/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 The matrices \(A, B, C, D, E, F,... [FREE SOLUTION] | 91Ó°ÊÓ

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The matrices \(A, B, C, D, E, F, G\) and \(H\) are defined as follows. $$\begin{aligned} &A=\left[\begin{array}{rr} 2 & -5 \\ 0 & 7 \end{array}\right] \quad B=\left[\begin{array}{rrr} 3 & \frac{1}{2} & 5 \\ 1 & -1 & 3 \end{array}\right] \quad C=\left[\begin{array}{rrr} 2 & -\frac{5}{2} & 0 \\ 0 & 2 & -3 \end{array}\right]\\\ &D=\left[\begin{array}{llll} 7 & 3 \end{array}\right] \quad E=\left[\begin{array}{l} 1 \\ 2 \\ 0 \end{array}\right] \quad F=\left[\begin{array}{lll} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right]\\\ &G=\left[\begin{array}{rrr} 5 & -3 & 10 \\ 6 & 1 & 0 \\ -5 & 2 & 2 \end{array}\right] \quad H=\left[\begin{array}{rr} 3 & 1 \\ 2 & -1 \end{array}\right] \end{aligned}$$ Carry out the indicated algebraic operation, or explain why it cannot be performed. (a) \(A^{2}\) (b) \(A^{3}\)

Short Answer

Expert verified
(a) \(A^2 = \begin{bmatrix} 4 & -45 \\ 0 & 49 \end{bmatrix}\); (b) \(A^3 = \begin{bmatrix} 8 & -385 \\ 0 & 343 \end{bmatrix}\)

Step by step solution

01

Determine A^2 Existence

For a square matrix A, the square matrix A^2 exists if A is 2x2. Check given matrix A: \[ A = \begin{bmatrix} 2 & -5 \ 0 & 7 \end{bmatrix} \]. A is a 2x2 matrix, so A^2 can be calculated.
02

Calculate A^2

To find \( A^2 \), multiply matrix A by itself:\[A^2 = A \times A = \begin{bmatrix} 2 & -5 \ 0 & 7 \end{bmatrix} \times \begin{bmatrix} 2 & -5 \ 0 & 7 \end{bmatrix} = \begin{bmatrix} 2 \cdot 2 + (-5) \cdot 0 & 2 \cdot (-5) + (-5) \cdot 7 \ 0 \cdot 2 + 7 \cdot 0 & 0 \cdot (-5) + 7 \cdot 7 \end{bmatrix} = \begin{bmatrix} 4 & -45 \ 0 & 49 \end{bmatrix} \]
03

Determine A^3 Existence

A^3 is defined if it can be computed as \( A \times A^2 \). Check matrix A: it is a 2x2 matrix. Since A^2 is calculated in Step 2, A^3 can be obtained by multiplying A by A^2.
04

Calculate A^3

Multiply matrix A by matrix A^2 to compute A^3:\[A^3 = A \times A^2 = \begin{bmatrix} 2 & -5 \ 0 & 7 \end{bmatrix} \times \begin{bmatrix} 4 & -45 \ 0 & 49 \end{bmatrix} = \begin{bmatrix} 2 \cdot 4 + (-5) \cdot 0 & 2 \cdot (-45) + (-5) \cdot 49 \ 0 \cdot 4 + 7 \cdot 0 & 0 \cdot (-45) + 7 \cdot 49 \end{bmatrix} = \begin{bmatrix} 8 & -385 \ 0 & 343 \end{bmatrix} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a way to combine two matrices to form a new one. This operation is only possible when the number of columns in the first matrix equals the number of rows in the second matrix. For instance, if you have a matrix
  • with dimensions \( m \times n \) and another with dimensions \( n \times p \),
then their product will be a new matrix with dimensions \( m \times p \). Each element in the resulting matrix is calculated by taking the dot product of corresponding rows and columns from the two matrices.
In simpler terms, think of moving horizontally across the rows of the first matrix, and vertically down the columns of the second one, multiplying numbers and adding them up.
Remember this: matrix multiplication is not commutative, meaning \( A \times B \) is not the same as \( B \times A \).
Square Matrix
A square matrix is simply a matrix with the same number of rows and columns. For example, a 2x2 or a 3x3 matrix. The operations on square matrices are often simpler to handle because of this balance in dimensions.
Square matrices possess unique properties: they have a determinant, can be inverted (under certain conditions), and are often used in solving systems of linear equations.
  • One important characteristic of square matrices is that they can be multiplied by themselves multiple times, leading to the calculation of exponents such as \( A^2 \), \( A^3 \), and so on.
In our exercise, matrix \(A\) is 2x2, making it a square matrix, which explains the feasibility of calculating its exponents, like \( A^2 \) and \( A^3 \).
Matrix Exponents
Matrix exponents involve multiplying a square matrix by itself a certain number of times. For example, \( A^2 \) means the matrix \( A \) is multiplied by itself once, while \( A^3 \) means it is multiplied by \( A^2 \).
  • Keep in mind: matrix exponents are defined only for square matrices.
  • Each resulting product has the potential to be calculated once you ensure the multiplication rules align.
Computing these exponents involves consecutively multiplying matrices, which follows similar rows and columns dot products as in normal matrix multiplication.
Matrix exponents are useful in various areas, such as in solving linear recurrence relations and modeling systems that evolve over time, known as dynamical systems.

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Most popular questions from this chapter

Use a graphing calculator to graph the solution of the system of inequalities. Find the coordinates of all vertices, rounded to one decimal place. $$\left\\{\begin{array}{c} x+y \geq 12 \\ 2 x+y \leq 24 \\ x-y \geq-6 \end{array}\right.$$

Manufacturing Furniture A furniture factory makes wooden tables, chairs, and armoires. Each piece of furniture requires three operations: cutting the wood, assembling, and finishing. Each operation requires the number of hours ( \(h\) ) given in the table. The workers in the factory can provide 300 hours of cutting, 400 hours of assembling, and 590 hours of finishing each work week. How many tables, chairs, and armoires should be produced so that all available labor-hours are used? Or is this impossible? $$\begin{array}{|l|c|c|c|} \hline & \text { Table } & \text { Chair } & \text { Armoire } \\ \hline \text { Cutting (h) } & \frac{1}{2} & 1 & 1 \\ \text { Assembling (h) } & \frac{1}{2} & 1 \frac{1}{2} & 1 \\ \text { Finishing (h) } & 1 & 1 \frac{1}{2} & 2 \\ \hline \end{array}$$

Use Cramer's Rule to solve the system. $$\left\\{\begin{array}{l} 0.4 x+1.2 y=0.4 \\ 1.2 x+1.6 y=3.2 \end{array}\right.$$

(a) If three points lie on a line, what is the area of the "triangle" that they determine? Use the answer to this question, together with the determinant formula for the area of a triangle, to explain why the points \(\left(a_{1}, b_{1}\right)\) \(\left(a_{2}, b_{2}\right),\) and \(\left(a_{3}, b_{3}\right)\) are collinear if and only if $$\left|\begin{array}{lll} a_{1} & b_{1} & 1 \\ a_{2} & b_{2} & 1 \\ a_{3} & b_{3} & 1 \end{array}\right|=0$$ (b) Use a determinant to check whether each set of points is collinear. Graph them to verify your answer. (I) \((-6,4),(2,10),(6,13)\) (II) \((-5,10),(2,6),(15,-2)\)

Find the inverse of the matrix. For what value(s) of \(x\) if any, does the matrix have no inverse? $$\left[\begin{array}{cc} x & 1 \\ -x & \frac{1}{x-1} \end{array}\right]$$

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