Chapter 1: Problem 71
Make a table of values and sketch the graph of the equation. Find the x- and y-intercepts and test for symmetry. $$x+y^{2}=4$$
Short Answer
Expert verified
The x-intercept is (4,0), y-intercepts are (0,2) and (0,-2). The graph is symmetrical about the x-axis.
Step by step solution
01
Rearrange the Equation
We start with the equation \(x + y^2 = 4\). To make a table of values, we need to solve for \(x\) in terms of \(y\), which gives us \(x = 4 - y^2\).
02
Create a Table of Values
Choose several values for \(y\), compute the corresponding values for \(x\), and list them in a table.- If \(y = -2\), then \(x = 4 - (-2)^2 = 0\)- If \(y = -1\), then \(x = 4 - (-1)^2 = 3\)- If \(y = 0\), then \(x = 4 - 0^2 = 4\)- If \(y = 1\), then \(x = 4 - 1^2 = 3\)- If \(y = 2\), then \(x = 4 - 2^2 = 0\)
03
Sketch the Graph
Plot the points from the table on a coordinate plane and draw a smooth curve through them. The graph should resemble a sideways parabola because of the \(y^2\) term.
04
Find the X-Intercept(s)
To find the x-intercept, set \(y = 0\) and solve for \(x\):\[ x + 0^2 = 4 \]Thus, \(x = 4\). The x-intercept is (4,0).
05
Find the Y-Intercept(s)
To find the y-intercepts, set \(x = 0\) and solve for \(y\): \[ 0 + y^2 = 4 \]Thus, \(y = \pm 2\). The y-intercepts are (0,2) and (0,-2).
06
Test for Symmetry
Test for symmetry about the x-axis, y-axis, and origin. By replacing \(y\) with \(-y\) and checking if we obtain the original equation:- Symmetry about the x-axis: "\(x + (-y)^2 = 4\)" gives \(x + y^2 = 4\), confirming symmetry about the x-axis.- Symmetry about the y-axis: \((-x) + y^2 = 4\) does not give the original equation, showing no symmetry about the y-axis.- Symmetry about the origin: \((-x) + (-y)^2 = 4\) does not return the original equation, so there's no symmetry about the origin.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-intercepts
An x-intercept refers to the point where a graph crosses the x-axis. To find this, we set the y-value of the equation to zero and then solve for the x-value. In the equation \(x + y^2 = 4\), setting \(y = 0\) simplifies it to \(x = 4\). This means the graph touches the x-axis at the point (4, 0).
Understanding x-intercepts is crucial because they reflect the solutions to the equation when the output, or y-value, is zero. Graphically, these intercepts help in sketching the curve accurately by providing a reference point. Students should practice finding x-intercepts in various functions to gain confidence in identifying these points on a graph.
To master the x-intercept concept, remember:
Understanding x-intercepts is crucial because they reflect the solutions to the equation when the output, or y-value, is zero. Graphically, these intercepts help in sketching the curve accurately by providing a reference point. Students should practice finding x-intercepts in various functions to gain confidence in identifying these points on a graph.
To master the x-intercept concept, remember:
- Set \(y = 0\) in the equation.
- Solve for \(x\) to find the x-intercept.
- For the equation given, the x-intercept is at (4, 0).
y-intercepts
The y-intercept is where the graph crosses the y-axis. We determine this by setting x to zero in the equation and solving for y. For \(x + y^2 = 4\), substituting \(x = 0\) gives \(y^2 = 4\). Solving for \(y\) yields \(y = \pm 2\), meaning there are two points: (0, 2) and (0, -2) where the graph intersects the y-axis.
Y-intercepts provide insight into the function's initial value when x is zero, which can also be seen as an entry point into the graph when starting from the x-axis. This property is crucial for sketching graphs accurately, highlighting where a curve might start or end in relation to the axes.
Remember these points for y-intercepts:
Y-intercepts provide insight into the function's initial value when x is zero, which can also be seen as an entry point into the graph when starting from the x-axis. This property is crucial for sketching graphs accurately, highlighting where a curve might start or end in relation to the axes.
Remember these points for y-intercepts:
- Set \(x = 0\) in the equation.
- Solve for \(y\) to find the y-intercept(s).
- In this case, the y-intercepts of the equation are (0, 2) and (0, -2).
graph symmetry
Graph symmetry refers to how a graph may mirror across a line or a point. Testing for symmetry involves substituting variables in different ways and checking if the original equation is obtained.
For the equation \(x + y^2 = 4\):
For the equation \(x + y^2 = 4\):
- **Symmetry about the x-axis:** Replace \(y\) with \(-y\). Since \(x + (-y)^2 = x + y^2 = 4\), the graph is symmetric about the x-axis.
- **Symmetry about the y-axis:** Replace \(x\) with \(-x\). Since this gives \(-x + y^2 = 4\), not equivalent to the original, there's no symmetry about the y-axis.
- **Symmetry about the origin:** Replace \(x\) with \(-x\) and \(y\) with \(-y\). This results in \(-x + (-y)^2 = 4\), again not matching the original, indicating no symmetry about the origin.
parabolas
Parabolas are a unique type of curve formed by quadratic equations. They have a characteristic "U" or inverted "U" shape due to the squared term. The graph of the equation \(x + y^2 = 4\) results in a sideways parabola, not the typical orientation because \(y\) is squared instead of \(x\).
This sideways arrangement means the parabola opens along the x-axis rather than the y-axis. Sketching this involves understanding that:
This sideways arrangement means the parabola opens along the x-axis rather than the y-axis. Sketching this involves understanding that:
- The vertex is the lowest or highest point; here, the vertex is also at the intercept point of (4, 0).
- Because \(x\) changes as \(y\) is incremented or decremented, the parabola stretches horizontally.
- The coefficients and constants in the equation influence the width and orientation.