Chapter 10: Problem 13
Graph the inequality. $$y>x^{2}+1$$
Short Answer
Expert verified
Sketch the parabola \( y = x^2 + 1 \) as a dashed line and shade above it.
Step by step solution
01
Understand the Inequality
The inequality given is \( y > x^2 + 1 \). This means that we need to shade the area above the parabola \( y = x^2 + 1 \). The line \( y = x^2 + 1 \) is the boundary, and since the inequality is strict (\(>\), not \(\geq\)), we will draw this boundary line as a dashed line.
02
Identify the Parabola
The parabola \( y = x^2 + 1 \) is in the vertex form \( y = ax^2 + bx + c \) with \( a = 1, b = 0, \) and \( c = 1 \). The vertex of this parabola is at \((0,1)\). Since \( a > 0 \), the parabola opens upwards.
03
Plot the Parabola
Sketch the parabola by plotting a few points around the vertex. The vertex is \((0,1)\). For \( x = -1 \) and \( x = 1 \), calculate \( y = (-1)^2 + 1 = 2 \) and \( y = 1^2 + 1 = 2 \) respectively. For \( x = -2 \) and \( x = 2 \), calculate \( y = 5 \). Plot these points: \((-1, 2)\), \((1, 2)\), \((-2, 5)\), and \((2, 5)\), and draw the dashed parabola through them.
04
Shade the Correct Region
Since the inequality is \( y > x^2 + 1 \), shade the region above the dashed parabola line. This represents all points \((x, y)\) where the \( y \) value is greater than \( x^2 + 1 \).
05
Verify With a Test Point
Pick a test point not on the parabola to verify the shading. A good candidate is the origin \((0,0)\). Substitute into the inequality: \( 0 > 0^2 + 1 \) or \( 0 > 1 \), which is false. Thus, the shading is correct as the point should not satisfy the inequality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a symmetric, U-shaped curve that is defined by a quadratic equation. In the inequality given in our exercise, we explore the parabola defined by the equation \( y = x^2 + 1 \). Here, the graph of the parabola serves as a boundary for the inequality \( y > x^2 + 1 \). To understand a parabola, it's critical to identify the vertex, which is the point where the parabola changes direction. In simpler terms, the parabola looks like a cup if it opens upwards or an upside-down cup if it opens downwards. In our example, the parabola opens upward because the coefficient of \( x^2 \) is positive. Points to remember about a parabola:
- The basic form is \( y = ax^2 + bx + c \).
- The vertex is derived from the terms \( a \), \( b \), and \( c \).
- A positive \( a \) means the parabola opens upwards.
Vertex Form
The vertex form of a quadratic equation is highly useful for graphing parabolas as it reveals the vertex directly. The standard vertex form is expressed as \( y = a(x - h)^2 + k \), where
- \( (h, k) \) is the vertex of the parabola, and
- \( a \) determines the direction and the width of the parabola.
- The vertex provides the starting point for drawing the curve,
- \( a \) confirms the parabola's direction (upward or downward), and
- \( c \) gives the vertical shift from the base parabola \( y = x^2 \).
Shading Regions
When graphing inequalities, shading the correct region is key to representing the solution set visually. For the inequality \( y > x^2 + 1 \), the process involves determining which part of the graph satisfies the inequality. Once the parabola is sketched using a dashed line, as the inequality is strict (indicated by \(>\) rather than \( \geq \)), shading takes place above this boundary line. Steps for shading:
- Identify the boundary line or curve (here, the parabola \( y = x^2 + 1 \)).
- Since the inequality is strict, use a dashed line to show the boundary isn’t included.
- Determine which region satisfies the inequality by choosing a test point, such as the origin \((0, 0)\). Substitute it into the inequality: \( y > x^2 + 1 \).
- If the test fails (like in this case \(0 > 1\) is false), the region that satisfies the test is on the opposite side of the test point.