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A polar equation of a conic is given. (a) Show that the conic is a hyperbola, and sketch its graph. (b) Find the vertices and directrix, and indicate them on the graph. (c) Find the center of the hyperbola, and sketch the asymptotes. $$r=\frac{6}{2+7 \cos \theta}$$

Short Answer

Expert verified
The conic is a hyperbola with eccentricity 3.5, vertices at \( (2/3, 0) \), and directrices at \( r = 2/3.5 \).

Step by step solution

01

Identify the Pole Equation

The given polar equation of the conic is \( r = \frac{6}{2 + 7\cos\theta} \). This is in the standard form of a conic: \( r = \frac{ed}{1 + e\cos\theta} \) or \( r = \frac{ed}{1 + e\sin\theta} \) for horizontal and vertical axes, respectively, where \( e \) is the eccentricity.
02

Determine Conic Type

For a conic determined by a polar equation, it is a hyperbola if the eccentricity \( e > 1 \), an ellipse if \( 0 < e < 1 \), and a parabola if \( e = 1 \). In our equation, comparing forms, \( ed = 6 \) and \( e = 7 \). Thus, solving \( e(2) = 7 \), we find \( e = 7/2 = 3.5 \), which is greater than 1, indicating a hyperbola.
03

Calculate Vertices and Directrix

For the hyperbola \( r = \frac{6}{2 + 7\cos\theta} \), the vertices occur where \( \theta = 0, \pi \) (the axis of symmetry is horizontal in polar form). The vertex closest to the pole when \( \theta = 0 \) is given by \( r = \frac{6}{2 + 7} = \frac{6}{9} = \frac{2}{3} \). The directrix is the line perpendicular to the axis of symmetry at distance \( \frac{d}{e} = \frac{2}{3.5} \) from the origin, both sides.
04

Sketch the Hyperbola

To sketch the hyperbola, plot points for several values of \( \theta \), especially those for \( \theta = 0, \pi/2, \pi, 3\pi/2 \). The graph is hyperbolic, notably expanding outwards around the vertex along its axis.
05

Find the Center and Asymptotes

The center of the hyperbola in polar coordinates is located along the line of symmetry at \( r = \frac{3}{2} \), for consistency along the axis. The line asymptotes are present around a hyperbola within Cartesian transformations, but in polar terms, these are implied by the behavior as \( \theta \to \theta + 2\pi \).
06

Graphical Representation

The graphical representation involves marking the vertices calculated previously near the pole, the directrix, and indicating asymptotic expansion in both directions from the center, forming hyperbolic wings in the plane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates are a method of representing points in a plane using a radius and an angle. Unlike Cartesian coordinates, which use (x, y) positions, polar coordinates specify a point by how far away it is from the origin, also known as the pole, and the angle from a reference direction, usually the positive x-axis.

These coordinates are particularly useful for conic sections, such as circles, ellipses, and hyperbolas, when they are centered at the origin. For a conic's polar equation, like the one in our exercise, the form is often given by the equation:
  • \( r = \frac{ed}{1 + e \cos\theta} \) for horizontal symmetry,
  • \( r = \frac{ed}{1 + e \sin\theta} \) for vertical symmetry.
Here, \( e \) is the eccentricity and \( d \) is a constant determining the distances in the polar plane. This form is instrumental in identifying the kind of conic section represented, such as determining if it is a hyperbola when \( e > 1 \).

It's helpful to visualize by plotting various \( \theta \) values and computing the corresponding \( r \) values to sketch the graph.
Eccentricity
Eccentricity \( e \) is a crucial parameter in the study of conic sections, as it defines the shape of the conic. It measures the deviation of a conic section from being circular. The eccentricity formula for a conic in polar coordinates is derived from its polar equation.
  • For a hyperbola, \( e > 1 \).
  • For an ellipse (including circles), \( 0 < e < 1 \).
  • For a parabola, \( e = 1 \).
In our example, the given polar equation is \( r = \frac{6}{2 + 7 \cos\theta} \). By matching this with the standard polar form \( r = \frac{ed}{1 + e \cos\theta} \), we find that \( ed = 6 \) and \( e = 7 \). Solving for these gives us \( e = 3.5 \), indicating the presence of a hyperbola since it exceeds 1.

This parameter significantly affects the scope and curvature of the conic section's graph and highlights the nature of the geometry of the curve.
Vertices of Conic Sections
The vertices of a conic section are points where the conic intersects its axis of symmetry. In polar coordinates, for a hyperbola with a horizontal axis, these vertices are determined by evaluating the conic equation at special angles, usually \( \theta = 0 \) and \( \theta = \pi \).

For our hyperbola with the equation \( r = \frac{6}{2 + 7 \cos\theta} \), the vertex closer to the pole occurs when \( \theta = 0 \). Calculating this:
  • \( r = \frac{6}{9} = \frac{2}{3} \) at \( \theta = 0 \).
The other vertex, in alignment with the axis, is equidistant in the opposite direction when \( \theta = \pi \). Vertices are crucial for sketching as they pinpoint major orientations along the axis of symmetry. They guide the initial plotting points when drawing the conic's shape.

These points don't just mark critical transformations but also help in indicating where the directrix should be positioned relative to the diagram.
Asymptotes
Asymptotes in hyperbolas are invisible lines that the branches of the hyperbola approach but never touch. These lines help in understanding and sketching the general behavior of the hyperbola's curves.

While asymptotes are easily visualized in Cartesian coordinates as lines that pass through the center of the hyperbola, in polar coordinates, they demand a keen eye for transformations. However, the concept remains the same: as you examine the conic's behavior for large values of \( \theta \), the branches will lean towards these lines.
  • The lines form a cross pattern in the typical Cartesian plane.
  • These are obtained from the calculation of limits and identifying the paths at which the rational function in \( r \) approaches infinity.
The hyperbola given in polar coordinates will also have such asymptotic behavior, implied via its constriction and the widening arc spread from the vertices. This understanding equips us to predict how the hyperbola lays on a graph, aiding its plotting beyond immediate vertex points.

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Most popular questions from this chapter

For an object in an elliptical orbit around the moon, the points in the orbit that are closest to and farthest from the center of the moon are called perilune and apolune, respectively. These are the vertices of the orbit. The center of the moon is at one focus of the orbit. The Apollo II spacecraft was placed in a lunar orbit with perilune at \(68 \mathrm{mi}\) and apolune at \(195 \mathrm{mi}\) above the surface of the moon. Assuming that the moon is a sphere of radius \(1075 \mathrm{mi}\), find an equation for the orbit of Apollo II. (Place the coordinate axes so that the origin is at the center of the orbit and the foci are located on the \(x\) -axis.) (IMAGE CANNOT COPY)

With an eccentricity of 0.25 Pluto's orbit is the most eccentric in the solar system. The length of the minor axis of its orbit is approximately \(10,000,000,000 \mathrm{km},\) Find the distance between Pluto and the sun at perihelion and at aphelion.

Several examples of the uses of parabolas are given in the text. Find other situations in real life in which parabolas occur. Consult a scientific encyclopedia in the reference section of your library, or search the Internet.

Let \(Z, Z^{\prime},\) and \(R\) be the matrices $$\begin{array}{cc} Z=\left[\begin{array}{l}x \\\y\end{array}\right] &Z^{\prime}=\left[\begin{array}{l}X \\\Y\end{array}\right] \\\R=\left[\begin{array}{ll}\cos \phi & -\sin \phi \\\\\sin \phi & \cos \phi\end{array}\right]\end{array}$$ Show that the Rotation of Axes Formulas can be written as $$Z=R Z^{\prime} \quad \text { and } \quad Z^{\prime}=R^{-1} Z$$

(a) Use the discriminant to identify the conic. (b) Confirm your answer by graphing the conic using a graphing device. $$2 x^{2}-4 x y+2 y^{2}-5 x-5=0$$

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