Chapter 1: Problem 73
If you stand on a ship in a calm sea, then your height \(x\) (in ft) above sea level is related to the farthest distance \(y\) (in mi) that you can see by the equation $$y=\sqrt{1.5 x+\left(\frac{x}{5280}\right)^{2}}$$ (a) Graph the equation for \(0 \leq x \leq 100\). (b) How high up do you have to be to be able to see \(10 \mathrm{mi}\) ?
Short Answer
Step by step solution
Understanding the Equation
Graphing the Equation
Solving for \( x \) When \( y = 10 \)
Squaring Both Sides
Simplifying and Solving the Equation
Solving the Quadratic Equation
Finding the Positive Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula helps you find the roots or solutions of the quadratic equation, where these roots can be real or complex numbers. Here's how you apply it:
- Identify the coefficients \( a \), \( b \), and \( c \) from your quadratic equation.
- Calculate the discriminant \( b^2 - 4ac \); this part of the formula determines the nature of the roots.
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, the equation has exactly one real root, often called a double root.
- If it is negative, the roots are complex numbers.
Solving Equations
- Ensure the equation is properly set up according to the problem's requirements.
- Simplify both sides of the equation as much as possible by combining like terms and eliminating parentheses.
- Use operations to isolate the variable. This may include adding, subtracting, multiplying, or dividing both sides by the same number.
- If dealing with a quadratic equation, utilize the quadratic formula to find the solutions.
Distance Calculation
- The equation \( y = \sqrt{1.5x + \left(\frac{x}{5280}\right)^2} \) links the observer's height \( x \) in feet to the possible distance \( y \) they can see in miles.
- The formula takes into account both a linear and a very small quadratic component to give a precise calculation of distance.
- A practical approach is to graph the function for realistic heights, providing a visual representation of distance based on different heights above sea level.
- When calculating specific scenarios, such as wanting to determine what height allows for a 10-mile view, one must effectively solve the equation for that particular distance.