Chapter 2: Problem 15
Explain how the graph of \(g\) is obtained from the graph of \(f\). (a) \(f(x)=x^{2}, \quad g(x)=(x+2)^{2}\) (b) \(f(x)=x^{2}, \quad g(x)=x^{2}+2\)
Short Answer
Expert verified
For (a) shift \(f(x)\) left by 2; for (b) shift \(f(x)\) up by 2.
Step by step solution
01
Understanding the Base Function for Part (a)
The base function for both exercises is the same: \( f(x)=x^2 \), which is a standard parabola with its vertex at the origin (0,0) and opens upwards.
02
Identifying the Transformation for Part (a)
The function \( g(x) = (x+2)^2 \) represents a horizontal shift of the base function. The \((x+2)\) shifts the graph of \( f(x) \) by 2 units to the left. This is because adding to \(x\) in \((x+2)^2\) affects the horizontal position.
03
Transforming the Graph for Part (a)
Take the graph of \( f(x) = x^2 \) and move every point 2 units to the left to get \( g(x) = (x+2)^2 \) with the vertex at (-2, 0).
04
Understanding the Base Function for Part (b)
Again, the base function is \( f(x)=x^2 \), a parabola with vertex at the origin that opens upwards.
05
Identifying the Transformation for Part (b)
The function \( g(x) = x^2 + 2 \) represents a vertical shift of the base function. The added 2 means we shift the entire graph of \( f(x) \) upwards by 2 units.
06
Transforming the Graph for Part (b)
Move the entire graph of \( f(x) = x^2 \) vertically upward by 2 units to form \( g(x) = x^2 + 2 \) with the vertex at (0, 2).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Horizontal Shifts
A horizontal shift in a graph involves moving the entire function left or right along the x-axis. When dealing with horizontal shifts in terms of quadratic functions, such as the function given by \[ g(x) = (x+2)^2 \] we find that the shift depends on the term inside the parentheses of the function form \[ (x + h)^2 \] where \( h \) affects the placement. In this case, \( h = 2 \) indicating a shift but in the opposite direction - here it's 2 units to the left. This is sometimes counterintuitive because a "+" inside the bracket (\(+2\)) results in a leftward shift. This concept emerges from solving for the vertex of the parabola, which moves from the origin, \( (0, 0) \), to \( (-2, 0) \).
Utilize this transformation rule to accurately move graphs by understanding that:
Utilize this transformation rule to accurately move graphs by understanding that:
- Adding inside the function \((x + h)\) results in a shift left by \( h \).
- Subtracting \((x - h)\) results in a shift right by \( h \).
Vertical Shifts
Vertical shifts are simpler to visualize as they involve moving the whole graph up or down along the y-axis without changing its shape. Consider the quadratic function example, where we transform \[ g(x) = x^2 + 2 \].
This involves taking the base function \[ f(x) = x^2 \] and adding a constant, \( k = 2 \), resulting in a shift upwards.
This will elevate the entire parabola by \( 2 \) units vertically, but retains the same form and opening direction.
Remember these essentials for vertical shifts:
This involves taking the base function \[ f(x) = x^2 \] and adding a constant, \( k = 2 \), resulting in a shift upwards.
This will elevate the entire parabola by \( 2 \) units vertically, but retains the same form and opening direction.
Remember these essentials for vertical shifts:
- Adding \(+ k\) moves the function upwards by \( k \) units.
- Subtracting \(- k\) moves the function downwards by \( k \) units.
Quadratic Functions
Quadratic functions are fundamental in algebra and are characterized by their U-shaped graphs known as parabolas. The standard form is \[ f(x) = ax^2 + bx + c \].
In these exercises, we specifically dealt with the simplest form \[ f(x) = x^2 \], where \( a = 1 \), \( b = 0 \), and \( c = 0 \). This basic quadratic function results in a parabola with its vertex at the origin and opening upwards.
Some key traits of quadratic functions to note:
In these exercises, we specifically dealt with the simplest form \[ f(x) = x^2 \], where \( a = 1 \), \( b = 0 \), and \( c = 0 \). This basic quadratic function results in a parabola with its vertex at the origin and opening upwards.
Some key traits of quadratic functions to note:
- The coefficient \( a \) determines if the parabola opens upwards (if \( a > 0 \)) or downwards (if \( a < 0 \)).
- The vertex form showing \[ (x-h)^2 \] helps in easily identifying shifts and transformations.
- Quadratics often represent situations where there is acceleration, such as projectile motion, making them practically applicable.
Parabolas
Parabolas are a distinct shape formed by graphs of quadratic functions, \[ y = ax^2 + bx + c \], and are recognized for their symmetrical, curved form. In the standard form where \( f(x) = x^2 \), the parabola has its vertex or the "tip" at the origin, \( (0, 0) \), and it opens upwards, creating a symmetric curve about the vertical axis.
Here are some essential features of parabolas:
Here are some essential features of parabolas:
- **Vertex**: The highest or lowest point of a parabola. Examples are \( (0, 0) \) for \( x^2 \) and \( (-2, 0) \) for \( (x+2)^2 \).
- **Axis of Symmetry**: A vertical line that divides the parabola into mirror images. For \( x^2 \), this is the y-axis, \( x = 0 \).
- **Direction**: Determined by the sign of \( a \). In a positive parabola like \( x^2 \), it opens upwards.