Chapter 10: Problem 56
Sketch the triangle with the given vertices, and use a determinant to find its area. $$(1,0),(3,5),(-2,2)$$
Short Answer
Expert verified
The area of the triangle is 9.5 square units.
Step by step solution
01
Sketch the Triangle
First, make a rough sketch of the triangle by plotting the given vertices on a coordinate plane. Plot the points at \((1,0)\), \((3,5)\), and \((-2,2)\). Connect them to form a triangle.
02
Setup the Determinant Formula for Area
The area \(A\) of a triangle with vertices \((x_1, y_1), (x_2, y_2), (x_3, y_3)\) can be calculated using the determinant:\[A = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right|\]
03
Substitute the Vertices into the Formula
Substitute the coordinates of the given vertices: - \((x_1, y_1) = (1,0)\)- \((x_2, y_2) = (3,5)\)- \((x_3, y_3) = (-2,2)\)The formula becomes:\[A = \frac{1}{2} \left| 1(5-2) + 3(2-0) + (-2)(0-5) \right|\]
04
Calculate the Determinant Expression
Calculate inside the absolute value:\[1(5-2) = 1 \times 3 = 3\]\[3(2-0) = 3 \times 2 = 6\]\[(-2)(0-5) = -2 \times -5 = 10\]Combine these:\[3 + 6 + 10 = 19\]
05
Compute the Final Area
Substitute the result back into the formula:\[A = \frac{1}{2} \left| 19 \right| = \frac{19}{2} = 9.5\]Thus, the area of the triangle is 9.5 square units.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coordinate Geometry
Coordinate Geometry is a fascinating branch of mathematics that allows us to explore the shapes and sizes of geometric figures through the use of a coordinate system. In the case of a triangle, we use the Cartesian plane to represent points as coordinates. This helps us visualize the placement and structure of geometric shapes and perform calculations on them.
Given a set of points, such as \(1,0\), \(3,5\), and \(-2,2\), we can plot these on the plane to form a triangle. Each point is described by an \(x, y\) coordinate, with the first number representing the horizontal position (x-axis) and the second the vertical position (y-axis).
Given a set of points, such as \(1,0\), \(3,5\), and \(-2,2\), we can plot these on the plane to form a triangle. Each point is described by an \(x, y\) coordinate, with the first number representing the horizontal position (x-axis) and the second the vertical position (y-axis).
- **Plotting points**: On a graph, identify the x and y coordinates and mark the points accordingly.
- **Drawing lines**: Connect the points sequentially to draw the sides of the triangle.
Determinants
Determinants are a mathematical tool that can transform many complex mathematical operations into simpler computation. Specifically, a determinant is a special number calculated from a square matrix. This concept is crucial in solving systems of linear equations, finding area and volume of certain geometric shapes, and more.
When relating determinants to a triangle on a coordinate plane, we use a specific determinant formula to find the triangle's area, when given its vertices.
When relating determinants to a triangle on a coordinate plane, we use a specific determinant formula to find the triangle's area, when given its vertices.
- The general formula employed is:
\[ A = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right| \] - Here, \(x_1, y_1, x_2, y_2, x_3, \) and \(y_3\) represent the coordinates of the triangle's vertices.
Triangle Area Calculation
Calculating the area of a triangle using its vertex coordinates is an essential application of both coordinate geometry and determinants. Instead of relying on the traditional base-times-height method, using coordinates allows for a straightforward approach to finding the area.
Consider the vertices \(1,0\), \(3,5\), and \(-2,2\). By plugging these into the determinant formula mentioned before, we calculate each term inside the determinant separately: \(1(5-2) = 3\), \(3(2-0) = 6\), and \((-2)(0-5) = \text{-10}\).
Consider the vertices \(1,0\), \(3,5\), and \(-2,2\). By plugging these into the determinant formula mentioned before, we calculate each term inside the determinant separately: \(1(5-2) = 3\), \(3(2-0) = 6\), and \((-2)(0-5) = \text{-10}\).
- **Combine the terms**: Add the results: \(3 + 6 + 10 = 19\).
- **Divide by two**: Take \(\frac{1}{2}\) of this total.
- **Absolute value**: Calculate the absolute value to ensure the area is positive, as area can't be negative.