/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 (a) Find the eccentricity and id... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$r=\frac{6}{2+\sin \theta}$$

Short Answer

Expert verified
Eccentricity is 1, identifying the conic as a parabola.

Step by step solution

01

Identify the Conic Form

The given equation is in the form \( r = \frac{ed}{1 + e \sin \theta} \), where \( e \) is the eccentricity and \( d \) is a constant related to the directrix. By comparing, here \( ed = 6 \) and \( 1 + e = 2 \) (since the form shows \( 2 + \sin \theta \)).
02

Solve for Eccentricity

From the equation in Step 1, we have \( 1 + e = 2 \). Solving for \( e \), we find that \( e = 1 \).
03

Identify the Conic Type

An eccentricity \( e = 1 \) indicates that the conic section is a parabola. Parabolas have \( e = 1 \), ellipses have \( 0 < e < 1 \), and hyperbolas have \( e > 1 \).
04

Sketch the Conic

A parabola with the equation \( r = \frac{6}{2 + \sin \theta} \) means it opens around the focus described by changes in \( \theta \). To sketch, draw a rough parabola that opens upwards with its vertex at the pole.
05

Label the Vertices

For a parabola in polar coordinates centered at the pole, the vertex is at the origin, \((0,0)\), relative to the focus and the directrix identified from the form of the equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eccentricity
Eccentricity is a fundamental concept that helps us identify and classify conic sections. It is a simple number denoting how "stretched" a conic section is. The value of eccentricity, denoted as \( e \), varies for different conics:
  • If \( e = 0 \), the conic is a circle.
  • If \( 0 < e < 1 \), we have an ellipse.
  • If \( e = 1 \), the conic is a parabola.
  • If \( e > 1 \), the conic forms a hyperbola.
In this exercise, we determined that \( e = 1 \), which characterizes the conic as a parabola. Eccentricity is crucial because it not only tells us the type of conic but also guides us in sketching and understanding its properties better. Remember, the eccentricity gives you a snapshot comparison between different conics. Think of it as how much it deviates from being circular.
Polar Coordinates
Polar coordinates offer a unique way to describe the location of a point in a plane. Instead of using the traditional \((x, y)\) Cartesian coordinates, polar coordinates use a combination of distance \( r \) from a fixed point (called the pole, similar to the origin in Cartesian coordinates) and an angle \( \theta \), measured from a fixed direction (often the positive \( x \)-axis in Cartesian systems).
  • \( r \): Distance from the pole.
  • \( \theta \): Angle from the fixed direction.
In dealing with conics like parabolas, polar coordinates allow us to express equations conveniently, as seen in the polar equation \( r = \frac{6}{2 + \sin \theta} \). This approach often simplifies finding the nature and properties of the conic sections, such as the direction it opens towards and how it can be sketched. Polar coordinates can sometimes make complex equations look simpler by focusing on angles and distances directly.
Parabola
A parabola is a distinct conic section represented by a particular set of equations. When a parabola is expressed in polar coordinates, it offers a unique perspective that can be advantageous for understanding its geometry. The characteristic property of a parabola is that it has an eccentricity \( e = 1 \). This means it is neither closed like an ellipse nor open like a hyperbola, but perfectly arches between extremes.
  • Parabolas have a single vertex, which can be considered the "sharpest" point.
  • They are symmetric, meaning both halves mirror each other from the vertex.
In this problem, the parabola equation \( r = \frac{6}{2 + \sin \theta} \) opens upwards relative to its center. Such polar forms help clarify how the parabola will appear when sketched—the parabola stretches out from a point where \( \theta \) changes, creating its distinct shape. Understanding a parabola's polar form involves recognizing how it is defined by the angle \( \theta \) and how it revolves around the focus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is closest to the sun is called perihelion, and the point at which it is farthest is called aphelion. These points are the vertices of the orbit. The earth's distance from the sun is \(147,000,000 \mathrm{km}\) at perihelion and \(153,000,000 \mathrm{km}\) at aphelion. Find an equation for the earth's orbit. (Place the origin at the center of the orbit with the sun on the \(x\) -axis.) (IMAGE CANNOT COPY)

(a) Use the discriminant to identify the conic. (b) Confirm your answer by graphing the conic using a graphing device. $$2 x^{2}-4 x y+2 y^{2}-5 x-5=0$$

A polar equation of a conic is given. (a) Find the eccentricity and the directrix of the conic. (b) If this conic is rotated about the origin through the given angle \(\theta\), write the resulting equation. (c) Draw graphs of the original conic and the rotated conic on the same screen. $$r=\frac{9}{2+2 \cos \theta} ; \quad \theta=-\frac{5 \pi}{6}$$

Graph the conics \(r=e /(1-e \cos \theta)\) with \(e=0.4,0.6,0.8\) and 1.0 on a common screen. How does the value of \(e\) affect the shape of the curve?

The hyperbolas $$\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 \quad \text { and } \quad \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=-1$$ are said to be conjugate to each other. (a) Show that the hyperbolas \(x^{2}-4 y^{2}+16=0 \quad\) and \(\quad 4 y^{2}-x^{2}+16=0\) are conjugate to each other, and sketch their graphs on the same coordinate axes. (b) What do the hyperbolas of part (a) have in common? (c) Show that any pair of conjugate hyperbolas have the relationship you discovered in part (b).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.