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Make a table of values and sketch the graph of the equation. Find the x- and y-intercepts and test for symmetry. $$y=16-x^{4}$$

Short Answer

Expert verified
The x-intercepts are (-2, 0) and (2, 0); y-intercept is (0, 16). The graph is symmetric with respect to the y-axis.

Step by step solution

01

Create a Table of Values

To sketch the graph, we first create a table of values by selecting various x-values and calculating the corresponding y-values using the equation \(y = 16 - x^4\). Let's choose x-values: -2, -1, 0, 1, 2, and calculate:- If \(x = -2\), \(y = 16 - (-2)^4 = 16 - 16 = 0\).- If \(x = -1\), \(y = 16 - (-1)^4 = 16 - 1 = 15\).- If \(x = 0\), \(y = 16 - 0^4 = 16\).- If \(x = 1\), \(y = 16 - 1^4 = 16 - 1 = 15\).- If \(x = 2\), \(y = 16 - 2^4 = 16 - 16 = 0\).These values create the set of points: (-2,0), (-1,15), (0,16), (1,15), and (2,0).
02

Sketch the Graph

Using the table of values, plot the points on a coordinate plane: 1. Plot (-2, 0) and (2, 0) which are symmetrical across the y-axis. 2. Plot (-1, 15) and (1, 15) showing symmetry. 3. Plot (0, 16), the peak of the graph. The graph should look like an inverted 'W' symmetrical on the y-axis, where the function flattens horizontally between x = -2 to x = 2.
03

Find the x-Intercepts

To find the x-intercepts, set \(y = 0\) in the equation \(16 - x^4 = 0\) and solve for \(x\).\[16 = x^4\]Taking the fourth root on both sides,\[x = \pm2\]Thus, the x-intercepts are at points (2, 0) and (-2, 0).
04

Find the y-Intercept

To find the y-intercept, set \(x = 0\) in the equation \(y = 16 - x^4\).\[y = 16 - 0^4 = 16\]Thus, the y-intercept is at the point (0, 16).
05

Test for Symmetry

To test for symmetry, check symmetry across the y-axis by determining if \(f(-x) = f(x)\). Substitute \(-x\) into the equation:\[f(-x) = 16 - (-x)^4 = 16 - x^4 = f(x)\]This shows that the function is symmetric with respect to the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

x-intercepts
The x-intercepts of a graph are the points where the graph crosses the x-axis. To find these points, you need to set the y-value in the equation equal to zero, since every point along the x-axis has a y-coordinate of zero.

In our given equation, which is \( y = 16 - x^4 \), we find the x-intercepts by setting \( y = 0 \). This gives us the equation:
  • \( 16 - x^4 = 0 \)
Solve for \( x \) by rearranging the equation to get \( x^4 = 16 \). To isolate \( x \), take the fourth root of both sides:
  • \( x = \pm 2 \)
This means the x-intercepts occur where the graph crosses the x-axis at the points (2, 0) and (-2, 0).

Remember, x-intercepts serve as an important feature when graphing polynomial functions, as they signal where the graph changes from positive to negative values or vice versa.
y-intercepts
The y-intercept of a graph is the point where the graph intersects the y-axis. At this intersection, the x-coordinate is always zero. To find the y-intercept, substitute \(x = 0\) into the equation of the function.

For the function \(y = 16 - x^4\), set \(x = 0\), resulting in:
  • \(y = 16 - (0)^4 = 16\)
This calculation indicates that the y-intercept of the graph is at the point (0, 16).

Finding the y-intercept helps with quickly sketching the graph, providing a reliable starting point and anchor for the curve of the function.
symmetry in graphs
Symmetry in graphs signifies that the graph is a mirror image over a particular line. In polynomial functions, we frequently check for symmetry about the y-axis and the origin.

In this case, to test for symmetry about the y-axis, we replace \(x\) with \(-x\) in the function and evaluate if \(f(-x) = f(x)\). For the equation \(y = 16 - x^4\), substituting \(-x\) yields:
  • \(f(-x) = 16 - (-x)^4 = 16 - x^4\), which simplifies to \(f(x)\)
As a result, since \(f(-x) = f(x)\), the function is symmetrical with respect to the y-axis.

This symmetry is visually reflected as you graph it, ensuring that if a point \((a, b)\) lies on the graph, its symmetric counterpart \((-a, b)\) will also be present. It simplifies understanding and sketching as it allows predicting the shape without plotting every point explicitly.

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