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The given function is not one-to-one. Restrict its domain so that the resulting function is one-to-one. Find the inverse of the function with the restricted domain. (There is more than one correct answer.) $$f(x)=4-x^{2}$$

Short Answer

Expert verified
Restrict the domain to \(x \geq 0\). The inverse is \(f^{-1}(y) = \sqrt{4 - y}\).

Step by step solution

01

Understand the Problem

We are given the function \(f(x) = 4 - x^2\), which is a quadratic function. We need to restrict its domain to make it one-to-one and then find its inverse.
02

Identify a Suitable Domain

A quadratic function is symmetrical about its vertex. The vertex of this parabola is at \(x = 0\). To make the function one-to-one, we can restrict the domain to either the left or the right of the vertex. For instance, we could choose \(x \geq 0\) or \(x \leq 0\). Both are valid domain restrictions.
03

Restrict the Domain

Let's choose the domain \(x \geq 0\). With this restriction, the function \(f(x) = 4 - x^2\) becomes one-to-one, because it is either strictly increasing or strictly decreasing in this range.
04

Express the Function with Restricted Domain

With the restriction \(x \geq 0\), the function is now \(f(x) = 4 - x^2 \) for \( x \geq 0\).
05

Find the Inverse of the Function

We start with \(y = 4 - x^2\). First, solve for \(x\): \(y = 4 - x^2\) becomes \(x^2 = 4 - y\). Rewriting gives \(x = \sqrt{4 - y}\). Since we chose \(x \geq 0\), the inverse function is \(f^{-1}(y) = \sqrt{4 - y}\).
06

Validate the Inverse Function

Check that \(f(f^{-1}(y)) = y\) and \(f^{-1}(f(x)) = x\) hold true for the new restricted domain. Substituting \(f^{-1}(y)\) into the original function will yield \(y\) if it's correct, and vice versa with \(f(x)\) into the inverse function yielding \(x\). These equations should satisfy the condition of inverse functions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Function
An inverse function essentially reverses the effect of the original function. The objective of finding an inverse is to determine how you can undo the operations of a function to return to the input from a given output. In mathematical terms, if you have a function represented as \( f \), its inverse, denoted as \( f^{-1} \), will satisfy the following properties:
  • For every \( x \) in the domain of \( f \), \( f^{-1}(f(x)) = x \).
  • For every \( y \) in the range of \( f \), \( f(f^{-1}(y)) = y \).
These conditions confirm that \( f \) and \( f^{-1} \) undo each other.
To find the inverse of a function like \( f(x) = 4 - x^{2} \) with a restricted domain, follow these steps:
  • Replace \( f(x) \) with \( y \), giving you \( y = 4 - x^2 \).
  • Solve for \( x \) in terms of \( y \). This gives you the inverse relation.
  • If the function is restricted with \( x \geq 0 \), the inverse ensures only the positive root is considered, \( x = \sqrt{4 - y} \).
Domain Restriction
A function is one-to-one if each output is connected to exactly one input. For functions like quadratic functions, which are not naturally one-to-one due to their parabolic shape with a symmetrical vertex, domain restriction is used. By restricting the domain, you adjust the range of inputs so that the function becomes one-to-one, and thus an inverse can exist.
For the quadratic function \( f(x) = 4 - x^2 \), the symmetry around its vertex \( x = 0 \) means the function overlaps in its outputs for inputs on opposite sides of the vertex.
To solve this, restrict the domain:
  • Choose either \( x \geq 0 \) or \( x \leq 0 \) as they do not overlap back on themselves.
  • A restricted domain like \( x \geq 0 \) ensures the function continues smoothly without duplication or repeat values for outputs.
This restriction effectively transforms the original function to one-to-one, paving the way for calculating a valid inverse.
Quadratic Function
A quadratic function is represented in the form of \( ax^2 + bx + c \) and illustrated graphically as a parabola. It's essential to grasp a few core aspects of this function:
  • Vertex: This is the peak or the lowest point of a parabola, where it changes direction.
  • Symmetry: Quadratics are symmetric around the vertical line passing through the vertex.
  • Shape and Direction: Depending on the parabola's orientation, it can either open upwards (like a smile) or downwards (like a frown). The function here, \( f(x) = 4 - x^2 \), opens downward.
Due to its shape, quadratic functions are not one-to-one naturally because the same output can relate to different inputs.
Manipulating a quadratic function's domain allows symmetry cutting and thus opens avenues to define an inverse.

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