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Find the domain of the function. $$k(x)=\frac{\sqrt{x+3}}{x-1}$$

Short Answer

Expert verified
The domain of \( k(x) \) is \([-3, 1) \cup (1, \infty)\)."

Step by step solution

01

Define the Domain for the Square Root

The function involves a square root, so we must ensure that the expression under the square root is non-negative. For the function \( k(x) = \frac{\sqrt{x+3}}{x-1} \), the expression inside the square root is \( x+3 \). We set \( x+3 \geq 0 \), which simplifies to \( x \geq -3 \).
02

Define the Domain for the Denominator

The denominator of the fractional part must not be zero because division by zero is undefined. Here, the denominator is \( x-1 \). Therefore, we set \( x-1 eq 0 \), which simplifies to \( x eq 1 \).
03

Combine the Domain Conditions

From Step 1, we have \( x \geq -3 \), and from Step 2, we have \( x eq 1 \). To find the domain, combine these conditions. The domain is all \( x \) such that \( x \geq -3 \) and \( x eq 1 \). This can be expressed in interval notation as \([-3, 1) \cup (1, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Square Root Function
The square root function is a fundamental concept that appears frequently in various mathematical contexts. It is represented as \( \sqrt{x} \), where \( x \) is the number or expression whose square root is to be taken. In this case, our focus is on the function \( k(x) = \frac{\sqrt{x+3}}{x-1} \).
The expression under the square root, \( x+3 \), must be non-negative to ensure that the square root is real and defined. This is because the square root of a negative number is not a real number. Hence, we set \( x+3 \geq 0 \).
After simplifying, this gives us \( x \geq -3 \). This inequality is one of the key considerations when finding the domain of the function, ensuring that all values of \( x \) meet this condition to make the square root function valid.
Undefined Division
In any mathematical expression involving division, as in our function \( k(x) = \frac{\sqrt{x+3}}{x-1} \), it's critical to remember that division by zero is undefined. This means that the denominator, which is \( x-1 \) in this case, should never be equal to zero. If it were, it would make the function undefined at that point.
To prevent undefined situations, we solve the equation \( x-1 = 0 \). Solving this, we find \( x = 1 \). Thus, \( x eq 1 \) for our function's domain.
This restriction is crucial because any value of \( x \) that makes the denominator zero must be excluded from the domain to maintain a valid and defined function.
Interval Notation
Interval notation is a concise way to describe the set of all numbers that meet certain conditions. After finding the conditions for the function \( k(x) = \frac{\sqrt{x+3}}{x-1} \), we can express its domain in interval notation.
From the previous sections, we determined:
  • \( x \geq -3 \) to ensure a defined square root function.
  • \( x eq 1 \) to avoid undefined division.
When combining these conditions, we include all values \( x \geq -3 \), except \( x = 1 \). Using interval notation, the domain is written as \([-3, 1) \cup (1, \infty)\). This representation uses brackets and parentheses to clearly indicate the intervals of valid \( x \) values, enhancing understanding of how the function behaves across its domain.

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Most popular questions from this chapter

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