Chapter 2: Problem 77
Find a function whose graph is the given curve. The top half of the circle \(x^{2}+y^{2}=9\)
Short Answer
Expert verified
The function is \(y = \sqrt{9 - x^2}\).
Step by step solution
01
Understand the Given Circle Equation
The equation given is \(x^2 + y^2 = 9\). This equation represents a circle centered at the origin (0,0) with a radius of 3 because \(9 = 3^2\).
02
Equation Rearrangement for y
To find a function for the top half of this circle, solve the circle equation for \(y\). Start with the equation \(x^2 + y^2 = 9\) and rearrange it to solve for \(y^2\): \( y^2 = 9 - x^2 \).
03
Taking the Square Root
Take the square root of both sides to solve for \(y\). Remember, taking the square root gives two potential solutions: \(y = \sqrt{9 - x^2}\) and \(y = -\sqrt{9 - x^2}\).
04
Selecting the Top Half Function
For the top half of the circle, choose the positive part of the square root, \(y = \sqrt{9 - x^2}\), because this represents the upper portion of the circle on the y-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Circle Equations
Circles are fundamental geometric shapes that are perfectly round and symmetrical. A circle equation helps describe the location, size, and position of these shapes in coordinate geometry. The standard form of a circle's equation is:
\[ x^2 + y^2 = r^2 \]
In this equation,
\[ x^2 + y^2 = r^2 \]
In this equation,
- \((x, y)\) represents any point on the circle,
- \((0, 0)\) is the center of the circle for this standard equation,
- and \(r\) is the radius of the circle.
- The center is identified by its coordinates (in our case, the origin (0,0)).
- The radius \(r\) is the positive square root of the number on the right-hand side of the equation.
- a center at the origin,
- and a radius of 3 (since \(3^2 = 9\)).
Graphing Functions
Graphing functions, especially when dealing with circle equations, highlights certain parts of these graph's characteristics. The goal here is to convert an equation into a visual representation.
When targeting specific sections, such as the top half of a circle, we need to formulate a function that describes only that part.
To graph a function representing part of a circle, we first isolate \(y\) in the circle's equation. In our case: Â
For the top half, select:
When targeting specific sections, such as the top half of a circle, we need to formulate a function that describes only that part.
To graph a function representing part of a circle, we first isolate \(y\) in the circle's equation. In our case: Â
- Start with \(x^2 + y^2 = 9\).
- Solve for \(y^2\) to get \(y^2 = 9 - x^2\).
- Then take the square root of both sides, ending with \(y = \pm \sqrt{9 - x^2}\).
For the top half, select:
- \(y = \sqrt{9 - x^2}\).
Upper Semicircle
The term "upper semicircle" refers to the top half of a full circle. When a complete circle is bisected horizontally, the upper semicircle contains all the points of the circle with non-negative y-coordinates.
In the context of turning circle equations into functions, the upper semicircle is extracted by:
In the context of turning circle equations into functions, the upper semicircle is extracted by:
- Choosing the positive root when solving the circle equation for \(y\).
- Expressing this as a function: \(y = \sqrt{9 - x^2}\).
- The domain of this function is from \(-3\) to \(3\), because beyond these x-values, the square root would yield a negative, non-real solution.
- This domain corresponds to the circle's diameter along the x-axis.