Chapter 12: Problem 20
Evaluate the expression. $$\left(\begin{array}{c}10 \\\5\end{array}\right)$$
Short Answer
Expert verified
The value of \( \left(\begin{array}{c}10 \\ 5\end{array}\right) \) is 252.
Step by step solution
01
Understanding Combinations
The problem requires calculating the binomial coefficient, which counts the number of ways to choose a subset of 5 elements from a total of 10 elements without regard to the order of selection. This is denoted by \( \binom{10}{5} \).
02
Using the Formula
The binomial coefficient is calculated using the formula: \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \). Here, \( n = 10 \) and \( r = 5 \), so the expression becomes \( \binom{10}{5} = \frac{10!}{5!(10-5)!} \).
03
Calculating Factorials
First, calculate the necessary factorials. \( 10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \). For \( 5! \), it is \( 5 \times 4 \times 3 \times 2 \times 1 \) and for \( (10-5)! = 5! \), it is the same, so \( 5! = 120 \).
04
Simplifying the Expression
Plug the values back into the formula: \( \binom{10}{5} = \frac{10!}{5!5!} \). Simplifying, we have: \( \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1} = \frac{30240}{120} = 252 \).
05
Verification
Verify the calculation to ensure correctness. Multiply the terms in the numerator and divide by 120, confirming that \( \binom{10}{5} = 252 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorials
Factorials are a simple yet fundamental concept in mathematics, especially when dealing with permutations and combinations. A factorial of a non-negative integer n, denoted as \( n! \), is the product of all positive integers less than or equal to n. For instance, the factorial of 4 is computed as \( 4! = 4 \times 3 \times 2 \times 1 = 24 \). Factorials grow very quickly in value as the integer increases.
Key points about factorials include:
Key points about factorials include:
- 0! is defined to be 1.
- Factorials are used to measure the number of permutations of a set. For example, the number of ways to arrange 5 items is 5!, which equals 120.
- Factorials are essential in computing combinations and binomial coefficients.
Combinations
Combinations are a way to calculate how many different groups can be formed from a larger set, where order does not matter. This is different from permutations, where the sequence of elements does matter. If you have 10 different books and want to select 5 to take on a trip without caring about the order, combinations help you count the number of possible selections.
For example, with a set of five letters, {A, B, C, D, E}, choosing three letters out of these gives combinations like {A, B, C} and {C, D, E}, where each different grouping of three letters is distinct.
The formula to calculate a combination is \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where:
For example, with a set of five letters, {A, B, C, D, E}, choosing three letters out of these gives combinations like {A, B, C} and {C, D, E}, where each different grouping of three letters is distinct.
The formula to calculate a combination is \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where:
- \( n \) is the total number of items.
- \( r \) is the number of items to be chosen.
nCr Formula
The \( nCr \) formula is a notation used in mathematics for combinations, specifically referring to how many combinations of r items can be formed from a set of n items. It's expressed as \( \binom{n}{r} \), which we read as "n choose r." The formula for calculating this combination is:\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \]This formula underscores the idea that we're choosing r items from a collection of n items without regard to the order of the items. To break it down:
- The numerator, \( n! \), accounts for the permutations of n items.
- The denominator, \( r!(n-r)! \), adjusts for the permutations within the smaller group of chosen items \( r \) and the ignored items \( n-r \).