Chapter 1: Problem 82
Solve the absolute value inequality. Express the answer using interval notation and graph the solution set. $$|8 x+3|>12$$
Short Answer
Expert verified
The solution in interval notation is \((-\infty, -\frac{15}{8}) \cup (\frac{9}{8}, \infty)\).
Step by step solution
01
Understanding the Inequality
The given inequality is \(|8x + 3| > 12\). This inequality involves an absolute value, which means the expression inside the absolute value can be greater than 12 or less than -12.
02
Breaking Down the Inequality
To solve \(|8x + 3| > 12\), we break it down into two separate inequalities:1. \(8x + 3 > 12\)2. \(8x + 3 < -12\)
03
Solving the First Inequality
Let's solve the inequality \(8x + 3 > 12\):Subtract 3 from both sides:\[8x > 12 - 3\]\[8x > 9\]Divide by 8:\[x > \frac{9}{8}\]
04
Solving the Second Inequality
Now, solve the inequality \(8x + 3 < -12\):Subtract 3 from both sides:\[8x < -12 - 3\]\[8x < -15\]Divide by 8:\[x < -\frac{15}{8}\]
05
Combining the Solutions
Combine the solutions from both parts. The solution to \(|8x + 3| > 12\) is the union of the solutions found:\[x < -\frac{15}{8} \text{ or } x > \frac{9}{8}\]In interval notation, this is:\[(-\infty, -\frac{15}{8}) \cup (\frac{9}{8}, \infty)\]
06
Graphing the Solution Set
To graph the solution set:- Draw a number line.- Mark an open circle at \(-\frac{15}{8}\) to indicate \(x < -\frac{15}{8}\).- Mark an open circle at \(\frac{9}{8}\) to indicate \(x > \frac{9}{8}\).- Shade the regions to the left of \(-\frac{15}{8}\) and to the right of \(\frac{9}{8}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a way to describe the solution sets of inequalities using intervals. It’s a concise method to denote all numbers that satisfy the inequality in question. When dealing with absolute value inequalities, like \(|8x + 3| > 12\), you often end up with two solution intervals because absolute value represents a distance from zero.
In the provided solution, solving \(|8x + 3| > 12\) gives us two separate conditions: \(x < -\frac{15}{8}\) or \(x > \frac{9}{8}\). These conditions tell us where the expression \(8x + 3\) is either less than -12 or greater than 12. Therefore, the solution is split into intervals:
In the provided solution, solving \(|8x + 3| > 12\) gives us two separate conditions: \(x < -\frac{15}{8}\) or \(x > \frac{9}{8}\). These conditions tell us where the expression \(8x + 3\) is either less than -12 or greater than 12. Therefore, the solution is split into intervals:
- From negative infinity to \(-\frac{15}{8}\) (\(-\infty, -\frac{15}{8})\)
- From \(\frac{9}{8}\) to positive infinity (\(\frac{9}{8}, \infty)\)
Inequalities
Inequalities are mathematical statements showing the relationship between quantities that are not necessarily equal. They often involve symbols like >, <, ≥, and ≤. In the context of absolute value inequalities, they are used to express the range of values that satisfy a condition like \(|8x + 3| > 12\).
When breaking down absolute value inequalities, you usually convert the problem into two separate inequalities. This is because the absolute value essentially measures how far a number is from zero in either direction. For instance, solving \(|8x + 3| > 12\) translates to needing to check both where \(8x + 3\) is greater than 12 or less than -12.
When breaking down absolute value inequalities, you usually convert the problem into two separate inequalities. This is because the absolute value essentially measures how far a number is from zero in either direction. For instance, solving \(|8x + 3| > 12\) translates to needing to check both where \(8x + 3\) is greater than 12 or less than -12.
- The inequality \(8x + 3 > 12\) is solved for \(x\) by isolating \(x\): first subtract 3, then divide by 8 to find \(x > \frac{9}{8}\).
- Similarly, solve \(8x + 3 < -12\) to get \(x < -\frac{15}{8}\).
Graphing Solutions
Graphing solutions is a visual representation of the solution set for inequalities on a number line. It helps to quickly interpret and understand the range of solutions. After solving inequalities, especially involving absolute values like \(|8x + 3| > 12\), graphing the solution can make it easier to visualize what's happening.
To graph the solution:
To graph the solution:
- Draw a horizontal line to represent a number line.
- Identify the critical points of \(-\frac{15}{8}\) and \(\frac{9}{8}\) from the solution \[x < -\frac{15}{8} \text{ or } x > \frac{9}{8}\]
- Place an open circle on both \(-\frac{15}{8}\) and \(\frac{9}{8}\) to indicate these points are not included in the solution (since our inequality is a strict 'greater than').
- Shade the region to the left of \(-\frac{15}{8}\) indicating numbers less than \(-\frac{15}{8}\), and the region to the right of \(\frac{9}{8}\) to show numbers greater than \(\frac{9}{8}\).