can be found using the formula \( x = -\frac{b}{2a} \).
Once you calculate the x-coordinate of the vertex, substitute it back into the function to find the y-coordinate.
In this exercise, with the function \( f(x) = x^2 + 2x - 1 \), the vertex is determined as follows:
Once you calculate the x-coordinate of the vertex, substitute it back into the function to find the y-coordinate.
In this exercise, with the function \( f(x) = x^2 + 2x - 1 \), the vertex is determined as follows:
- Calculate the x-coordinate: \( x = -\frac{2}{2 \cdot 1} = -1 \).
- Find the y-coordinate: \( f(-1) = (-1)^2 + 2(-1) - 1 = -2 \).
Standard Form of a Quadratic Function
Quadratic functions often begin in the standard form, which is expressed as \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. This form is pivotal because it helps identify the basic properties of the quadratic function, such as the parabola's direction (through the value of \( a \)) and the vertex.
For the given function \( f(x) = x^2 + 2x - 1 \):
For the given function \( f(x) = x^2 + 2x - 1 \):
- Coefficient \( a = 1 \), making the parabola open upwards.
- Coefficient \( b = 2 \), which is part of the calculation for the vertex's position \((-\frac{b}{2a})\).
- Constant \( c = -1 \), contributes to determining the y-intercept where the graph crosses the y-axis.