Chapter 10: Problem 19
Find all solutions of the system of equations. $$\left\\{\begin{array}{l} y+x^{2}=4 x \\ y+4 x=16 \end{array}\right.$$
Short Answer
Expert verified
The solution is \( x = 4 \) and \( y = 0 \).
Step by step solution
01
Solve the Second Equation for y
We start by solving the second equation for \( y \). The equation is \( y + 4x = 16 \). Subtract \( 4x \) from both sides to isolate \( y \):\[ y = 16 - 4x \].
02
Substitute for y in the First Equation
Now take the expression for \( y \) from Step 1 and substitute it into the first equation \( y + x^2 = 4x \). This gives us:\[ (16 - 4x) + x^2 = 4x \].
03
Simplify the Equation
Distribute and simplify the equation from Step 2:\[ x^2 - 4x + 16 = 4x \].Subtract \( 4x \) from both sides:\[ x^2 - 8x + 16 = 0 \].
04
Solve the Quadratic Equation
The equation is a perfect square trinomial. Recognize and factor it as:\[ (x - 4)^2 = 0 \].This gives \( x = 4 \) since the only solution to a perfect square is when it's zero.
05
Find the Corresponding y Value
Substitute \( x = 4 \) back into the equation \( y = 16 - 4x \) from Step 1:\[ y = 16 - 4(4) \].Calculate to find \( y = 16 - 16 = 0 \).
06
Verify the Solution
Substitute \( x = 4 \) and \( y = 0 \) back into the original equations to verify:- For the first equation, \( y + x^2 = 4x \) becomes \( 0 + 16 = 16 \), which holds true.- For the second equation, \( y + 4x = 16 \) becomes \( 0 + 16 = 16 \), which also holds true.Both equations are satisfied, confirming the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is an equation of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( x \) is the variable. In systems of equations like the one in the exercise, quadratic equations often need solving to find values of \( x \). The standard methods to solve them include:
- Factoring
- Using the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- Completing the square
Substitution Method
The substitution method is a technique used to solve systems of equations, especially when one of the equations can easily be solved for one variable. This method involves:
- Solving one of the equations for one variable in terms of the other. For instance, solving \( y + 4x = 16 \) for \( y \) gives \( y = 16 - 4x \).
- Substituting this expression into the other equation. In the original task, we substitute \( y = 16 - 4x \) into \( y + x^2 = 4x \), leading to a single equation with one variable.
- Simplifying and solving the resulting equation.
Perfect Square Trinomial
A perfect square trinomial is a type of quadratic expression that can be pretty easily factored as the square of a binomial. It has the form \( (ax + b)^2 = a^2x^2 + 2abx + b^2 \). In the given exercise, the quadratic equation \( x^2 - 8x + 16 = 0 \) can be recognized as a perfect square trinomial.To identify a perfect square trinomial:
- Check if the first and last terms are perfect squares.
- Ensure the middle term is twice the product of the square roots of the first and last terms.