Chapter 1: Problem 65
Make a table of values and sketch the graph of the equation. Find the x- and y-intercepts and test for symmetry. $$y=x^{2}-9$$
Short Answer
Expert verified
The graph is a parabola with x-intercepts at (3,0) and (-3,0), y-intercept at (0,-9), and is symmetric about the y-axis.
Step by step solution
01
Make a Table of Values
To sketch the graph, we need a set of points. Select a few values for \( x \) and calculate the corresponding \( y \) values using the equation \( y = x^2 - 9 \). For example, for \( x = -3, -2, -1, 0, 1, 2, 3 \), the corresponding \( y \) values are \( 0, -5, -8, -9, -8, -5, 0 \). This gives us the points: \((-3,0), (-2,-5), (-1,-8), (0,-9), (1,-8), (2,-5), (3,0)\).
02
Sketch the Graph
Using the points from the table, plot them on a coordinate grid. Connect the points with a smooth curve. The shape should resemble a parabola opening upwards with its vertex at \( (0,-9) \).
03
Find the x-Intercepts
The x-intercepts occur where \( y = 0 \). From the equation \( y = x^2 - 9 \), set \( y = 0 \) and solve for \( x \): \( x^2 - 9 = 0 \). This simplifies to \( x^2 = 9 \). Solving gives \( x = \pm 3 \). Thus, the x-intercepts are \( (3,0) \) and \( (-3,0) \).
04
Find the y-Intercept
The y-intercept occurs where \( x = 0 \). Substitute \( x = 0 \) in the equation: \( y = 0^2 - 9 = -9 \). Therefore, the y-intercept is \( (0,-9) \).
05
Test for Symmetry
A function is symmetric about the y-axis if \( f(x) = f(-x) \). Substitute \( -x \) into the equation: \( y = (-x)^2 - 9 = x^2 - 9 \). Since the equation remains unchanged, the function is symmetric about the y-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a symmetrical shape that you can easily recognize from its U-like curve. In mathematics, parabolas are represented as the graph of a quadratic function, which is an equation of the form \( y = ax^2 + bx + c \). In the given exercise, the equation is \( y = x^2 - 9 \). This indicates it is a basic quadratic equation with no linear term, meaning the parabola opens upwards.The main parts of a parabola include the vertex, which is the highest or lowest point depending on the parabola's orientation, and the axis of symmetry. For the equation \( y = x^2 - 9 \), the vertex is at the point \((0, -9)\), which is the lowest point in this particular graph. The axis of symmetry runs through the vertex, splitting the parabola into two mirror-image halves.
x-intercepts
The x-intercepts are the points where the graph of a function crosses the x-axis. This occurs where the y-value is zero. For quadratic equations like \( y = x^2 - 9 \), finding the x-intercepts involves solving the equation \( x^2 - 9 = 0 \). You can achieve this by setting \( y \) to zero and solving for \( x \).In this case:
- Step 1: Set \( y = 0 \), giving you the equation \( x^2 = 9 \).
- Step 2: Solve \( x^2 = 9 \) to find \( x = \pm 3 \).
y-intercept
The y-intercept is a specific point where the graph crosses the y-axis. At this point, the x-value is always zero. To find the y-intercept of a quadratic function, simply plug \( x = 0 \) into the equation and solve for \( y \).For the given equation \( y = x^2 - 9 \):
- Substitute \( x = 0 \): \( y = 0^2 - 9 \)
- Thus, \( y = -9 \)
Symmetry of Functions
Functions can show different kinds of symmetry, but one common type is symmetry about the y-axis. A function is symmetric about the y-axis if flipping it over this axis results in the same graph.For a quadratic function like \( y = x^2 - 9 \), you can check for this symmetry by substituting \(-x\) for \(x\) and checking if the function remains unchanged:
- Substitute \(-x\) into the function: \[ y = (-x)^2 - 9 \]
- Since \((-x)^2 = x^2\), the equation simplifies back to \( y = x^2 - 9 \)