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Determine whether the system of linear equations is inconsistent or dependent. If it is dependent, find the complete solution. $$\left\\{\begin{aligned} x+y+z &=2 \\ y-3 z &=1 \\ 2 x+y+5 z &=0 \end{aligned}\right.$$

Short Answer

Expert verified
The system is inconsistent.

Step by step solution

01

Write the system of equations in matrix form

First, we write the system of equations in its matrix form, which helps us to see the coefficients clearly. This system can be represented as:\[\begin{bmatrix}1 & 1 & 1 \0 & 1 & -3 \2 & 1 & 5 \\end{bmatrix}\begin{bmatrix}x \y \z \\end{bmatrix}=\begin{bmatrix}2 \1 \0 \\end{bmatrix}\]
02

Perform Gaussian elimination

We aim to convert the matrix into row-echelon form or reduced row-echelon form to identify the characteristics of the system.1. The first row is \([1, 1, 1 | 2]\).2. To eliminate the first element in the third row, subtract 2 times the first row from the third row: \([2, 1, 5 | 0] - 2[1, 1, 1 | 2] = [0, -1, 3 | -4]\)Thus, the matrix becomes:\[\begin{bmatrix}1 & 1 & 1 | 2 \0 & 1 & -3 | 1 \0 & -1 & 3 | -4 \\end{bmatrix}\]
03

Simplify second and third rows

To simplify the second and third row further by eliminating a variable:- Add the second row to the third row to eliminate the \(y\) term in the third row: \([0, -1, 3 | -4] + [0, 1, -3 | 1] = [0, 0, 0 | -3]\)Notice, we now have a row \([0, 0, 0 | -3] \) which indicates an inconsistency.
04

Identify the system as inconsistent

The row \([0, 0, 0 | -3]\) suggests that there is no solution to this system because it implies the equation 0x + 0y + 0z = -3, which is a contradiction. Hence, the system is inconsistent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gaussian elimination
To tackle systems of linear equations, mathematicians often turn to a method called Gaussian elimination. This technique enables us to systematically simplify a set of equations and here, the beauty of linear algebra unfolds.

In Gaussian elimination, the main goal is to modify the system into a form that simplifies solution extraction. By performing row operations such as scaling, swapping, and combining rows, we strive to reach what is known as "row-echelon form" or even further to "reduced row-echelon form."
  • The process begins by filling up the diagonal of the matrix with 1s, if possible, starting from the first row.
  • You aim to achieve zeroes beneath these leading 1s, which makes it easier to solve for variables.
  • Gaussian elimination is a structured way to isolate variables through systematized transformation of the matrix.
This method is powerful in identifying whether a system has a unique solution, is dependent, or is inconsistent.
Matrix representation of equations
Converting a system of linear equations into matrix form is instrumental for applying computational techniques like Gaussian elimination. Instead of dealing with multiple equations simultaneously, a matrix compactly represents all coefficients and constants of the system.

Let's break down how this works:
  • The "coefficient matrix" contains all the numerical coefficients of the variables.
  • The "variable matrix" includes the variables themselves, often structured as a column matrix.
  • The "constant matrix" or "augmented matrix" incorporates the constants from the right side of the equations.
For instance, in our original problem, the matrices were shown as
\[\begin{bmatrix}1 & 1 & 1 \0 & 1 & -3 \2 & 1 & 5 \\end{bmatrix} \cdot \begin{bmatrix}x \y \z \\end{bmatrix} =\begin{bmatrix}2 \1 \0 \\end{bmatrix}\] which makes a complex equation easier to handle, and sets the stage for Gaussian elimination.
Inconsistent system
An inconsistent system of equations is one that lacks a solution. These systems often arise when the equations contradict each other. Recognizing a system as inconsistent is a crucial step in your analysis.

In the context of matrices and Gaussian elimination, inconsistency becomes apparent when you encounter a row in the final matrix form that translates to an impossible equation. For example, the row [0, 0, 0 | -3] implies
\[0x + 0y + 0z = -3\]
Clearly, \(0 = -3\) is not a plausible statement and indicates that no value of \(x, y, z\) will satisfy such a contradiction.

Hence, the original system of equations cannot have any solution. Determining this can prevent wasted effort trying to solve an unsolvable problem.
Row-echelon form
When you hear row-echelon form, think of steps or staircases. This representation of a matrix makes equation-solving more methodical and systematic.

In row-echelon form:
  • Every row starts with zeros, and the first non-zero number is a 1, called the leading 1.
  • Each subsequent leading 1 is further to the right than the leading 1 in the row just above it.
  • Once a row is filled entirely with zeros, it’s placed at the bottom.
Using row-echelon form takes us halfway to solving a system of linear equations. The ideal outcome is then a series of equations that can be easily solved through back-substitution.

Achieving this form is a significant milestone in Gaussian elimination, far reducing the complexity of systems of equations, turning insurmountable puzzles into manageable tasks.

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Most popular questions from this chapter

A cat food manufacturer uses fish and beef byproducts. The fish contains \(12 \mathrm{g}\) of protein and \(3 \mathrm{g}\) of fat per ounce. The beef contains \(6 \mathrm{g}\) of protein and \(9 \mathrm{g}\) of fat per ounce. Each can of cat food must contain at least \(60 \mathrm{g}\) of protein and \(45 \mathrm{g}\) of fat. Find a system of inequalities that describes the possible number of ounces of fish and beef that can be used in each can to satisfy these minimum requirements. Graph the solution set.

A roadside fruit stand sells apples at \(75 \notin\) a pound, peaches at \(90 \notin\) a pound, and pears at \(60 \notin\) a pound. Muriel buys 18 pounds of fruit at a total cost of 13.80 dollar Her peaches and pears together cost 1.80 dollar more than her apples. (a) Set up a linear system for the number of pounds of apples, peaches, and pears that she bought. (b) Solve the system using Cramer's Rule.

Use Cramer's Rule to solve the system. $$\left\\{\begin{array}{l} \frac{1}{2} x+\frac{1}{3} y=1 \\ \frac{1}{4} x-\frac{1}{6} y=-\frac{3}{2} \end{array}\right.$$

Graph the solution of the system of inequalities. Find the coordinates of all vertices, and determine whether the solution set is bounded. $$\left\\{\begin{aligned} x^{2}+y^{2} & \leq 8 \\ x & \geq 2 \\ y & \geq 0 \end{aligned}\right.$$

To graph the solution of a system of inequalities, we have shaded the solution of each inequality in a different color; the solution of the system is the region where all the shaded parts overlap. Here is a different method: For each inequality, shade the region that does not satisfy the inequality. Explain why the part of the plane that is left unshaded is the solution of the system. Solve the following system by both methods. Which do you prefer? Why? $$\left\\{\begin{aligned} x+2 y &>4 \\ -x+y &<1 \\ x+3 y &<9 \\ x &<3 \end{aligned}\right.$$

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