Chapter 1: Problem 73
It took a crew 2 h 40 min to row 6 km upstream and back again. If the rate of flow of the stream was 3 km/h, what was the rowing speed of the crew instill water?
Short Answer
Expert verified
The rowing speed of the crew in still water is 6 km/h.
Step by step solution
01
Convert Time to Hours
The time given is 2 hours and 40 minutes. Convert this time into hours: \(2 + \frac{40}{60} = 2.67\) hours.
02
Define Variables for Speed
Let the rowing speed of the crew in still water be \(x\) km/h. The speed upstream would be \(x - 3\) km/h and the speed downstream would be \(x + 3\) km/h due to the current's speed.
03
Set Up the Equation Based on Time
The time taken to row upstream can be calculated as \(\frac{6}{x-3}\) and downstream as \(\frac{6}{x+3}\). The total time for both trips is given by the equation: \[ \frac{6}{x-3} + \frac{6}{x+3} = 2.67 \]
04
Simplify the Equation
Simplify the previous equation to find \(x\). First, find a common denominator and set the equation: \[ \frac{6(x+3) + 6(x-3)}{(x-3)(x+3)} = 2.67 \] Simplifying: \[ \frac{12x}{x^2 - 9} = 2.67 \]
05
Solve the Quadratic Equation
Multiply through by \((x^2 - 9)\) to clear the denominator: \[ 12x = 2.67(x^2 - 9) \] Solving gives: \[ 2.67x^2 - 12x - 24.03 = 0 \] This is a quadratic equation to solve for \(x\).
06
Find the Roots of the Quadratic
Apply the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) to find \(x\), where \(a = 2.67\), \(b = -12\), and \(c = -24.03\). Solve to find the value of \(x\).
07
Identify the Reasonable Solution
Calculate the discriminant and solve:\[ x = \frac{12 \pm \sqrt{144 + 4 \times 2.67 \times 24.03}}{2 \times 2.67} \]First calculate:\[ 144 + 4 \times 2.67 \times 24.03 = 408.26\]And:\[ sqrt(408.26) \approx 20.20\]Thus:\[ x = \frac{12 \pm 20.20}{5.34}\]This gives two roots; use the positive root as speed cannot be negative: \(x \approx 6\) km/h.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a vital part of algebra, taking the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. They can appear daunting at first, but with understanding, they become manageable.One common method to solve quadratic equations is using the quadratic formula:
Another method is factoring, where the equation is expressed as the product of its roots if they exist as rational numbers.
Understanding the discriminant \(\sqrt{b^2 - 4ac}\) is crucial, as it indicates the nature of the roots:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Another method is factoring, where the equation is expressed as the product of its roots if they exist as rational numbers.
Understanding the discriminant \(\sqrt{b^2 - 4ac}\) is crucial, as it indicates the nature of the roots:
- If positive, there are two distinct real roots.
- If zero, there's exactly one real root (a repeated root).
- If negative, there are no real roots (the roots are complex numbers).
Distance-Rate-Time Problems
Distance-rate-time problems connect three fundamental quantities in mathematics: distance, rate (speed), and time. These problems often require setting up and solving equations where distance equals rate multiplied by time (\(d = rt\)). These types of problems frequently appear in real-life contexts, such as travel or work-related scenarios.
When confronted with such problems:
When confronted with such problems:
- Identify the quantities you know.
- Use the formula to set up equations based on the context.
- Solve to find the unknown value.
Upstream and Downstream Problems
Upstream and downstream problems involve understanding how a current affects travel, whether it be rowing or motoring. The main concept revolves around the impact of the current on travel speed.When traveling upstream:
- The current works against you.
- Effective speed is reduced: \( x - c \), with \(x\) being the speed in still water and \(c\) the current's speed.
- The current assists you.
- Effective speed increases: \( x + c\).
Algebraic Equations
Algebraic equations form the backbone of mathematical problem-solving, providing a way to express relationships between quantities and solve for unknowns.Solving algebraic equations involves:
- Writing expressions using variables to represent unknown quantities.
- Arranging these expressions into an equation that models the given scenario.
- Using arithmetic operations and algebraic manipulations to solve for the unknowns.